Is KCL a restatement of the law of charge?

Is KCL a restatement of the law of charge?
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First law of thermodynamics is a restatement of which law?

Description : First law of thermodynamics is a restatement of which law?

Last Answer : Ans. Law of conservation of energy.

The first law of thermodynamics is a restatement of the law of conservation of (A) Mass (B) Energy (C) Momentum (D) None of these

Description : The first law of thermodynamics is a restatement of the law of conservation of (A) Mass (B) Energy (C) Momentum (D) None of these

Last Answer : (B) Energy

What is A restatement in ones own words of someone else's written words?

Description : What is A restatement in ones own words of someone else's written words?

Last Answer : A paraphrase, or a summary.

What is a restatement in one's own words of someone else's writtten work?

Description : What is a restatement in one's own words of someone else's writtten work?

Last Answer : It is called paraphrasing. To restate in your own words.

A restatement in ones own words of someone else’s written work?

Description : A restatement in ones own words of someone else’s written work?

Last Answer : To restate in ones own words the written work of someone else is to paraphrase.

What are the properties of KCl compound ?

Description : What are the properties of KCl compound ?

Last Answer : 1. High melting point and boiling point. 2. Soluble in polar solvent (water) but insoluble in polar solvent. 3. In solid state it remains in the form of crystals. 4. Electrically conductive in molten or dissolved state.

The decomposition of `KClO_(3)` to KCl and `O_(2)` on heating is an example of :

Description : The decomposition of `KClO_(3)` to KCl and `O_(2)` on heating is an example of :

Last Answer : The decomposition of `KClO_(3)` to KCl and `O_(2)` on heating is an example of : A ... redox change C. Disproportionation or auto redox change D. None

`CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`.

Description : `CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`.

Last Answer : `CH_(3)NH_(2)+CHCl_(3)+KOH to` Nitrogen containing compound `+KCl + H_(2)O`. A. `CH_(3)-C-=N` B. `CH_(3)-NH- ... -= C^(+)` D. `CH_(3)-N^(+)-=C^(-)`

How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii),"conc." H_(2)SO_(4) + KCl rarr),((iii),"conc." H_

Description : How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii),"conc." H_(2)SO_(4) + KCl rarr),((iii),"conc." H_

Last Answer : How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii)," ... ,((ix),"conc." H_(2)SO_(4) + Cu rarr,,):}`

How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii),"conc." H_(2)SO_(4) + KCl rarr),((iii),"conc." H_

Description : How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii),"conc." H_(2)SO_(4) + KCl rarr),((iii),"conc." H_

Last Answer : How many are redox reaction- `{:((i),K_(4)[Fe (CN)_(6)] + "conc."H_(2)SO_(4) overset(Delta)rarr,(ii)," ... ,((ix),"conc." H_(2)SO_(4) + Cu rarr,,):}`

One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`.

Description : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`.

Last Answer : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`. A. 6 B. 1 C. 7 D. 3

`NiCl_(2) overset(KCN)to "complex"A` `NiCl_(2) underset("excess") overset(KCl)to "complex"B` A & B complexes have the co-ordination number 4. The hybr

Description : `NiCl_(2) overset(KCN)to "complex"A` `NiCl_(2) underset("excess") overset(KCl)to "complex"B` A & B complexes have the co-ordination number 4. The hybr

Last Answer : `NiCl_(2) overset(KCN)to "complex"A` `NiCl_(2) underset("excess") overset(KCl)to "complex"B` A & B complexes have ... ^(2) & sp^(3)` D. both `sp^(3)`

During the electrolysis of carnallite , `MgCl_(2)` is decomposed and not KCl . This is because of :

Description : During the electrolysis of carnallite , `MgCl_(2)` is decomposed and not KCl . This is because of :

Last Answer : During the electrolysis of carnallite , `MgCl_(2)` is decomposed and not KCl . This is because of : A. lower ... both (A) and (B) D. none of the above

Carnalite is present in sea water mainly. It is the main ore of magnesium which has the chemicakl fromula `MgCl_(2).KCl.xH_(2)O` . The value of x is .

Description : Carnalite is present in sea water mainly. It is the main ore of magnesium which has the chemicakl fromula `MgCl_(2).KCl.xH_(2)O` . The value of x is .

Last Answer : Carnalite is present in sea water mainly. It is the main ore of magnesium which has the chemicakl fromula `MgCl_(2).KCl.xH_(2)O` . The value of x is .

What is the molarity of 10.0 g of KCl in 0.500 L of solution?

Description : What is the molarity of 10.0 g of KCl in 0.500 L of solution?

Last Answer : The molarity is 0,268.

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Description : What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Description : What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

How many mols in 74g of KCl?

Description : How many mols in 74g of KCl?

Last Answer : 1 mole.

Give reason for the following: (a)LiCl is more covalent than KCl. (b)LiF has lower melting point than NaCl. (c)CuCl is more covalent than NaCl.

Description : Give reason for the following: (a)LiCl is more covalent than KCl. (b)LiF has lower melting point than NaCl. (c)CuCl is more covalent than NaCl.

Last Answer : Ans(a).Due to smaller size and high poalrising power of Li+ ion ,LiCl is more covalent than KCl. (b)Small cation Li+ ion highly polarizes large anion I- , LiI is more covalent and hence has ... to pseudo inert gas configuration, Cu+ is more polarizing than Na+ and hence CuCl is more Covalent NaCl.

Which will have greater molar conductivity ? Solution containing 1 mol KCl in 200 cc or 1 mol of KCl in 500 cc.

Description : Which will have greater molar conductivity ? Solution containing 1 mol KCl in 200 cc or 1 mol of KCl in 500 cc.

Last Answer : Ans. 1 mol of KCl in 500 cc. 

Muriate of Potash is— (A) K 2 SO 4 (B) KCl (C) K 2 HPO 4 (D) KNO 3

Description : Muriate of Potash is— (A) K 2 SO 4 (B) KCl (C) K 2 HPO 4 (D) KNO 3

Last Answer : (B) KCl

A Potassic fertiliser contains 50% K2O. It could be (A) Potassium sulphate (B) Potassium chloride (C) A mixture of NaCl + KCl (D) None of these

Description : A Potassic fertiliser contains 50% K2O. It could be (A) Potassium sulphate (B) Potassium chloride (C) A mixture of NaCl + KCl (D) None of these

Last Answer : (A) Potassium sulphate

Potassic fertiliser is graded based on its __________ content. (A) KCl (B) K2O (C) KNO3 (D) K2SO4

Description : Potassic fertiliser is graded based on its __________ content. (A) KCl (B) K2O (C) KNO3 (D) K2SO4

Last Answer : (B) K2O

State KVL and KCL

Description : State KVL and KCL

Last Answer : Statement of Kirchhoff's Current Law or KCL:  In any electrical network, the algebraic sum of the currents meeting at a point or junction is zero.  (OR)  Total current entering a junction or node is exactly ... all voltages within the loop must be equal to zero.  ∑ IR + ∑ emf = 0 round a mesh

What is KCL in circuit?

Description : What is KCL in circuit?

Last Answer : Kirchhoff's Current Law which states that " The sum of the currents entering a junction is equal to the sum of the currents leaving the junctions."