Description : An analog signal carries 4 bits in each signal unit. If 1000 signal units are sent per second, then baud rate and bit rate of the signal are ............... and .............. (A) 4000 bauds \ sec & ... (B) 2000 bauds \ sec & 1000 bps (C) 1000 bauds \ sec & 500 bps (D) 1000 bauds \ sec & 4000 bps
Last Answer : (D) 1000 bauds \ sec & 4000 bps Explanation: Bit rate is the number of bits per second. Baud rate is the number of signal units per second. Baud rate is less than or equal to the bit rate. Baud rate = 1000 bauds per second (baud/s) Bit rate = 1000 x 4 = 4000 bps
Description : The baud rate of a signal is 600 baud/second. If each signal unit carries 6 bits, then the bit rate of a signal is ................. (A) 3600 (B) 100 (C) 6/600 (D) None of the above
Last Answer : (A) 3600
Description : A device is sending out data at the rate of 2000 bps. How long does it take to send a file of 1,00,000 characters ? (A) 50 (B) 200 (C) 400 (D) 800
Last Answer : (C) 400 Explanation: 1,00,000 characters = 1,00,000 x 8 bits = 8,00,000 bits 8,00,000 bits/2000 bps = 400 seconds
Description : Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it ... sample requires 8 bits? (A) 32 kbps (B) 64 kbps (C) 128 kbps (D) 256 kbps
Last Answer : (C) 128 kbps
Description : A device is sending out data at the rate of 2000 bps. How long does it take to send a file of 1,00,000 characters ? a. 50 b. 200 c. 400 d. 800
Last Answer : c. 400
Description : In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps
Last Answer : (C) 1000 bps
Description : What is the commonly used unit for measuring the speed of data transmission? A) Bytes per second B) Baud C) Bits per second
Last Answer : B) Baud
Description : How many bytes of data can be sent in 15 seconds over a serial link with baud rate of 9600 in asynchronous mode with odd parity and two stop bits in the frame? a. 10,000 bytes b. 12,000 bytes c. 15,000 bytes d. 27,000 bytes
Last Answer : b. 12,000 bytes
Description : Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is ............... (A) 400 bps (B) 800 bps (C) 1600 bps (D) 3200 bps
Last Answer : (D) 3200 bps Answer: D Explanation: The multiplexer is shown in the Figure. Each frame carries 1 byte from each channel; the size of each frame, therefore, is 4 bytes, or 32 bits. Because each ... channel, the frame rate must be 100 frames per second. The bit rate is 100 32 = 3200 bps.
Description : A data file of 1,00,000 characters contains only the characters g-l, with the frequencies as indicated in table: using the variable-length code by Huffman codes, the file can be encoded with (A) 2,52,000 bits (B) 2,64,000 bits (C) 2,46,000 bits (D) 2,24,000 bits
Last Answer : (D) 2,24,000 bits
Description : Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s. b. 2 c. 2.5 d. 5
Last Answer : b. 2
Description : The data rate is sometimes calledthe ___ rate. A) baud B) bit C) signal D) none of the above
Last Answer : bit
Description : The ________ rate defines thenumber of dataelements sent in1s; the______ rate is the numberof signalelements sent in 1s. A) data; signal B) signal; data C) baud; bit D) none of the above
Last Answer : data; signal
Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps
Last Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps
Description : How many 8-bit characters can be transmitted per second over a 9600 baud serial communication link using asynchronous mode of transmission with one start bit, eight data bits, two stop bits, and one parity bit ? a. 600 b. 800 c. 876 d. 1200
Last Answer : b. 800
Description : The signal rate is sometimes called the ____ rate. A) baud B) bit C) signal D) none of the above
Last Answer : baud
Description : Usually, it takes10-bits to represent one character. How many characters can betransmittedat a speed of 1200 BPS? A. 10 B. 12 C. 120 D. 1200 E. None of the above
Last Answer : 120
Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps
Last Answer : Answer: Marks given to all
Description : If the bit rate for a16-QAM signal is 4000 bps, what is the baudrate? A) 300 B) 400 C) 1000 D) 1200
Last Answer : 1000
Description : If the bit rate for an FSK signal is1200 bps, thebaud rate is ________. A) 300 B) 400 C) 600 D) 1200
Last Answer : 1200
Description : f the bit rate for an ASK signal is1200 bps, thebaud rate is ________. A) 300 B) 400 C) 600 D) 1200
Description : Processor’s speed of a computer is measured in (1) BPS (2) MIPS (3) Baud (4) Hertz
Last Answer : Million instructions per second (MIPS)
Description : How many characters per sec (7 bits + 1 parity ) can be transmitted over a 2400 bps line if the transfer is synchronous (1 start and 1 stop bit)?
Last Answer : 1. 300 2. 240 3. 250 4. 275 Ans- 2400/(7+1+2) 240
Description : ECE Board Exam March 1996 What is the transmission rate of a system for transmitting the output of a microcomputer to a line printer operating at a speed of 30 lines/minute? Assume that the line printer has 8 bits ... and prints out 80 characters/line. A. 800 bps B. 400 bps C. 320 bps D. 640 bps
Last Answer : C. 320 bps
Description : What is the baud rate of the standard 10 Mbps Ethernet ? (A) 10 megabaud (B) 20 megabaud (C) 30 megabaud (D) 40 megabaud
Last Answer : (B) 20 megabaud
Description : What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps
Last Answer : (C) 153.6 Mbps Explanation: The number of bits/sec is just 800x600x40x8 or 153.6 Mbps.
Description : A multiplexer combines four 100-Kbps channels using a time slot of 2 bits. What is the bit rate? (A) 100 Kbps (B) 200 Kbps (C) 400 kbps (D) 1000 Kbps
Last Answer : (C) 400 kbps
Description : For the 8-bit word 00111001, the check bits stored with it would be 0111. Suppose when the word is read from memory, the check bits are calculated to be 1101. What is the data word that was read from memory? (A) 10011001 (B) 00011001 (C) 00111000 (D) 11000110
Last Answer : (B) 00011001
Description : In Unix, files can be protected by assigning each one a 9-bit mode called rights bits. Now, consider the following two statements: I. A mode of 641 (octal) means that the owner can read and write the file, other ... (B) Only II is correct (C) Both I and II are correct (D) Both I and II are incorrect
Last Answer : (C) Both I and II are correct
Description : The process of dividing an analog signal into a string of discrete outputs, each of constant amplitude, is called: (A) Strobing (B) Amplification (C) Conditioning (D) Quantization
Last Answer : (D) Quantization
Description : What is the commonly used unit for measuring the speed of data transmission? A) Bytes per second B) Baud C) Bits per second D) Both B and C
Description : The ______ technique expands the bandwidthof a signal by replacing each data bit with n bits. A) FDM B) DSSS C) FHSS D) TDM
Last Answer : DSSS
Description : Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is __________. a. 400 bps b. 800 bps c. 1600 bps d. 3200 bps
Last Answer : d. 3200 bps
Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps
Last Answer : (B) 2 Mbps
Description : A computer program selects an integer in the set {k : 1 ≤ k ≤ 10,00,000} at random and prints out the result. This process is repeated 1 million times. What is the probability that the value k = 1 appears in the printout atleast once ? (A) 0.5 (B) 0.704 (C) 0.632121 (D) 0.68
Last Answer : (C) 0.632121
Description : If X is a binary number which is power of 2, then the value of X&(X-1) is: (1) 11....11 (2) 00.....00 (3) 100.....0 (4) 000.....1
Last Answer : Answer: 2
Description : The missing number in the series : 0, 6, 24, 60, 120, ?, 336, is (A) 240 (B) 220 (C) 280 (D) 210
Last Answer : Answer: D
Description : Is the total useful information processed or communicated over a specific amount of time A. Baud rate B. Bit rate C. Information theory D. Throughput
Last Answer : D. Throughput
Description : In Ethernet when Manchester encoding is used, the bit rate is: a. Half the baud rate. b. Twice the baud rate. c. Same as the baud rate. d. None of the above
Last Answer : a. Half the baud rate.
Description : Define (i)Bit rate (ii)Baud rate
Last Answer : (i)Bit rate :- Bit rate is simply the number of bits transmitted during one second and is expressed in bits per second (bps). Mathematically bit rate is given by:- Rb =1 / Tb where Tb is time ... 1 / Ts Where, baud rate = symbol rate (symbols per second) and Ts = time interval of one symbol.
Description : Which performance parameter is the minimum amount of optical power required to achieve a specific bit-error rate (BER) in digital systems or a given signal-to-noise ratio (SNR) in analog systems?
Last Answer : Receiver sensitivity.
Description : In a laboratory test run, the rate of drying was found to be 0.5 x 10 - 3 kg/m2 .s, when the moisture content reduced from 0.4 to 0.1 on dry basis. The critical moisture content of the material is 0.08 on a dry ... of the solids from 0.3 to 0.2 (dry basis) is (A) 2000 (B) 4000 (C) 5000 (D) 6000
Last Answer : (C) 5000
Description : Which of the following statements are true ? I. A circuit that adds two bits, producing a sum bit and a carry bit is called half adder. II. A circuit that adds two bits, producing a sum bit and a carry bit is called full adder. ... an inverter. (A) I & II (B) II & III (C) I, II, III (D) I, III & IV
Last Answer : (D) I, III & IV
Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps
Last Answer : a. 2 Mbps
Description : If the claim does not exceed Rs. 1,00,000, the claimant should be asked to submit an application duly completed to the authorities mentioned below who are competent to sanction claims without production of legal ... director, Director GPO is Rs 75000/- d) CPMG/PMG Rs 10000/- e) All the above
Last Answer : e) All the above
Description : Bits can be sent over guided and unguided media as analog signal by ___________ a. digital modulation b. amplitude modulation c. frequency modulation d. phase modulation
Last Answer : a. digital modulation
Description : A terminal multiplexer has six 1200 bps terminals and ‘n’ 300 bps terminals connected to it. If the outgoing line is 9600 bps, what is the value of n ? (A) 4 (B) 8 (C) 16 (D) 28
Last Answer : (B) 8
Description : A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec
Last Answer : (D) 533.33 m sec Explanation: The request has to go up and down, and the response has to go up and down. The total path length traversed is thus 160.000 km. The speed of light in air and vacuum is 300,000 km/sec, so the propagation delay alone is 160,000/300,000 sec or about 533 msec.
Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps
Last Answer : (C) 32 Kbps
Description : If the baudrate is400 for a QPSK signal, thebit rate is ________ bps. A) 100 B) 400 C) 800 D) 1600
Last Answer : 800