5) An iron ring of mean circumference of 80 cm is uniformly wound with 500 turns of wire. Calculate the value of flux density that a current of 1 A would produce in the ring. Assume relative permeability 1400.

Question

Please ripley me due to emergency

Answer 1

To calculate the flux density in the ring, you need to use the following formula:

B = (μ * I * N) / (2 * π * r)

where:

B is the flux density in the ring (in teslas)

μ is the relative permeability of the iron (1400 in this case)

I is the current in the wire (1 A in this case)

N is the number of turns of wire (500 in this case)

r is the radius of the iron ring (in meters)

First, you need to find the radius of the ring. You can do this by dividing the mean circumference by 2π:

r = 80 cm / (2 * π)

= 12.7 cm

Then, you can use the formula above to calculate the flux density:

B = (1400 * 1 A * 500 turns) / (2 * π * 0.127 m)

= 0.53 T

So the flux density in the ring would be approximately 0.53 teslas.