Reichert-Meissl number: (A) 0.1 N KOH (B) 0.5 KOH (C) 0.1 N NaOH (D) 0.5 NaOH

Reichert-Meissl number: (A) 0.1 N KOH (B) 0.5 KOH (C) 0.1 N NaOH (D) 0.5 NaOH
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Number of ml of 0.1 N KOH required to neutralize fatty acids from 5 gms of fat: (A) Iodine number (B) Polenske number (C) Reichert-Miessl number (D) None of these

Description : Number of ml of 0.1 N KOH required to neutralize fatty acids from 5 gms of fat: (A) Iodine number (B) Polenske number (C) Reichert-Miessl number (D) None of these

Last Answer : Answer : B

Which of the following test is used for distinguishing among dry oils, semi-drying oils and non drying oils? (A) Elaiden test (B) Reichert-Meissl value test (C) Hunter value test (D) Iodine value test

Description : Which of the following test is used for distinguishing among dry oils, semi-drying oils and non drying oils? (A) Elaiden test (B) Reichert-Meissl value test (C) Hunter value test (D) Iodine value test

Last Answer : Option A

The number of ml of N/10 KOH required to neutralize the fatty acids in the distillate from 5 gm of fat is called (A) Reichert-Meissel number (B) Polenske number (C) Acetyl number (D) Non volatile fatty acid number

Description : The number of ml of N/10 KOH required to neutralize the fatty acids in the distillate from 5 gm of fat is called (A) Reichert-Meissel number (B) Polenske number (C) Acetyl number (D) Non volatile fatty acid number

Last Answer : Answer : A

In the given reaction sequence `C_(6)H_(5)-CH_(2)-NH_(2) overset(CHCl_(3)//Alc.KOH)underset(Delta)rarr [X] overset(H_(2)O //NaOH)rarr [Y],[Y]` will be

Description : In the given reaction sequence `C_(6)H_(5)-CH_(2)-NH_(2) overset(CHCl_(3)//Alc.KOH)underset(Delta)rarr [X] overset(H_(2)O //NaOH)rarr [Y],[Y]` will be

Last Answer : In the given reaction sequence `C_(6)H_(5)-CH_(2)-NH_(2) overset(CHCl_(3)//Alc.KOH)underset(Delta)rarr [X] ... -NH_(2)` D. `C_(6)H_(5)-CH_(2)OH`

The reaction of oil/fat with NaOH/KOH as

Description : The reaction of oil/fat with NaOH/KOH as

Last Answer : Ans. Saponification

Even though NaOH & KOH contains –OH group. It is not included in the group of organic substances. Why?

Description : Even though NaOH & KOH contains –OH group. It is not included in the group of organic substances. Why?

Last Answer : NaOH and KOH are strong bases which are ionic compound that contain OH ions. Alcohols are covalent compounds, even though they have on or more hydroxyl ( -OH ) functional group, they do not behave like bases. The – OH group attached to a carbon atom is a covalent bond.

Which among the following is not a base? (a) NaOH (b) KOH ( c) NH4OH (d)C2H5 OH

Description : Which among the following is not a base? (a) NaOH (b) KOH ( c) NH4OH (d)C2H5 OH

Last Answer : (d)C2H5 OH

Which of the following reagents is used to prepare benzenediazoniumchloride from aniline?(a) NaNO2 + HCl(b) LiAlH4(c) NH2NH2 + KOH(d) NaOH

Description : Which of the following reagents is used to prepare benzenediazonium chloride from aniline? (a) NaNO2 + HCl (b) LiAlH4 (c) NH2NH2 + KOH (d) NaOH

Last Answer : NaNO2 + HCl

A primary amine can be identified by using (a) HCl (b) CHCl3 (c) NaOH (d) CHCl3 + KOH

Description : A primary amine can be identified by using (a) HCl (b) CHCl3 (c) NaOH (d) CHCl3 + KOH

Last Answer : CHCl3 + KOH

The electrolytic solution used in a hydrogen-oxygen fuel cell is ____________ a) 75% KOH solution b) 25% KOH solution c) 75% NaOH solution d) 25% NaOH solution

Description : The electrolytic solution used in a hydrogen-oxygen fuel cell is ____________ a) 75% KOH solution b) 25% KOH solution c) 75% NaOH solution d) 25% NaOH solution

Last Answer : b) 25% KOH solution

Which reagent is used for conversion of benzaldehyde into toluene? a. KMnO4/NaOH b. NH2NH2/KOH c. HIO4 d. V2O5

Description : Which reagent is used for conversion of benzaldehyde into toluene? a. KMnO4/NaOH b. NH2NH2/KOH c. HIO4 d. V2O5

Last Answer : b. NH2NH2/KOH

The number of milliliters of 0.1 N KOH required to neutralize the insoluble fatty acids from 5 gms of fat is called (A) Acid number (B) Acetyl number (C) Halogenation (D) Polenske number

Description : The number of milliliters of 0.1 N KOH required to neutralize the insoluble fatty acids from 5 gms of fat is called (A) Acid number (B) Acetyl number (C) Halogenation (D) Polenske number

Last Answer : Answer : D

The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is:

Description : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is:

Last Answer : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is: A. 1.65 kg B. 1.4 kg C. 16.5 kg D. 140 kg

Isopropyl bromide reacts with alcoholic KOH to give (a) Propene (b) Isopropyl alcohol (c) Propane (d) n-Propyl alcohol

Description : Isopropyl bromide reacts with alcoholic KOH to give (a) Propene (b) Isopropyl alcohol (c) Propane (d) n-Propyl alcohol

Last Answer : Propene

Saponification number is (A) mg of KOH required to saponify one gm of fat or oil (B) mg of KOH required to neutralize free fatty acids of one gms of fat (C) mg of KOH required to neutralize the acetic acid obtained by saponification of one gm of fat after it has been acetylated (D) None of these

Description : Saponification number is (A) mg of KOH required to saponify one gm of fat or oil (B) mg of KOH required to neutralize free fatty acids of one gms of fat (C) mg of KOH required to neutralize the acetic acid obtained by saponification of one gm of fat after it has been acetylated (D) None of these

Last Answer : Answer : C

A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`

The end product (B) of the reaction sequence: `C_(2)H_(5)-underset(H)underset(|)(N)-CH_(3) overset(Ph-overset(O)overset(||)(C)-Cl)underset(NaOH)rarrA

Description : The end product (B) of the reaction sequence: `C_(2)H_(5)-underset(H)underset(|)(N)-CH_(3) overset(Ph-overset(O)overset(||)(C)-Cl)underset(NaOH)rarrA

Last Answer : The end product (B) of the reaction sequence: `C_(2)H_(5)-underset(H)underset(|)(N)-CH_(3) overset(Ph-overset ... )underset(H_(2)O)rarr B` A. B. C. D.

Compound `[X] C_(4)H_(11)N` reacts with p-toluence sulphonyl chloride in aqueous `NaOH` to give a solid. The compound [X] is:

Description : Compound `[X] C_(4)H_(11)N` reacts with p-toluence sulphonyl chloride in aqueous `NaOH` to give a solid. The compound [X] is:

Last Answer : Compound `[X] C_(4)H_(11)N` reacts with p-toluence sulphonyl chloride in aqueous `NaOH` to give a solid. ... 2)-underset(CH_(3))underset(|)(N)-CH_(3)`

HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Description : HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Last Answer : Dissolve 6 g dry sodium hydroxide in 200 mL water.

If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution what is the molarity of the new solution?

Description : If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution what is the molarity of the new solution?

Last Answer : If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution,what is the molarity of the new solution?

Alkaloids are usually purified by extraction with (A) Ether (B) Dil HCl (C) NaOH (D) Chloroform

Description : Alkaloids are usually purified by extraction with (A) Ether (B) Dil HCl (C) NaOH (D) Chloroform

Last Answer : Answer : B

The acid D obtained through the following sequence of reactions is: `C_(2)H_(5)Br overset(Alc. KOH)rarrA overset(Br_(2))underset(C Cl_(4))rarrBoverset

Description : The acid D obtained through the following sequence of reactions is: `C_(2)H_(5)Br overset(Alc. KOH)rarrA overset(Br_(2))underset(C Cl_(4))rarrBoverset

Last Answer : The acid D obtained through the following sequence of reactions is: `C_(2)H_(5)Br overset(Alc. KOH) ... B. Malonic acid C. Maleic acid D. Oxalic acid

The acid D obtained through the following sequence of reactions is: `C_(2)H_(5)Br overset(Alc. KOH)rarrA overset(Br_(2))underset(C Cl_(4))rarrBoverset

Description : The acid D obtained through the following sequence of reactions is: `C_(2)H_(5)Br overset(Alc. KOH)rarrA overset(Br_(2))underset(C Cl_(4))rarrBoverset

Last Answer : The acid D obtained through the following sequence of reactions is: `C_(2)H_(5)Br overset(Alc. KOH) ... B. Malonic acid C. Maleic acid D. Oxalic acid

The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150

The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst(NaNO_(2)//HCl)underset(ul(" "0-5^(

Description : The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst(NaNO_(2)//HCl)underset(ul(" "0-5^(

Last Answer : The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst( ... 5^(@)C" "))toB` A. B. C. D.

Is KOC(CH3)3 equivalent to KOH as a base in chemical equations?

Description : Is KOC(CH3)3 equivalent to KOH as a base in chemical equations?

Last Answer : This depends completely on the equation in question. For instance, both are strong bases, so if that's all you're worried about, yeah, they're about equivalent. But potassium tert-butoxide is way bulkier ... not in others. Those are the big differences that jump out to me, but there may be others.

By whom were India’s famous Peacock Throne and the diamond Koh-e-Noor taken away? -Do You Know?

Description : By whom were India’s famous Peacock Throne and the diamond Koh-e-Noor taken away? -Do You Know?

Last Answer : answer:

WHAT ISBASIC ANHYDRIDE OF KOH?

Description : WHAT ISBASIC ANHYDRIDE OF KOH?

Last Answer : ko

What is the trade name of KOH ?

Description : What is the trade name of KOH ?

Last Answer : KOH 's trade name is Kashtik Potash.

When I log in to the original, it says "enter koh generated with the help of an authorized application" ps: nothing came to my mail?

Last Answer : Well it may take a while or turn to tech. support or reseller. ☠ ☠ ☣ ☠ ☣ ☠ ☣ ☠ ☢

Which of the following compounds will give isocyanide on reaction with `CHCl_(3) + KOH` ?

Description : Which of the following compounds will give isocyanide on reaction with `CHCl_(3) + KOH` ?

Last Answer : Which of the following compounds will give isocyanide on reaction with `CHCl_(3) + KOH` ? A. B. C. D. none of these

An orgainc compound A upon reacting with `NH_(3)` gives `B` On heating `B` give `C.C` in presence `KOH` reacts with `Br_(2)` to yield `CH_(3)CH_(2)NH_

Description : An orgainc compound A upon reacting with `NH_(3)` gives `B` On heating `B` give `C.C` in presence `KOH` reacts with `Br_(2)` to yield `CH_(3)CH_(2)NH_

Last Answer : An orgainc compound A upon reacting with `NH_(3)` gives `B` On heating `B` give `C.C` in presence `KOH ... underset(|)(CH)-COOH` D. `CH_(3)CH_(2)COOH`

The reaction of chloroform with alcoholic `KOH` and p- toluidine forms

Description : The reaction of chloroform with alcoholic `KOH` and p- toluidine forms

Last Answer : The reaction of chloroform with alcoholic `KOH` and p- toluidine forms A. B. C. D.

When primary aminereacts with chloroform in ehthanolic `KOH` then the product is .

Description : When primary aminereacts with chloroform in ehthanolic `KOH` then the product is .

Last Answer : When primary aminereacts with chloroform in ehthanolic `KOH` then the product is . A. an isocyanide B. an aldehyde C. a cyanide D. an alcohol

`CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`.

Description : `CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`.

Last Answer : `CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`. A. `CH_(3)-C-=N` B. `CH_(3)-NH- ... -= C^(+)` D. `CH_(3)-N^(+)-=C^(-)`

Chloroform when treated aniline and alcoholic KOH, the product formed is?

Description : Chloroform when treated aniline and alcoholic KOH, the product formed is?

Last Answer : Chloroform when treated aniline and alcoholic KOH, the product formed is? A. Phenyl cyanide B. Phenyl isocyanide C. Chlorobenzene D. Phenol

When m-chlorobenzaldehyde is treated with `50% KOH` solution, the product (s) obtained is (are)

Description : When m-chlorobenzaldehyde is treated with `50% KOH` solution, the product (s) obtained is (are)

Last Answer : When m-chlorobenzaldehyde is treated with `50% KOH` solution, the product (s) obtained is (are) A. B. C. D.

End product of the following reaction is `CH_(3)CH_(2)COOH overset(Cl_(2))underset(red P)to overset("alcoholic KOH")to`

Description : End product of the following reaction is `CH_(3)CH_(2)COOH overset(Cl_(2))underset(red P)to overset("alcoholic KOH")to`

Last Answer : End product of the following reaction is `CH_(3)CH_(2)COOH overset(Cl_(2))underset(red P)to overset(" ... |)(C)H_(2)underset(OH)underset(|)(C)HCOOH`

Cyclohexene on ozonolysis followed by reaction with zinc dust and water gives compound E. Compound E on furhter treatment with aqueous KOH yields comp

Description : Cyclohexene on ozonolysis followed by reaction with zinc dust and water gives compound E. Compound E on furhter treatment with aqueous KOH yields comp

Last Answer : Cyclohexene on ozonolysis followed by reaction with zinc dust and water gives compound E. Compound E on furhter ... . Compound F is A. B. C. D.

Ethylidene chloride on treatement with aq. KOH gives

Description : Ethylidene chloride on treatement with aq. KOH gives

Last Answer : Ethylidene chloride on treatement with aq. KOH gives A. `CH_(3)CHO` B. `(CH_(2)OH)_(2)` C. HCHO D. `(CHO)_(2)`

Write the product of following reactions `(a) CH_3-CH_(2)-OH overset(I_(2)//KOH)to "" Ph-CH_(2)-CO-CH_(3)overset(I_(2)//KOH)to` (c) CH_(3)-underset(OH

Description : Write the product of following reactions `(a) CH_3-CH_(2)-OH overset(I_(2)//KOH)to "" Ph-CH_(2)-CO-CH_(3)overset(I_(2)//KOH)to` (c) CH_(3)-underset(OH

Last Answer : Write the product of following reactions `(a) CH_3-CH_(2)-OH overset(I_(2)//KOH)to "" Ph-CH_(2)-CO- ... (OH)underset(|)(CH)-Ph overset(I_(2)//KOH)to`

Ethylidene chloride on treatement with aq. KOH gives

Description : Ethylidene chloride on treatement with aq. KOH gives

Last Answer : Ethylidene chloride on treatement with aq. KOH gives A. `CH_(3)CHO` B. `(CH_(2)OH)_(2)` C. HCHO D. `(CHO)_(2)`

Write the product of following reactions `(a) CH_3-CH_(2)-OH overset(I_(2)//KOH)to "" Ph-CH_(2)-CO-CH_(3)overset(I_(2)//KOH)to` (c) CH_(3)-underset(OH

Description : Write the product of following reactions `(a) CH_3-CH_(2)-OH overset(I_(2)//KOH)to "" Ph-CH_(2)-CO-CH_(3)overset(I_(2)//KOH)to` (c) CH_(3)-underset(OH

Last Answer : Write the product of following reactions `(a) CH_3-CH_(2)-OH overset(I_(2)//KOH)to "" Ph-CH_(2)-CO- ... (OH)underset(|)(CH)-Ph overset(I_(2)//KOH)to`

Which of the following compounds will give isocyanide on reaction with `CHCl_(3) + KOH` ?

Description : Which of the following compounds will give isocyanide on reaction with `CHCl_(3) + KOH` ?

Last Answer : Which of the following compounds will give isocyanide on reaction with `CHCl_(3) + KOH` ? A. B. C. D.

`overset(1.Br_(2)^(-)+KOH, Delta)underset(2.H_(3)O^(o+))rarr` The product of above reaction is:

Description : `overset(1.Br_(2)^(-)+KOH, Delta)underset(2.H_(3)O^(o+))rarr` The product of above reaction is:

Last Answer : `overset(1.Br_(2)^(-)+KOH, Delta)underset(2.H_(3)O^(o+))rarr` The product of above reaction is: A. B. C. D.

Carbylamine test is performed in alcoholic `KOH` by heating a mixture of:

Description : Carbylamine test is performed in alcoholic `KOH` by heating a mixture of:

Last Answer : Carbylamine test is performed in alcoholic `KOH` by heating a mixture of: A. chloroform and silver ... amine D. an alkyl cyanide and a primary amine

Reaction of `RCONH_(2)` with a mixture of `Br_(2)` and `KOH` gives `RNH_(2)` as the main product. The intermediates involved in the reaction are:

Description : Reaction of `RCONH_(2)` with a mixture of `Br_(2)` and `KOH` gives `RNH_(2)` as the main product. The intermediates involved in the reaction are:

Last Answer : Reaction of `RCONH_(2)` with a mixture of `Br_(2)` and `KOH` gives `RNH_(2)` as the main product. The intermediates ... ` B. `R-NHBr` C. `R-N=C=O` D.

Salicylic acid is produced when phenol in alcoholic KOH is treated with

Description : Salicylic acid is produced when phenol in alcoholic KOH is treated with

Last Answer : Salicylic acid is produced when phenol in alcoholic KOH is treated with A. `CH_(3)Cl` B. `CHCl_(3)` C. `CH_(2)Cl_(2)` D. `C Cl_(4)`

What is the final product obtained when chlorine reacts with ethyl alcohol in KOH ?

Description : What is the final product obtained when chlorine reacts with ethyl alcohol in KOH ?

Last Answer : What is the final product obtained when chlorine reacts with ethyl alcohol in KOH ? A. `CHCl_(3)` B. `C Cl_(3) CHO` C. `CH_(3)Cl` D. none

What is the oxidation for KOH?

Description : What is the oxidation for KOH?

Last Answer : The molecule is neutral.