Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Helium ( R= 0.4698 BTU/lbm-˚R ) is
compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4.
Calculate the work done by the gas.
 A. –1454 BTU/lbm
 B. -364 BTU/lbm
 C.-187BTU/lbm
 D.46.7 BTU/lbm
Formula: W = RT ln (V2/V1)
by

1 Answer

Answer :

-364 BTU/lbm
by

Related questions

3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

Description : Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

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Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

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What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

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Last Answer : W = mRTln (V2/V1)

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A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C. 2.54 kg  D. 3.16 kg Formula: from the steam table at 600kPa vƒ = 0.001101 m^3 / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Description : A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C ... / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Last Answer : 3.16 kg

A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 x10^6 kJ  D. 2 x10^6 kJ Formula: fromthe steamtable vƒ = 0.001043 m^3 / kg vg = 1.6940 m^3 / kg u ƒ= 417.3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Description : A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 ... 3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Last Answer : 2 x10^6 kJ

An ideal gas is compressed in a cylinder so well insulated that there is essentially no heat transfer. The temperature of gas  a. Remains constant  b. increases  c. decreases  d. is basically zero

Description : An ideal gas is compressed in a cylinder so well insulated that there is essentially no heat transfer. The temperature of gas  a. Remains constant  b. increases  c. decreases  d. is basically zero

Last Answer : increases

If the initial volume of an ideal gas is compressed to one-half its original volume and to twice its original temperature, the pressure:  a. doubles  b. halves  c. quadruples  d. triples

Description : If the initial volume of an ideal gas is compressed to one-half its original volume and to twice its original temperature, the pressure:  a. doubles  b. halves  c. quadruples  d. triples

Last Answer : quadruples

The volume of the gas held at constant pressure increases 4 cm² at 0°C to 5cm². What is the final pressure?  a. 68.65ºC  b. 68.25ºC  c. 70.01°C  d. 79.1ºC t2= T2–T1

Description : The volume of the gas held at constant pressure increases 4 cm² at 0°C to 5cm². What is the final pressure?  a. 68.65ºC  b. 68.25ºC  c. 70.01°C  d. 79.1ºC t2= T2–T1

Last Answer : 981 N

The mechanical equivalent of heat is  a. joule  b. calorie  c. Btu  d. Specific heat

Description : The mechanical equivalent of heat is  a. joule  b. calorie  c. Btu  d. Specific heat

Last Answer : joule

What is defined as the quantity of heat needed to raise the temperature of one kilogram of water by one degrees Celsius?  a. Kilojoule  b. Btu  c. Kilocalorie  d. Latent heat

Description : What is defined as the quantity of heat needed to raise the temperature of one kilogram of water by one degrees Celsius?  a. Kilojoule  b. Btu  c. Kilocalorie  d. Latent heat

Last Answer : Kilocalorie

1 British thermal unit (BTU) is equivalent to how many joules?  A. 1016  B. 1043  C. 1023  D. 1054

Description : 1 British thermal unit (BTU) is equivalent to how many joules?  A. 1016  B. 1043  C. 1023  D. 1054

Last Answer : 1054

The amount of heat required to raise the temperature of 1 pound of water by 1°F is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Description : The amount of heat required to raise the temperature of 1 pound of water by 1°F is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Last Answer : BTU

The amount of heat required to raise the temperature of 1kg of water through 1 °C is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Description : The amount of heat required to raise the temperature of 1kg of water through 1 °C is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Last Answer : Kilocalorie