In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid Rs.156 for a journey of 16 km and another person paid Rs.204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is (A) 236 (B) 240 (C) 248 (D) 256

1 Answer

Answer :

Answer: B

Related questions

Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Last Answer : 3) 840 km

Description : On a certain day, the ratio of the passenger in the 1st class and the second class travelling by train is 1:3. the ratio of the fares collected from each first class and second class passengers is 30:1. If ... in Rs, collected from the second class passengers. A) 240 B) 360 C) 480 D) 120 E) None

Last Answer : Answer: D Let the number of passengers travelling by first class and second class be x and 3x respectively. Lets the fares collected from each of the first class and second class passengers be 30y and y ... 3xy=33xy=1320 xy=40. Total amount collected from the second class =3xy=3 40= Rs 120.

Description : 188, 212, 236, ?, 268, 284 a) 260 b) 256 c) 252 d) 248 e) 244

Last Answer : The pattern is 47×4=188, 53×4=212, 59×4=236, 61×4=244, 67×4=268, 71×4=284 47, 53, 59, 61, 69 and 71 are consecutive prime numbers. Answer: e)

Description : Shreya travel the first part of her journey at 160 kmph and the second part at 240 kmph and cover the total distance of 3840 km to her destination in 20 hours. How long did the first part of her journey last? a) 8 hrs b) 12 hrs c) 16 hrs d) 10 hrs

Last Answer : B The total time of journey = 20 hours. Let 'x' hours be the time that shreya travelled at 160 kmph Therefore, 20-x hours would be time that she travelled at 240 kmph. Hence, she would have covered x*160+( ... 20-x)*240 =3840 160x +4800-240x =3840 240x-160x=4800-3840 80x= 960 X=960/80=12 hrs

Description : Two taps M and N can alone fill a tank in 80 minutes and 120 minutes respectively. But due to a leakage of tank, it took 12 more minutes to fill the tank. In how many hours, the leak can alone empty the full tank? A) 240 B) 230 C) 248 D) 256

Last Answer : A A and B can fill tank in (1/80 + 1/120) = 1/48 so 48minutes But it took 12 more minutes, this means the tank got full in 48+12= 60 minutes So (1/80 + 1/120 – 1/x) = 1/60 1/X=1/80+1/120-1/60 Solve, x = 240

Description : Anil after travelling 6 km towards East from his house realized that he has travelled in a wrong direction, lie turned and travelled 12 km towards West, turned right and travelled 8 km to reach his office. The straight distance of the office from his house is: (A) 20 km (B) 14 km (C) 12 km (D) 10 km

Last Answer : Answer: D

Description : 256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176

Last Answer : The series is ×0.5, ÷1, ×1.5, ÷2, ×2.5.... Answer: d)

Description : Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Last Answer : C) Given x= 168 , y = 112 Required average speed = (2xy / x + y) km/hr = 2 * 168 *112 / 168 + 112 = 37632 / 280 =134.4 km/hr

Description : Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.

Last Answer : A Mr.Aneesh travelled 60 km/hr for 1 1/2 hours (3/2 hours). Distance covered in 3/2 hours = 60 x 3/2 = 90 km. Therefore, remaining distance = 120 -90 = 30 km After 3/2 hours, the speed was ... village 2 at 3.00 pm + 3 hours 30 minutes = 6.30pm Hence the required answer is 6.30 pm.

Description : Insert the missing number in the following series: 4 16 8 64 ? 256 (A) 16 (B) 24 (C) 32 (D) 20

Last Answer : Answer: A Square root of 16 is 4, Square root of 64 is 8, Therefore Square root of 256 is 16.

Description : Three individuals X, Y, Z hired a car on a sharing basis and paid Rs. 1,040. They used it for 7, 8, 11 hours, respectively. What are the charges paid by Y? (A) Rs. 290 (B) Rs. 320 (C) Rs. 360 (D) Rs. 440

Last Answer : Answer: B X,Y,Z used car for 26 hours i.e 7 + 8 + 11 = 26 paid 1040. Therefore, 1040/26 = 40, Y used for 8 hours i.e 40 * 8 = 320.

Description : Preethi bought 240 reams of brown sheet at Rs 200 per ream and the expenditure on transport Was Rs 960. she had to pay an octroi duty of 1Rs per ream and the labour charges were Rs 120. What should she charge per ream to gain 80%(in Rs)?

Last Answer : Total CP= Rs(240*200)=Rs. 48000 Total expenditure=(960+1*240+120)= Rs. 1320 totalCp= 48000+1320=Rs. 49320 gain= 80% sp of 240reams = 49320*180/100 = Rs.88776 Sp per ream= 88776/240= Rs 369.9

Description : There is a bridge besides a river. Two friends Arun and varun started their journey from place L, moved to the garden located at another place M & then returned to place L. Arun moves by swimming at a speed of 30 ... 12km/hr, what will be the average speed of boat sailor? A) 36 B) 18 C) 24 D) 48 

Last Answer : ANSWER:B Explanation: As Arun swims both the ways at the speed of 30km/hr, the average speed of swimming is 30 km/hr Being a boat sailor, varun moves downstream at speed =24 +12=36km/hr and upstream at speed = 24-12= ... Upstream Speed])] = (36*12)/0.5(36+12) km/hr = 432/24 km/hr = 18 km/hr

Description : A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Last Answer : Let the distance be x km. then (x/40) + (x/6) = 13 + (48/60) = 69/5 Answer is: d)

Description : 5 6 16 57 ? 1245 7506 a) 240 b) 248 c) 244 d) 250 e) 260

Last Answer : Answer: b)

Description : A taxi driver makes a profit of 25% on every trip when he carries 4 passengers and the price of petrol is Rs. 35 a litre. Find the approximate % profit for the same journey if he goes for 5 passengers per trip and the price of petrol reduces to Rs. 28 litres?

Last Answer : When 4 passengers income was 4x Expense= Rs.35. Profit =25% of 35+35= Rs.43.75 That means his earning is Rs.44.775.so that per passenger fare must be Rs.10.93  When 5 passengers earning = 10.99x5=Rs.54.68 Expense =Rs.28  Profit = 95.28 % approx.

Description : A train, 1800 meters long running at the rate of 204 km/hr will cross a platform in: A) 16 B) 32 C) 45 D) 64 

Last Answer : ANSWER: B  Explanation: Speed of the train = 204 km/hr. We have to find the time in seconds, so convert the speed in the unit of m/sec. Therefore 204 km/hr = 204 x 5/18 m/s  = 1020/18 m/s  Length ... m/sec  Time = distance/speed  = 1800/(1020/18)sec  = (1800*18/1020)sec  = 32 sec (approx.)

Description : A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60 

Last Answer : B Average speed =(2xy/( x+y)) km/hr Given x =60 km/hr y = 30km/hr Average speed = (2*60*30/ (60+30)) km/hr =(3600/ 90) =40 km/hr

Description : A person covered `5//8` of his journey and he has to walk 240 m more to complete his journey. Find the total distance of the journey

Last Answer : A person covered `5//8` of his journey and he has to walk 240 m more to complete his journey. Find the total distance of the journey

Description : The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs ... speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Last Answer : D Let the speed in return journey be x km/hr Then speed in upward journey = 150 /100 x = (3/2 x)km/hr Average speed = (2*3x/2*x) / (3x/2 +x) =3x2 / (5x/2) =6x2 / 5x =6x/5 km/hr Therefore (1600 ... 192x = 8000 X = 41.66 Speed in upward journey = (3/2 x ) km/hr =(3/2*41.66) =62.49 km/hr 

Description : A man wnt uphill with a speed of 20 km.p.h. and came downhill with a speed of 30 km p.h. The average speed for his journey was (a) 25 km. p.h. (b) 22 1/2 km. p.h. (c) 24 km. p.h. (d) 25 1/2 km. p.h.

Last Answer : 24 km.p.h.

Description : The total number of bones in our body is - (1) 226 (2) 206 (3) 256 (4) 236

Last Answer : (2) 206

Description : Income and expenses for the year 2012 are- Fee Received in Cash - Rs.24,000 Accrued Fee - Rs.6,000 Rent for Chamber Paid - Rs.6,000 Outstanding Rent - Rs.2,000 Salary Paid to Staff - Rs.6,000 Miscellaneous Expenses Paid - Rs. ... basis ? (A) Rs. 11,800 (B) Rs. 13,200 (C) Rs. 16,800 (D) Rs. 30,000

Last Answer : Answer: Rs. 13,200

Description : The missing number in the series : 0, 6, 24, 60, 120, ?, 336, is (A) 240 (B) 220 (C) 280 (D) 210

Last Answer : Answer: D

Description : The torque on a conductor with flux density 23 units, current 1.6A and area 6.75 units will be a) 248.4 b) 192.6 c) 175.4 d) 256.9

Last Answer : a) 248.4

Description : For a fixed beam with UDL,maximum bending moment at midpoint is a. wL3/248 b. wL2/248 c. wL2/24 d. wL2/24

Last Answer : c. wL2/24

Description : A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance travelled by car. -Science

Last Answer : a. Acceleration is given by a=ΔvΔta=ΔvΔt Δv=54−36=18km/hr=18×10003600m/s=5m/sΔv=54−36=18km/hr=18×10003600m/s=5m/s So a=.5 m/s2 b. Distance is given by S=ut+12at2S=ut+12at2 Now u=36 km/hr =10m/s s=10×10+12×.5×102s=10×10+12×.5×102 So s=125m

Description : 2 bus start from A & B respectively and travel towards each other at a speed of 150 km/hr and 120 km/hr respectively. By the time they meet, the first bus has travelled by 300km more than the second. The distance between A & B is a) 2700 b) 2800 c) 2750 d) 2457

Last Answer : A At the time of meeting, Let the distance travelled by the second bus be xkm Then distance covered by the 1st bus is (x+300)km x/120= (x+300) /150 150x = 120(x+300) 150x = 120x +36000 30x = ... X=36000/30 X=1200 So the distance covered between A & B =(x+x+300) =(1200+1200+300) =2700km.

Description : The speed of a van increases by 5 kmph after every one hour. If the distance travelled in the first one hour was 55 km, what was the total distance travelled in 8 hours? a) 580km b) 116km c) 147km d) 240km

Last Answer :  A Distance travelled in 1ST hour =55 km Speed of the van increases by 5 kmph after every one hour. Hence, distance travelled in 2nd hour =60 km distance travelled in 3rd hour =65 km and so on Total distance travelled =(55+60+……..+(8 terms)) =8/2(2*55+(8-1)5) =4(110+35) =580km

Description : In a business P and R invested amounts in the ratio 2 : 1, whereas the ratio between amounts invested by P and Q was 3 : 2 . If Rs. 2,236 was their profit, how much amount did Q  receive ? A.Rs.650 B.Rs.688 c.Rs.588 D.Rs.490

Last Answer : Answer- B(Rs.688 ) Solution : P : Q = 3 : 2 , P : R = 2 : 1 [given] Q : P = 2 : 3 [reverse], Q : P = 4 : 6 [multiply by 2] Now, P : R = 2 : 1 P : R = 6 : 3 [multiply by 3] P : Q =6 : 4 [after x3] , So Q : P : R = 4 : 6 : 3 or, P : Q : R = 6 : 4 : 3 Q’s share= 4/13 x 2236=Rs.688

Description : On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Last Answer : Answer: B Solution:. Let us find the day on 1st April, 1994. 2000 years have 0 odd day. We have to calculate day on 1st April, 1994. 2000-1994 = 6 Years. 1996 is leap year and have 4 odd days Ordinary years ... was Friday Thus, on 3 rd , 10 th , 17 th , 24 th will be Sunday fall on April 1994.

Description : Two railway tickets from city A and B and three tickets from city A to C cost Rs.177. Three tickets from city A to B and two tickets from city A to C city Rs.173. The fare for city B from city A will be Rs. (A) 25 (B) 27 (C) 30 (D) 33

Last Answer : Answer: D

Description : With anIP address set starting with 150, you currently havesix offices that you are treating as subnets. Plans are in place toopen 10 more officesbefore the end of theyear. What subnet mask should you useto ... maximize thenumberof hosts available at eachsite? A. 192 B. 224 C. 240 D. 248 E. 252

Last Answer : 248

Description : You are working with a network thathas the network ID 192.168.10.0. What subnet should you use that supportsup to 25 hosts and a maximum number of subnets? A. 255.255.255.192 B. 255.255.255.224 C. 255.255.255.240 D. 255.255.255.248 E. 255.255.255.252

Last Answer : 255.255.255.224

Description : With anIP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts? A. 192 B. 224 C. 240 D. 248 E. 252

Last Answer : 252

Description : You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. ... B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255

Last Answer : 255.254.0.0

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

Description : A boys rows to a certain place and comes back, but by mistake he covers 2/3rd more distance while coming back. The total time for this journey is 20 hours. The ratio of speed of boat to that of ... starting point from his present position? A) 2hr 13mints B)1hr 30 mins C) 2hr 30mins D)1hr 40 mins

Last Answer : ANSWER : A Explanation: let speed of boat and stream be 2x and x respectively So downstream speed = 2x+x = 3x, and upstream speed = 2x-x = x Let total distance between points is d km So he covered d ... with speed 3x = 48 km/hr(downstream) So time is 80/36 * 60 = 133.33 minutes = 2hr 13mins

Description : Which of the following comprise teaching skill? (A) Black Board writing (B) Questioning (C) Explaining (D) All the above

Last Answer : Answer: D  All of the above are the teaching skills without them a teacher is like a without gun in a battalefield. Basic teaching skills Setting the scene - make sure that your students are ... and closing a session -don't give new information, and remind students about next week's topic

Description : A sum of money is divided among Suresh, Ganesh, Vignesh and Mahesh in the ratio of 3 : 4 : 9 : 10 respectively. If the share of Vignesh is Rs.2,580/-more than the share of Ganesh, then what is the total amount of money of Suresh ... ,985/- b) Rs. 6,487/- c) Rs. 6,708/- d) Rs. 7,156/- e) Rs. 8,457/-

Last Answer : According to the question, difference of ratio of Ganesh and Vignesh is 5 so, 1 ratio = 2580/5 = 516 Now, total ratio of Suresh + Mahesh = 13 So, total money = 13 × 516 = Rs. 6708 Answer: c)

Description : Wipro is the leading IT company then the profit earned by same organization is distributed among HR and officers in the ratio of 13:7 respectively. If the number of HR is 104 and the number of officers is ... amount received by HR is Rs 6000. What was the total amount of profit earned (in lakhs )?

Last Answer : Total amount distributed among 104 HR’s= Rs. 104*6000 =Rs. 624000 Let the amount distributed to 156 officers be x Then 624000/x = 13/ 7 Then x = Rs, 336000 The total profit = Rs. 624000+336000= Rs. 9.6lakhs

Description : Horizontal distance travelled by a ball if it's thrown with initial velocity of 20 m s-1 at an angle of 30° is A. 24 m B. 56 m C. 35.3 m D. 36.3 m

Last Answer : 35.3 m

Description : What is the distance travelled by an object over a certain period of time?

Last Answer : There are two pieces of data that need to be recorded. The distance and the time it takes to complete the known distance, gives you the speed. For an example, your car travels at a steady 60 miles, in one hour you would expect to have travelled 60 miles.

Description : For a space wave transmission, the radio horizon distance of a receiving antenna with a height of 64 meters is approximately A. 8 km B. 32 km C. 64 km D. 256 km

Last Answer : B. 32 km

Description : A 1800 km journey of 24 hrs, if 360km is done by van and the rest by train. It takes 60 mins more, if 600km is done by van and the rest by train. The ratio of the speed of the van to that of the train is. a) 2:4 b) 4:3 c) 3:4 d) 5:3

Last Answer : C Let the speed of the van be x km/hr And that of the train be y km/hr 360/x+1440/y = 24 --------------->A Dividing by 24 on both sides 15/x+60/y = 1 ---------1 And 600/x +1200/y =25 Dividing by ... 720/y =9 Y=80 Put y value in A 360/x = 24-18 X=360/6 X=60 Ratio of speeds = 60:80 = 3:4

Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)

Description : You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12 ... , B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

Last Answer : Correct answer: A * 255.255.255.248,

Description : Rohit sold his bicycle at 4 % profit. If he sold it for Rs.204 less, he would have made a 30% loss. What was his cost price(in Rs.)? a)630 b)640 c)600 d)560

Last Answer : c)600 

Description : Jackson travels a distance of 100km in 5 hrs. How much faster in kilometer per hr, on an average, must he travel to make a journey in 5/3 hr less time? a) 5 km/hr b) 10km/hr c) 6 km/hr d) 8 km/hr

Last Answer : B Time required = (5 hrs – 5/3 hrs) =(5 hrs – 100 mints) = (5 hrs – 1hr 40 mints) = 3 hrs 20 mints = 3 1/3 hrs Required speed = (100*3/10) km/hr =30 km/hr Original speed = (100/5)km/hr = 20 km/hr Difference speed = required speed – original speed =(30-20) =10km/hr

Description : The summarized balance sheet of Rakesh udyog Limited shows the balances of previous and current year of provision for taxation Rs. 50,000 and Rs. 65,000. If taxed paid during the current year amounted to Rs. 70,000 then amount charge ... a) Rs. 55,000 (b) Rs. 85,000 (c) Rs. 45,000 (d) Rs. 1,85,000

Last Answer : (b) Rs. 85,000