The self-inductance of a long solenoid with a turns per unit length is: a. L = μ nA/ l b. L = μ n2 A/ l c. L = μ n2 A l d. L = μ n l/ A

The self-inductance of a long solenoid with a turns per unit length is:
a. L = μ nA/ l b. L = μ n2 A/ l c. L = μ n2 A l d. L = μ n l/ A
by

1 Answer

Answer :

d. L = μ n l/ A
by

Related questions

A solenoid has n turns and length l. If length is reduced to l/2 and turns are doubled then magnetic field B produced by it becomes equal to a) 2B b) 4B c) 1/2 B d) None of these

Description : A solenoid has n turns and length l. If length is reduced to l/2 and turns are doubled then magnetic field B produced by it becomes equal to a) 2B b) 4B c) 1/2 B d) None of these

Last Answer : a) 2B

The inductance of a long solenoid of length 1000 mm wound uniformly with 3000 turns on a cylindrical paper

Description : The inductance of a long solenoid of length 1000 mm wound uniformly with 3000 turns on a cylindrical paper tube of 60 mm diameter is  (A) 3.2 µH (B) 3.2 mH (C) 32.0 mH (D) 3.2 H

Last Answer : The inductance of a long solenoid of length 1000 mm wound uniformly with 3000 turns on a cylindrical paper tube of 60 mm diameter is 32.0 mH

Energy stored per unit volume inside the solenoid is called: a. Energy density b. Charge Density c. Mass density d. Volume charge density

Description : Energy stored per unit volume inside the solenoid is called: a. Energy density b. Charge Density c. Mass density d. Volume charge density

Last Answer : energy density is correct

The Si unit of mutual inductance and self inductance is: a.same b. different c. no unit d. a & b

Description : The Si unit of mutual inductance and self inductance is: a.same b. different c. no unit d. a & b

Last Answer : b. different

Find the turns in an solenoid of inductance 23.4mH , current 2A and area 15cm. a) 900 b) 400 c) 498 d) 658

Description : Find the turns in an solenoid of inductance 23.4mH , current 2A and area 15cm. a) 900 b) 400 c) 498 d) 658

Last Answer : c) 498

The magnetic field at a point on the axis of a long solenoid having 5 turns per cm length when a current of 0.8 A flows through it is

Description : The magnetic field at a point on the axis of a long solenoid having 5 turns per cm length when a current of 0.8 A flows through it is

Last Answer : The magnetic field at a point on the axis of a long solenoid having 5 turns per cm length when a current of 0.8 A ... )` D. `8.024xx10^(-8) Wb//m^(2)`

Due to self-inductance, the coil wires are known as: a. Insulator b. Conductor c. Inductor d. Semi-conductor

Description : Due to self-inductance, the coil wires are known as: a. Insulator b. Conductor c. Inductor d. Semi-conductor

Last Answer : c. Inductor

The phenomenon of producing emf in the coil due to change of current in the coil itself is called: a. mutual induction b. self-induction c. self-inductance d. mutual inductance

Description : The phenomenon of producing emf in the coil due to change of current in the coil itself is called: a. mutual induction b. self-induction c. self-inductance d. mutual inductance

Last Answer : d. mutual inductance

The expression for the inductance in terms of turns, flux and current is given by a) L = N dφ/di b) L = -N dφ/di c) L = Niφ d) L = Nφ/i

Description : The expression for the inductance in terms of turns, flux and current is given by a) L = N dφ/di b) L = -N dφ/di c) L = Niφ d) L = Nφ/i

Last Answer : a) L = N dφ/di

When number of turns in a coil is trippled, without any change in the length of coil, its self inductance becomes? (1) Nine times (2) Three times (3) Six times (4) One-third

Description : When number of turns in a coil is trippled, without any change in the length of coil, its self inductance becomes? (1) Nine times (2) Three times (3) Six times (4) One-third

Last Answer : (1) Nine times

When number of turns in a coil is trippled, without any change in the length of coil, its self inductance becomes? (1) Nine times (2) Three times (3) Six times (4) One–third

Description : When number of turns in a coil is trippled, without any change in the length of coil, its self inductance becomes? (1) Nine times (2) Three times (3) Six times (4) One–third

Last Answer : Nine times

Tesla is a unit of (a) field strength (b) inductance (c) flux density (d) flux

Description : Tesla is a unit of (a) field strength (b) inductance (c) flux density (d) flux

Last Answer : (c) flux density

The unit of inductance is: a. Volt b. Ampere c. Henry d. Ohm

Description : The unit of inductance is: a. Volt b. Ampere c. Henry d. Ohm

Last Answer : c. Henry

The energy density of an inductor is: a. B 2 / 2 μ2 b. B/ 2 μ c. B/ 2 μ2 d. B 2 / 2 μ

Description : The energy density of an inductor is: a. B 2 / 2 μ2 b. B/ 2 μ c. B/ 2 μ2 d. B 2 / 2 μ

Last Answer : c. B/ 2 μ2

Fleming's left hand rule is used to find (a) direction of magnetic field due to current carrying conductor (b) direction of flux in a solenoid (c) direction of force on a current carrying conductor in a magnetic field (d) polarity of a magnetic pole

Description : Fleming's left hand rule is used to find (a) direction of magnetic field due to current carrying conductor (b) direction of flux in a solenoid (c) direction of force on a current carrying conductor in a magnetic field (d) polarity of a magnetic pole

Last Answer : (c) direction of force on a current carrying conductor in a magnetic field

What is a solenoid?*

Description : What is a solenoid?*

Last Answer : Single layered coil.

The magnetic field is _________ inside a solenoid a) Zero b) uniform c) non-uniform d) infinite

Description : The magnetic field is _________ inside a solenoid a) Zero b) uniform c) non-uniform d) infinite

Last Answer : b) uniform

Which of the following does not equal the unit of magnetic flux density? a) 1 Wbm-2 b) 1 NA-1m -1 c) Both (a) and (b) d) 1 Wbm-1

Description : Which of the following does not equal the unit of magnetic flux density? a) 1 Wbm-2 b) 1 NA-1m -1 c) Both (a) and (b) d) 1 Wbm-1

Last Answer : d) 1 Wbm-1

A solenoid has length `0.4cm`, radius 1 cm and 400 turns of wire. If a current fo 5 A is passed through this solenoid, then what is the magnetic field

Description : A solenoid has length `0.4cm`, radius 1 cm and 400 turns of wire. If a current fo 5 A is passed through this solenoid, then what is the magnetic field

Last Answer : A solenoid has length `0.4cm`, radius 1 cm and 400 turns of wire. If a current fo 5 A is passed through this ... `6.28xx10^(-7)T` D. `6.28xx10^(-6)T`

Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A. a) 250 b) 325 c) 175 d) 375

Description : Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A. a) 250 b) 325 c) 175 d) 375

Last Answer : d) 375

The quantized Bohr orbit radius of electron in hydrogen atom is given by a) n2 r3 b) nr1 c) n2 r2 d) n2 r1

Description : The quantized Bohr orbit radius of electron in hydrogen atom is given by a) n2 r3 b) nr1 c) n2 r2 d) n2 r1

Last Answer : d) n2 r1

The region where the Lyman series contains the wavelength 1∕ λ = RH [1/ 12 – 1/ n2 ] is a) visible region b) infrared region c) ultraviolet region d ) none of these

Description : The region where the Lyman series contains the wavelength 1∕ λ = RH [1/ 12 – 1/ n2 ] is a) visible region b) infrared region c) ultraviolet region d ) none of these

Last Answer : c) ultraviolet region

. In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Description : . In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Last Answer : A Fn =N √(R/L)

In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A) Fn =N √(R/L) B) Fn =1/N √(R/L) C) Fn =N/2 √(R/L) D) Fn =N2 √(R/L)

Description : In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A) Fn =N √(R/L) B) Fn =1/N √(R/L) C) Fn =N/2 √(R/L) D) Fn =N2 √(R/L)

Last Answer : A) Fn =N √(R/L)

A coil of 500 turns is linked with a flux of 25 mwb, when carries a current of 12.5A. Calculate the value of self-inductance.

Description : A coil of 500 turns is linked with a flux of 25 mwb, when carries a current of 12.5A. Calculate the value of self-inductance.

Last Answer : Ans: Self-Inductance: L = NΦ /I = 500 × 25 × 10-3 / 12.5 = 1 H

Mutual Inductance What?

Last Answer : that Features Or Of religion Due As well as Two Coil Of one Of current Of change As a result In the other Voltage Obsessed Is That said Religion Or Features Mutual Inductions Says.

.A(75-j50)-is connectedtoa coaxialtransmission lineofZO=75 ,at 10GHz.The bestmethod ofmatching consistsin connecting a. a short-circuited stub at the load b. an inductance at the load c. a capacitance at some specific distance d. a short-circuited stub at some specific distance from the load

Description : .A(75-j50)-is connectedtoa coaxialtransmission lineofZO=75 ,at 10GHz.The bestmethod ofmatching consistsin connecting a. a short-circuited stub at the load b. an inductance at the load c. a capacitance at some specific distance d. a short-circuited stub at some specific distance from the load

Last Answer : d. a short-circuited stub at some specific distance from the load

The mutual inductance of the coil depends upon: a. density of the coil b. stiffness of coil c. material of coil d. geometry of the coil

Description : The mutual inductance of the coil depends upon: a. density of the coil b. stiffness of coil c. material of coil d. geometry of the coil

Last Answer : d. geometry of the coil

A conductor of length L has current I passing through it, when it is placed parallel to a magnetic field. The force experienced by the conductor will be (a) zero (b) BLI (c) B2LI (d) BLI2

Description : A conductor of length L has current I passing through it, when it is placed parallel to a magnetic field. The force experienced by the conductor will be (a) zero (b) BLI (c) B2LI (d) BLI2

Last Answer : (a) zero

A wire of uniform area of cross-section A length L and resistance R is cut into two parts. Resistivity of each part a. remains the same b. is doubled c. is halved d. becomes zero

Description : A wire of uniform area of cross-section A length L and resistance R is cut into two parts. Resistivity of each part a. remains the same b. is doubled c. is halved d. becomes zero

Last Answer : a. remains the same

Find the inductance of a coil with permeability 3.5, turns 100 and length 2m. Assume the area to be thrice the length. a) 131.94mH b) 94.131mH c) 131.94H d) 94.131H

Description : Find the inductance of a coil with permeability 3.5, turns 100 and length 2m. Assume the area to be thrice the length. a) 131.94mH b) 94.131mH c) 131.94H d) 94.131H

Last Answer : a) 131.94mH

lt the length, number of turns and area of a coil are doubled, the inductance of the coil

Description : lt the length, number of turns and area of a coil are  doubled, the inductance of the coil

Last Answer : lt the length, number of turns and area of a coil are  doubled, the inductance of the coil is quadrupled

One tesla equals a) 1 NA-1m -1 b) 1 NA-2m -3 c) 1NAm-1 d) 1NA-1 m

Description : One tesla equals a) 1 NA-1m -1 b) 1 NA-2m -3 c) 1NAm-1 d) 1NA-1 m

Last Answer : a) 1 NA-1m -1

Which of the following characteristics is most critical in determining the size of the cable to be used in a particular circuit? A. voltage rating B. weight per unit length C. current rating D. inductance per unit length

Description : Which of the following characteristics is most critical in determining the size of the cable to be used in a particular circuit? A. voltage rating B. weight per unit length C. current rating D. inductance per unit length

Last Answer : Answer: C

5) An iron ring of mean circumference of 80 cm is uniformly wound with 500 turns of wire. Calculate the value of flux density that a current of 1 A would produce in the ring. Assume relative permeability 1400.

Description : Please ripley me due to emergency

Last Answer : To calculate the flux density in the ring, you need to use the following formula: B = (μ * I * N) / (2 * π * r) where: B is the flux density in the ring (in teslas) μ is the relative permeability ... 2 * π * 0.127 m) = 0.53 T So the flux density in the ring would be approximately 0.53 teslas.

A transformer steps down 220V to 40 volts. If the secondary turns are 40 then primary turns will be: a. 20 b. 40 c. 120 d. 220

Description : A transformer steps down 220V to 40 volts. If the secondary turns are 40 then primary turns will be: a. 20 b. 40 c. 120 d. 220

Last Answer : d. 220V

If μ = absolute viscosity, N= speed of the journal and p = unit bearing pressure, then the bearing characteristic number is given by (A) μN/p (B) μp/N (C) pN/μ (D) μ/pN

Description : If μ = absolute viscosity, N= speed of the journal and p = unit bearing pressure, then the bearing characteristic number is given by (A) μN/p (B) μp/N (C) pN/μ (D) μ/pN

Last Answer : (A) μN/p

S.I unit of strain is a) Newton b) N m–2 c) Pascal d) no unit

Description : S.I unit of strain is a) Newton b) N m–2 c) Pascal d) no unit

Last Answer : a) Newton

S.I unit of stress is: a) N/m b) N m c) Nm–2 d) Newton

Description : S.I unit of stress is: a) N/m b) N m c) Nm–2 d) Newton

Last Answer : c) Nm–2

The force per unit charge is called: (a) Electric field (b) Electric field intensity (c) Electric potential energy (d) Electric potential

Description : The force per unit charge is called: (a) Electric field (b) Electric field intensity (c) Electric potential energy (d) Electric potential

Last Answer : b) Electric field intensity

The circuit shows a resistance, `R=0.01Omega` and inductance L=3mH connected toa conducting rod PQ of length l=wm which can slide on a perfectly condu

Description : The circuit shows a resistance, `R=0.01Omega` and inductance L=3mH connected toa conducting rod PQ of length l=wm which can slide on a perfectly condu

Last Answer : The circuit shows a resistance, `R=0.01Omega` and inductance L=3mH connected toa conducting rod PQ of length l= ... (inN-m) at t=(0.3In 2) second.

The circuit shows a resistance, `R=0.01Omega` and inductance L=3mH connected to a conducting rod PQ of length l=wm which can slide on a perfectly cond

Description : The circuit shows a resistance, `R=0.01Omega` and inductance L=3mH connected to a conducting rod PQ of length l=wm which can slide on a perfectly cond

Last Answer : The circuit shows a resistance, `R=0.01Omega` and inductance L=3mH connected to a conducting rod PQ of length ... (inN-m) at t=(0.3In 2) second.

If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Last Answer : B. 80 L

Dimension of Rydberg constant is a) LT-1 b) L-1 c) (LT)-1 d) L-1T

Description : Dimension of Rydberg constant is a) LT-1 b) L-1 c) (LT)-1 d) L-1T

Last Answer : b) L-1

The dimension of strain is a) [L] b) [ML2T –2 ] c) [M L–1 T –2 ] d) Dimensionless

Description : The dimension of strain is a) [L] b) [ML2T –2 ] c) [M L–1 T –2 ] d) Dimensionless

Last Answer : d) Dimensionless

The negative sign in expression ɛ= -vBL shows that the angle between the direction of L and (v x B) is: a. 90 b. 180 c. 45 d. 0

Description : The negative sign in expression ɛ= -vBL shows that the angle between the direction of L and (v x B) is: a. 90 b. 180 c. 45 d. 0

Last Answer : a. 90

The traveling salesman problem involves n cities with paths connecting the cities. The time taken for traversing through all the cities, without knowing in advance the length of a minimum tour, is ___________ a) O(n) b) O(n2) c) O(n!) d) O(n/2)

Description : The traveling salesman problem involves n cities with paths connecting the cities. The time taken for traversing through all the cities, without knowing in advance the length of a minimum tour, is ___________ a) O(n) b) O(n2) c) O(n!) d) O(n/2)

Last Answer : c) O(n!)

A current of 5.8 A flows through a 0.25 m long straight conductor which is kept perpendicular in a region of uniform magnetic field of 3.7 T . The force on conductor is a) 5.4 N b) 2.4 N c) 3.4 N d) 6.4 N

Description : A current of 5.8 A flows through a 0.25 m long straight conductor which is kept perpendicular in a region of uniform magnetic field of 3.7 T . The force on conductor is a) 5.4 N b) 2.4 N c) 3.4 N d) 6.4 N

Last Answer : a) 5.4 N

The left hand rule correlates to (a) current, induced e.m.f. and direction of force on a conductor (b) magnetic field, electric field and direction of force on a conductor (c) self induction, mutual induction and direction of force on a conductor (d) current, magnetic field and direction of force on a conductor

Description : The left hand rule correlates to (a) current, induced e.m.f. and direction of force on a conductor (b) magnetic field, electric field and direction of force on a conductor (c) self induction, ... and direction of force on a conductor (d) current, magnetic field and direction of force on a conductor

Last Answer : (d) current, magnetic field and direction of force on a conductor

What is a self-monitoring alarm circuit?

Description : What is a self-monitoring alarm circuit?

Last Answer : It self monitors the health of the alarm circuit. That is, it senses whether the power supply to the alarm circuit is healthy and all the relays and contacts are functioning normally. Check with E/O for more details.