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Given that the standard free energy change (∆G°) for the hydrolysis of ATP is –7.3 K cal/mol and that for the hydrolysis of Glucose 6-phosphate is –3.3 Kcal/mol, the ∆G° for the phosphorylation of glucose is Glucose + ATP → Glucose 6– Phosphate + ADP. (A) –10.6 Kcal/mol (B) –7.3 Kcal/mol (C) –4.0 Kcal/mol (D) +4.0 Kcal/mol
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Answer :  C
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