An overhead transmission line has a span of 260 m. The weight of the conductor is 0.68 kg/m. The maximum allowable tension in the line is 1550 kg. Maximum sag of the line should be (a) 5.8 m (b) 4.6 m (c) 2.7 m (d) 3.7 m 

1 Answer

Answer :

Maximum sag = (l^2)/8c
So c = T/W
c = 1550/0.68
c= 2279.4
Now Maximum sag = (260^2)/8(2279.4)
= 3.7 (d)

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