Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

1 Answer

Answer :

Answer- 3( 19,20,21)

Explanation:- let number be x,x+1,x+2

2x + 3(x+1)+4(x+2)=180

x=19

so numbers are 19,20,21

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