In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be
(A) ΔQ = 0, ΔS=0
(B) ΔQ = 0, ΔS = +ve
(C) ΔQ = 0, ΔS = -ve
(D) ΔQ = +ve, ΔS= +ve

1 Answer

Answer :

(B) ΔQ = 0, ΔS = +ve

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