What is the baud rate of the standard 10 Mbps Ethernet ? (A) 10 megabaud (B) 20 megabaud (C) 30 megabaud (D) 40 megabaud

What is the baud rate of the standard 10 Mbps Ethernet ? (A) 10 megabaud (B) 20 megabaud (C) 30 megabaud (D) 40 megabaud
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(B) 20 megabaud
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Ethernet is baseband system using CSMA/CD operating at A. 20 Mbps B. 10 Mbps C. 30 Mbps D. 40 Mbps

Description : Ethernet is baseband system using CSMA/CD operating at A. 20 Mbps B. 10 Mbps C. 30 Mbps D. 40 Mbps

Last Answer : B. 10 Mbps

An image is 1024∗800 pixels with 3 bytes/pixel. Assume the image is uncompressed. How long does it take to transmit it over a 10-Mbps Ethernet ? (A) 196.6 seconds (B) 19.66 seconds (C) 1.966 seconds (D) 0.1966 seconds

Description : An image is 1024∗800 pixels with 3 bytes/pixel. Assume the image is uncompressed. How long does it take to transmit it over a 10-Mbps Ethernet ? (A) 196.6 seconds (B) 19.66 seconds (C) 1.966 seconds (D) 0.1966 seconds

Last Answer : (C) 1.966 seconds

Standard Ethernet (10-Mbps) uses_______ encoding A) NRZ B) AMI C) Manchester D) differential Manchester

Description : Standard Ethernet (10-Mbps) uses_______ encoding A) NRZ B) AMI C) Manchester D) differential Manchester

Last Answer : Manchester

The IEEE 802.3 Standard defines _________ CSMA/CD as the access method for first-generation 10-Mbps Ethernet. A) 1-persistent B) p-persistent C) non-persistent D) none of the above

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Last Answer : 1-persistent

What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps

Description : What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps 

Last Answer : (C) 153.6 Mbps Explanation: The number of bits/sec is just 800x600x40x8 or 153.6 Mbps.

In Ethernet when Manchester encoding is used, the bit rate is: a. Half the baud rate. b. Twice the baud rate. c. Same as the baud rate. d. None of the above

Description : In Ethernet when Manchester encoding is used, the bit rate is: a. Half the baud rate. b. Twice the baud rate. c. Same as the baud rate. d. None of the above

Last Answer : a. Half the baud rate.

Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s.b. 2 c. 2.5 d. 5

Description : Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s. b. 2 c. 2.5 d. 5

Last Answer : b. 2

The baud rate of a signal is 600 baud/second. If each signal unit carries 6 bits, then the bit rate of a signal is ................. (A) 3600 (B) 100 (C) 6/600 (D) None of the above

Description : The baud rate of a signal is 600 baud/second. If each signal unit carries 6 bits, then the bit rate of a signal is ................. (A) 3600 (B) 100 (C) 6/600 (D) None of the above

Last Answer : (A) 3600 

An analog signal carries 4 bits in each signal unit. If 1000 signal units are sent per second, then baud rate and bit rate of the signal are ............... and .............. (A) 4000 bauds \ sec & 1000 bps (B) 2000 bauds \ sec & 1000 bps (C) 1000 bauds \ sec & 500 bps (D) 1000 bauds \ sec & 4000 bps

Description : An analog signal carries 4 bits in each signal unit. If 1000 signal units are sent per second, then baud rate and bit rate of the signal are ............... and .............. (A) 4000 bauds \ sec & ... (B) 2000 bauds \ sec & 1000 bps (C) 1000 bauds \ sec & 500 bps (D) 1000 bauds \ sec & 4000 bps

Last Answer : (D) 1000 bauds \ sec & 4000 bps Explanation: Bit rate is the number of bits per second. Baud rate is the number of signal units per second. Baud rate is less than or equal to the bit rate. Baud rate = 1000 bauds per second (baud/s) Bit rate = 1000 x 4 = 4000 bps

An analog signal has a bit rate of 6000 bps and a baud rate of 2000 baud. How many data elements are carried by each signal element ? (A) 0.336 bits/baud (B) 3 bits/baud (C) 120,00,000 bits/baud (D) None of the above

Description : An analog signal has a bit rate of 6000 bps and a baud rate of 2000 baud. How many data elements are carried by each signal element ? (A) 0.336 bits/baud (B) 3 bits/baud (C) 120,00,000 bits/baud (D) None of the above

Last Answer : (B) 3 bits/baud

In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps

Description : In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps

Last Answer : (C) 1000 bps 

A node X on a 10 Mbps network is regulated by a token bucket. The token bucket is filled at a rate of 2 Mbps. Token bucket is initially filled with 16 megabits. The maximum duration taken by X to transmit at full rate of 10 Mbps is ............ secs. (1) 1 (2) 2 (3) 3 (4) 4

Description : A node X on a 10 Mbps network is regulated by a token bucket. The token bucket is filled at a rate of 2 Mbps. Token bucket is initially filled with 16 megabits. The maximum duration taken by X to transmit at full rate of 10 Mbps is ............ secs. (1) 1 (2) 2 (3) 3 (4) 4

Last Answer : (2) 2 

The maximum frame length for 10-Mbps Ethernet is ________ bytes. A) 1518 B) 1500 C) 1200 D) none of the abov

Description : The maximum frame length for 10-Mbps Ethernet is ________ bytes. A) 1518 B) 1500 C) 1200 D) none of the abov

Last Answer : 1518

The minimum frame length for 10-Mbps Ethernet is _______bytes. A) 32 B) 80 C) 128 D) none of the above

Description : The minimum frame length for 10-Mbps Ethernet is _______bytes. A) 32 B) 80 C) 128 D) none of the above

Last Answer : none of the above

Suppose the round trip propagation delay for a 10 Mbps Ethernet having 48-bit jamming signal is 46.4 ms. The minimum frame size is a. 94 b. 416 c. 464

Description : Suppose the round trip propagation delay for a 10 Mbps Ethernet having 48-bit jamming signal is 46.4 ms. The minimum frame size is a. 94 b. 416 c. 464

Last Answer : c. 464

Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ................ (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Last Answer : Answer: Marks given to all

If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps

Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps

Last Answer : (C) 32 Kbps

………………….. is a collective term for a number of Ethernet Standards that carry traffic at the nominal rate of 1000 Mbit/s against the original Ethernet speed of 10 Mbit/s. A) Ethernet B) Fast Ethernet C) Gigabit Ethernet D) All of the above

Description : ………………….. is a collective term for a number of Ethernet Standards that carry traffic at the nominal rate of 1000 Mbit/s against the original Ethernet speed of 10 Mbit/s. A) Ethernet B) Fast Ethernet C) Gigabit Ethernet D) All of the above

Last Answer : B) Fast Ethernet

............ is a collective term for a number of Ethernet Standards that carry traffic at the nominal rate of 1000 Mbits/s against the original Ethernet speed of 10 Mbit/s. A) Ethernet B) Fast Ethernet C) Gigabit Ethernet D) All of the above

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Last Answer : B) Fast Ethernet

Suppose that the one-way propagation delay for a 100 Mbps Ethernet having 48-bit jamming signal is 1.04 micro-seconds. The minimum frame size in bits is: a. 112 b. 160 c. 208 d. 256

Description : Suppose that the one-way propagation delay for a 100 Mbps Ethernet having 48-bit jamming signal is 1.04 micro-seconds. The minimum frame size in bits is: a. 112 b. 160 c. 208 d. 256

Last Answer : d. 256

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Last Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps 

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Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Last Answer : (B) 2 Mbps

Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Description : Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Last Answer : (2) 10

A WAN typically spans a set of countries that have data rates less than ……………. Mbps.A) 2 B) 1 C) 4 D) 100

Description : A WAN typically spans a set of countries that have data rates less than ……………. Mbps.A) 2 B) 1 C) 4 D) 100

Last Answer : B) 1

……………….. is a high performance fiber optic token ring LAN running at 100 Mbps over distances upto 1000 stations connected. A) FDDI B) FDDT C) FDDR D) FOTR

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Last Answer : A) FDDI

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Description : What is the name of the European WLAN standard that provides user data rate upto 54 Mbps? a) UNII b) WISP c) MMAC d) HIPERLAN/2

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Description : Consider a fuzzy set old as defined below Old = {(20, 0.1), (30, 0.2), (40, 0.4), (50, 0.6), (60, 0.8), (70, 1), (80, 1)} Then the alpha-cut for alpha = 0.4 for the set old will be (A) {(40, 0.4)} (B) {50, 60, ... , (30, 0.2)} (D) {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}

Last Answer : (D) {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}

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Description : IEEE 802.3ab defines Gigabit Ethernet transmission over unshielded twisted pair (UTP) category 5, 5e or 6 cabling known as .................... A) 1000 BASE-T B) 1000 BASE-SX C) 1000 BASE-LX D) 1000 BASE-CX

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Last Answer : B) 100 BASE-TX

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Last Answer : A) Star LAN

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Last Answer : (B) 38

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Assume that a program will experience 200 failures in infinite time. It has now experienced 100 failures. The initial failure intensity was 20 failures/CPU hr. Then the current failure intensity will be (A) 5 failures/CPU hr (B) 10 failures/CPU hr. (C) 20 failures/CPU hr. (D) 40 failures/CPU hr.

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