Description : With anIP address set starting with 150, you currently havesix offices that you are treating as subnets. Plans are in place toopen 10 more officesbefore the end of theyear. What subnet mask should you useto ... maximize thenumberof hosts available at eachsite? A. 192 B. 224 C. 240 D. 248 E. 252
Last Answer : 248
Description : You are working with a network thathas the network ID 192.168.10.0. What subnet should you use that supportsup to 25 hosts and a maximum number of subnets? A. 255.255.255.192 B. 255.255.255.224 C. 255.255.255.240 D. 255.255.255.248 E. 255.255.255.252
Last Answer : 255.255.255.224
Description : You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. ... B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255
Last Answer : 255.254.0.0
Description : If a Company require 60 hosts then What is the best possible subnet mask? a. 255.255.255.0 b. 255.255.255.192 c. 255.255.225.224 d. 225.225.255.240
Last Answer : b. 255.255.255.192
Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240
Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248
Description : You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and192.168.7.0. What subnet mask can you use to combine these addresses intoone? A. 255.255.252.0 B. 225.255.254.0 C. 255.255.255.240 D. 255.255.255.252
Last Answer : 255.255.252.0
Description : You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12 ... , B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15
Last Answer : Correct answer: A * 255.255.255.248,
Description : A subnet has been assigned a subnet mask of 255.255.255.192. What is the maximum number of hosts that can belong to this subnet? a. 14 b. 30 c. 62 d. 126
Last Answer : c. 62
Description : You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, ... 0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255
Last Answer : Correct answer: A,B & D Subnet addresses in this situation are all in multiples of 8. In this example, 201.222.5.16 is the subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on subnet 201.222.5.16.
Description : The address of a class B host is to be split into subnets with a 6-bit subnet number. What is the maximum number of subnets and the maximum number of hosts in each subnet? a. 62 subnets and 262142 hosts. b. 64 subnets and 262142 hosts. c. 62 subnets and 1022 hosts. d. 64 subnets and 1024 hosts
Last Answer : c. 62 subnets and 1022 hosts.
Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248.
Description : You are designing a network which needs to support 200 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs? Select the best answer. A. 255.255.0.0 B. 255.255.255.0 C. 255.0.0.0 D. 255.224.0.0 E. 255.255.255.200
Last Answer : 255.255.255.0
Description : What is IP class and number of sub- networks if the subnet mask is 255.224.0.0? a. Class A, 3 b. Class A, 8 c. Class B, 3 d. Class B, 32
Last Answer : b. Class A, 8
Description : A network on the Internet has a subnet mask of 255.255.240.0. What is the maximum number of hosts it can handle ? (A) 1024 (B) 2048 (C) 4096 (D) 8192
Last Answer : (C) 4096
Description : On a class B network, how manyhostsare availableat eachsite witha subnet mask of 248? A. 16,382 B. 8,190 C. 4,094 D. 2,046 E. 1,022
Last Answer : 2,046
Description : Given the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many hosts are available? * 254 * 510 * 126 * 16,372
Last Answer : 254
Description : What partof 192.168.10.51 is the Network ID, assuming a default subnet mask? A. 192 B. 192.168.10 C. 0.0.0.5 D. 51 E. None of the above
Last Answer : 192.168.10
Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127
Last Answer : Correct answer: A 255.255.255.224,
Description : You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122
Last Answer : Correct answer: A The easiest way to calculate this is to subtract 255.255.255.248 (subnet mask) from 255.255.255.255, this equals 7. Convert the address 201.222.5.121 to binary- ... mask 255.255.255.248 to binary-11111111 11111111 11111111 11111000. AND them together to get: 11001001 1101111
Description : ........ implies that all subnets obtained from the same network use the subnet mask. A) Static subnetting B) Dynamic Subnetting C) Variable length subnetting D) Both B and C
Last Answer : A) Static subnetting
Description : ............ implies that all subnets obtained from the same network use the subnet mask. A) Static subnetting B) Dynamic Subnetting C) Variable length subnetting D) Both B and C
Description : ………………….. implies that all subnets obtained from the same subnet mask. A) Static subnetting B) Dynamic subnetting C) Variable length subnetting D) Both B and C
Description : Consider the given network implementation scenario. For the given classful NID 199.10.20.0/24, the requirement is to create 13 subnets. With given details, find the range of first and last valid IP in 15th subnet. a. ... .20.225 to 199.10.20.238 c. 199.10.20.193 to 199.10.20.206 d. Not of these
Last Answer : a. A Only
Description : There are two types of designs for communication subnets: they are ………… A. Point-to-Point channels and Broadcast channels B. packet-switched subnet and store-and-forward C. Multicasting and Broadcasting D. Point-to-Point channels and store-and-forward
Last Answer : A. Point-to-Point channels and Broadcast channels
Description : Which IP Address Class can have 16 million subnets but support 254 hosts? * Class C * Class A * Class B * Class D
Last Answer : Correct answer: A Possible Subnets IP Address Class Possible Hosts
Description : Which IP Address Class is INCORRECTLY paired with its range of network numbers? * Class A addresses include 192.0.0.0 through 223.255.255.0 * Class A addresses include 1.0.0.0 through 126.0.0.0 * Class B ... 192.0.0.0 through 223.255.255.0 * Class D addresses include 224.0.0.0 through 239.255.255.0
Last Answer : 1
Description : Which one is nota contiguous mask? A) 255.255.255.254 B) 255.255.224.0 C) 255.148.0.0 D) all are
Last Answer : 255.148.0.0
Description : Which of the following best illustrates the default subnet mask for a class A,B, and C Network? A. 0.0.0.0,0.0.0.1, 0.0.1.1 B. 255.255.255.0, 255.255.0.0,255.0.0.0 C. 255.0.0.0, 255.255.0.0, 255.255.255.0 D. 255.255.0.0, 255.255.255.0,255.255.255.255 E. None of the above
Last Answer : 255.0.0.0, 255.255.0.0, 255.255.255.0
Description : What is the default subnet mask for a class C network? A. 127.0.0.1 B. 255.0.0.0 C. 255.255.0.0 D. 255.255.255.0 E. None of the above
Description : Two taps M and N can alone fill a tank in 80 minutes and 120 minutes respectively. But due to a leakage of tank, it took 12 more minutes to fill the tank. In how many hours, the leak can alone empty the full tank? A) 240 B) 230 C) 248 D) 256
Last Answer : A A and B can fill tank in (1/80 + 1/120) = 1/48 so 48minutes But it took 12 more minutes, this means the tank got full in 48+12= 60 minutes So (1/80 + 1/120 – 1/x) = 1/60 1/X=1/80+1/120-1/60 Solve, x = 240
Description : In a block, the mask is 255.255.192.0; what is the prefix length? A) /20 B) /28 C) /18 D) none of the above
Last Answer : /18
Description : 256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176
Last Answer : The series is ×0.5, ÷1, ×1.5, ÷2, ×2.5.... Answer: d)
Description : Which among the following definitions is correct: a) Address - The unique number ID assigned to one host or interface in a network b) Subnet - A portion of a network sharing a particular subnet address c) ... to the host d) Interface - A network connection e) None of These f) All of the Above
Last Answer : f) All of the Above
Description : 2 male, 6 female, and 8 girls can do a work in 192 hrs, 4 male and 16 girls can do it in 160 hrs, 4 male and 6 female can do it in 240 hrs.10 male and 24 girls can do it in. a) A.87 3/ 11 hrs b) B.78 4 /11 hrs c) C.88 6 /12 hrs d) 80 4 /5 hrs
Last Answer : A Let 1 males 1 hr work = x 1 female 1 hour work = y 1 girl 1 hour work = z Then 2x + 6y + 8z = 1/192 ------>1 4x + 16z = 1/160 --------->2 4x + 6y = 1/240 ------------->3 Adding 2 and ... 1/192 + 1/160 =(5+6) / 960 = 11/960 10 male and 24 girls can do work in 960/11 hrs i.e., 87 3 /11 hrs
Description : 188, 212, 236, ?, 268, 284 a) 260 b) 256 c) 252 d) 248 e) 244
Last Answer : The pattern is 47×4=188, 53×4=212, 59×4=236, 61×4=244, 67×4=268, 71×4=284 47, 53, 59, 61, 69 and 71 are consecutive prime numbers. Answer: e)
Description : An organization isgranteda block;one address is2.2.2.64/20. The organization needs 10 subnets. What is thesubnet prefix length? A) /20 B) /24 C) /25 D) none of the above
Last Answer : /24
Description : An organization is granted the block 130.34.12.64/26. It needs to have 4 subnets. Which of the following is not an address of this organization? a. 130.34.12.124 b. 130.34.12.89 c. 130.34.12.70 d. 130.34.12.132
Last Answer : d. 130.34.12.132
Description : The combination of an IP address and a port number is known as ................... (A) network number (B) socket address (C) subnet mask number (D) MAC address
Last Answer : (B) socket address
Description : A gas engine has a volume of 300 cc and clearance volume of 25 cc. Its volumetric efficiency is 0.8 and mech efficiency is 0.9. What is the volume of the mixture taken in per stroke? (a) 248 cc (b) 252 cc (c) 264 cc (d) 286 cc
Last Answer : Ans : c
Description : Why is the subnet mask important in determining the network address?
Last Answer : What is the answer ?
Description : You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000
Last Answer : Correct answer: A To find the network address, convert the IP address to binary-10101100 000100000 00000010 10100000-then ANDed it with the subnet mask-11111111 11111111 00000000 00000000. The rest is ... that the class of an address can be determined by the numerical value of the first octet
Description : When configuring the subnet mask for an IP address, which formats can be used? * dotted-decimal. * Hexadecimal * Bit-count * Octal * Binary
Last Answer : Correct answer: A, B &C
Description : One tube can fill a tank five times as fast as another tube. If together the two tubes can fill tank in 42 min, then the slower tube alone will be able to fill the tank in? A) 252 min B) 208 min C) 244 min D) 192 min
Last Answer : A Let the slower tube alone fill the tank in x min. Then, faster tube will fill it in x/5 min. 1/x + 5/x = 1/42 6/x = 1/42 => x = 252min.
Description : The torque on a conductor with flux density 23 units, current 1.6A and area 6.75 units will be a) 248.4 b) 192.6 c) 175.4 d) 256.9
Last Answer : a) 248.4
Description : Which addresses are INCORRECTLY paired with their class? * 240 - 255, Class D * 240 - 255, Class E * 224 - 239, Class D
Last Answer : Correct answer: A & D Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and 240 to 255, Class E.
Description : Which of the following statement is true? I. An address with all bits 1 is interpreted as all networks or all hosts. II. The class A network 128.0.0.0 is defined as the loopback network. a. i only b. ii only c. Both A and B d. None of the above
Last Answer : a. i only
Description : Find out the components of DHCP: 1) A protocol that delivers host-specific configuration parameters from a server to a host. 2) The client determines its own hardware address; this is normally in a ROM on the hardware. 3) ... or permanent network addresses to hosts. A. 1,2 B. 1,3 C. 2,3 D. 1,2,3
Last Answer : B. 1,3
Description : 5 6 16 57 ? 1245 7506 a) 240 b) 248 c) 244 d) 250 e) 260
Last Answer : Answer: b)
Description : .If you are currently producing 100,000 units at an automation level of 5, how much would it cost to maximize automation? a. $500,000 b. $50,000 c. $2,000,000 d. $5,000,000 e. none of the above
Last Answer : c. $2,000,000