If a Company require 60 hosts then What is
the best possible subnet mask?
a. 255.255.255.0
b. 255.255.255.192
c. 255.255.225.224
d. 225.225.255.240

1 Answer

Answer :

b. 255.255.255.192

Related questions

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Description : With anIP address set starting with 150, you currently havesix offices that you are treating as subnets. Plans are in place toopen 10 more officesbefore the end of theyear. What subnet mask should you useto ... maximize thenumberof hosts available at eachsite? A. 192 B. 224 C. 240 D. 248 E. 252

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Description : With anIP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts? A. 192 B. 224 C. 240 D. 248 E. 252

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Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

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Description : You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. ... B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255

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Description : You are designing a network which needs to support 200 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs? Select the best answer. A. 255.255.0.0 B. 255.255.255.0 C. 255.0.0.0 D. 255.224.0.0 E. 255.255.255.200

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Description : What is IP class and number of sub- networks if the subnet mask is 255.224.0.0? a. Class A, 3 b. Class A, 8 c. Class B, 3 d. Class B, 32

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Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Last Answer : Correct answer: A 255.255.255.224,

Description : You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, ... 0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Last Answer : Correct answer: A,B & D Subnet addresses in this situation are all in multiples of 8. In this example, 201.222.5.16 is the subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on subnet 201.222.5.16.

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Description : Which one is nota contiguous mask? A) 255.255.255.254 B) 255.255.224.0 C) 255.148.0.0 D) all are

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Description : Which of the following best illustrates the default subnet mask for a class A,B, and C Network? A. 0.0.0.0,0.0.0.1, 0.0.1.1 B. 255.255.255.0, 255.255.0.0,255.0.0.0 C. 255.0.0.0, 255.255.0.0, 255.255.255.0 D. 255.255.0.0, 255.255.255.0,255.255.255.255 E. None of the above

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Description : What partof 192.168.10.51 is the Network ID, assuming a default subnet mask? A. 192 B. 192.168.10 C. 0.0.0.5 D. 51 E. None of the above

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