# What is KCL and KVL law?

What is KCL and KVL law?

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Kcl means sum of entering currents is equal to sum of leaving currents.

Kvl means sum of voltages around a clised loop is equal to zero.

Basically KCL and KVL are two laws that are presented by Kirchoff

KCL stands for kirchoff, s current law

And

KVL stands for kirchoff, s voltage law

According to KVL:sum of all the voltages in a closed loop is zero

For example

v1 +v2+ v3+ v4 =0

According to KCL:

Incoming current=outgoing current

## Related Questions

I found that by the same process of applying KCL and KVL, the problems of mesh analysis can also be solved. My teacher used KCL and KVL too. So, what's the difference between mesh analysis and Kirchoff's laws?

KVL examples
Last Answer : KVL example 2

KVL problem

State KVL and KCL
Last Answer : Statement of Kirchhoff's Current Law or KCL:  In any electrical network, the algebraic sum of the currents meeting at a point or junction is zero.  (OR)  Total current entering a junction or node is exactly ... all voltages within the loop must be equal to zero.  ∑ IR + ∑ emf = 0 round a mesh

Is KCL a restatement of the law of charge?

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Last Answer : u can assume the direction of current either in clockwise or anticlockwise...but the solution will remain same in both cases

does kvl appl for a switch that is closed?

What are the properties of KCl compound ?
Last Answer : 1. High melting point and boiling point. 2. Soluble in polar solvent (water) but insoluble in polar solvent. 3. In solid state it remains in the form of crystals. 4. Electrically conductive in molten or dissolved state.

The decomposition of `KClO_(3)` to KCl and `O_(2)` on heating is an example of :
Last Answer : The decomposition of `KClO_(3)` to KCl and `O_(2)` on heating is an example of : A ... redox change C. Disproportionation or auto redox change D. None

`CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`.
Last Answer : `CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`. A. `CH_(3)-C-=N` B. `CH_(3)-NH- ... -= C^(+)` D. `CH_(3)-N^(+)-=C^(-)`

How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii),"conc." H_(2)SO_(4) + KCl rarr),((iii),"conc." H_
Last Answer : How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii)," ... ,((ix),"conc." H_(2)SO_(4) + Cu rarr,,):}`

How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii),"conc." H_(2)SO_(4) + KCl rarr),((iii),"conc." H_
Last Answer : How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii)," ... ,((ix),"conc." H_(2)SO_(4) + Cu rarr,,):}`

One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`.
Last Answer : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`. A. 6 B. 1 C. 7 D. 3

`NiCl_(2) overset(KCN)to "complex"A` `NiCl_(2) underset("excess") overset(KCl)to "complex"B` A & B complexes have the co-ordination number 4. The hybr
Last Answer : `NiCl_(2) overset(KCN)to "complex"A` `NiCl_(2) underset("excess") overset(KCl)to "complex"B` A & B complexes have ... ^(2) & sp^(3)` D. both `sp^(3)`

During the electrolysis of carnallite , `MgCl_(2)` is decomposed and not KCl . This is because of :
Last Answer : During the electrolysis of carnallite , `MgCl_(2)` is decomposed and not KCl . This is because of : A. lower ... both (A) and (B) D. none of the above

Carnalite is present in sea water mainly. It is the main ore of magnesium which has the chemicakl fromula `MgCl_(2).KCl.xH_(2)O` . The value of x is .
Last Answer : Carnalite is present in sea water mainly. It is the main ore of magnesium which has the chemicakl fromula `MgCl_(2).KCl.xH_(2)O` . The value of x is .

What is the molarity of 10.0 g of KCl in 0.500 L of solution?
Last Answer : The molarity is 0,268.

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?
Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?
Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

How many mols in 74g of KCl?

Give reason for the following: (a)LiCl is more covalent than KCl. (b)LiF has lower melting point than NaCl. (c)CuCl is more covalent than NaCl.
Last Answer : Ans(a).Due to smaller size and high poalrising power of Li+ ion ,LiCl is more covalent than KCl. (b)Small cation Li+ ion highly polarizes large anion I- , LiI is more covalent and hence has ... to pseudo inert gas configuration, Cu+ is more polarizing than Na+ and hence CuCl is more Covalent NaCl.

Which will have greater molar conductivity ? Solution containing 1 mol KCl in 200 cc or 1 mol of KCl in 500 cc.
Last Answer : Ans. 1 mol of KCl in 500 cc.

Muriate of Potash is— (A) K 2 SO 4 (B) KCl (C) K 2 HPO 4 (D) KNO 3

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Potassic fertiliser is graded based on its __________ content. (A) KCl (B) K2O (C) KNO3 (D) K2SO4

What is KCL in circuit?
Last Answer : Kirchhoff's Current Law which states that " The sum of the currents entering a junction is equal to the sum of the currents leaving the junctions."

Ohm's law formula
Last Answer : Ohm's law formula

Kirchhoff's Voltage Law
Last Answer : Kirchhoff's voltage law

Kirchhoff's Current Law
Last Answer : Kirchhoff's current law

State and explain Lenz's law.
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