Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated ... 56 mL B. 112 mL C. 168 mL D. 224 mL
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... . 0.8 g C. 4.2 g D. 0.98 g
Description : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes
Last Answer : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of ... strength of `H_(2)O_(2)` is 1.344 L
Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0
Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M
Description : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified
Last Answer : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for ... +2H_(2)O " " `(Atomic weight : As = 75)
Description : In the test for iodine, `I_(2)` is treated with sodium thiosulphate `(Na_(2)S_(2)O_(3))` : `Na_(2)S_(2)O_(3)+I_(2) to NaI +..`
Last Answer : In the test for iodine, `I_(2)` is treated with sodium thiosulphate `(Na_(2)S_(2)O_(3))` : `Na_(2)S_(2)O_(3 ... (4)` C. `Na_(2)S` D. `Na_(3)ISO_(4)`
Description : iodine is liberated from Kl solution when treated with:
Last Answer : iodine is liberated from Kl solution when treated with: A. (A) `ZnSO_4` B. (B) `CuSO_4 ` C. (C) `NiSO_4 ` D. (D) `FeSO_4`
Description : The eq. wt. of `Na_(2)S_(2)O_(3)` as reductant in the reaction, `Na_(2)S_(2)O_(3)+H_(2)O+Cl_(2)rarrNa_(2)SO_(4)+2HCl+S` is :
Last Answer : The eq. wt. of `Na_(2)S_(2)O_(3)` as reductant in the reaction, `Na_(2)S_(2)O_(3)+H_(2)O+Cl_(2)rarrNa_(2) ... wt.)/2 C. (Mol. wt.)/6 D. (Mol. wt.)/8
Description : The product of the chemical reaction between `Na_(2)S_(2)O_(3)`, `Cl_(2)` and `H_(2)O` are
Last Answer : The product of the chemical reaction between `Na_(2)S_(2)O_(3)`, `Cl_(2)` and `H_(2)O` are A. `HCl + Na_( ... + Na_(2)SO_(3)` D. `NaHClO_(3) + H_(2)O`
Description : Aqueous solution of `Na_(2)S_(2)O_(3)` on reaction with `CI_(2)`, gives
Last Answer : Aqueous solution of `Na_(2)S_(2)O_(3)` on reaction with `CI_(2)`, gives A. `Na_(2)S_(2)O_(6)` B. `NaHSO_(4)` C. `NaCl` D. `NaOH`
Description : The primary standard solution for estimation of `Na_(2)S_(2)O_(3)` is
Last Answer : The primary standard solution for estimation of `Na_(2)S_(2)O_(3)` is A. `I_(2)` solution B. `KMnO_(4)` C. `K_(2)Cr_(2)O_(7)` D. oxalic acid
Last Answer : Aqueous solution of `Na_(2)S_(2)O_(3)` on reaction with `CI_(2)`, gives A. `Na_(2)S_(4)O_(6)` B. `NaHSO_(4)` C. NaCl D. NaOH
Description : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` acidified with dilute of `H_(2)SO_(4)`. The same volu
Last Answer : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` ... calculate the molarity of `H_(2)O_(2)`.
Description : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute
Last Answer : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating ... A. `200` B. `100` C. `50` D. `25`
Description : Three different solutions of oxidising agents `KMnO_(4),K_(2)Cr_(2)O_(7) " and "I_(2)` is titrated separately with 0.158 gm of `Na_(2)S_(2)O_(3)`. If
Last Answer : Three different solutions of oxidising agents `KMnO_(4),K_(2)Cr_(2)O_(7) " and "I_(2)` is ... D. all three oxidising agent can act as self indicator.
Description : One gram of `Na_(3)AsO_(4)` is boiled with excess of solid `KI` in presence of strong `HCl`. The iodine evolved is absorbed in `KI` solution and titra
Last Answer : One gram of `Na_(3)AsO_(4)` is boiled with excess of solid `KI` in presence of strong `HCl`. The iodine evolved ... B. 38.4 mL C. 24.7 mL D. 30.3 mL
Description : Asserton :- The formal oxidation no. of sulphur in `Na_(2)S_(4)O_(6)` is `2.5` Reason :- Two S-atoms are not directly linked with O-atoms.
Last Answer : Asserton :- The formal oxidation no. of sulphur in `Na_(2)S_(4)O_(6)` is `2.5` Reason :- ... Reason is False. D. If both Assertion & Reason are False.
Description : Oxidation number of sulphur in `Na_(2)S_(2)O_(3)` is
Last Answer : Oxidation number of sulphur in `Na_(2)S_(2)O_(3)` is A. `+2` B. `+4` C. `-2` D. 0
Description : In the above reaction (in Q.99) `Na_(2)S_(2)O_(4)` acts as a
Last Answer : In the above reaction (in Q.99) `Na_(2)S_(2)O_(4)` acts as a A. 2 electron reducing ... C. 3 electron reducing agent D. 4 electron reducing agent
Description : The difference in the oxidation numbers of two types of sulphul atoms in `Na_(2)S_(4)O_(6)` is…..
Last Answer : The difference in the oxidation numbers of two types of sulphul atoms in `Na_(2)S_(4)O_(6)` is…..
Description : `Na_(2)S_(2)O_(3)` is prepared by :
Last Answer : `Na_(2)S_(2)O_(3)` is prepared by : A. reacting `H_(2)S_(2)O_(3)` with NaOH B. reacting `Na_( ... S D. reducing `Na_(2)SO_(4)` with S in acidic medium
Description : `Na_(2)S_(2)O_(3)` may react with the compounds given in coloum I. `Na_(2)S_(2)O_(3)` exhibits the properties of the type given in the coloum II, matc
Last Answer : `Na_(2)S_(2)O_(3)` may react with the compounds given in coloum I. `Na_(2)S_(2)O_(3)` exhibits the ... "),("d)",I_(2),,"s) an antichlor"):}`
Description : Statement -1 : Sodium thiosulphate is not prepared by boiling `Na_(2)SO_(3)` with S in acidic medium. Statement -2 : `Na_(2)S_(2)O_(3)+H^(+) to 2Na++H
Last Answer : Statement -1 : Sodium thiosulphate is not prepared by boiling `Na_(2)SO_(3)` with S in acidic medium. Statement ... +H^(+) to 2Na++H_(2)SO_(3)+Sdarr`
Description : `Na_(2)S_(2)O_(3)` is oxidised by `I_(2)` to
Last Answer : `Na_(2)S_(2)O_(3)` is oxidised by `I_(2)` to A. `Na_(2)S` B. `Na_(2)SO_(4)` C. `NaHSO_(3)` D. `Na_(2)S_(4)O_(6)`
Description : Select the correct statements about `Na_(2)S_(2)O_(3).5H_(2)O` :
Last Answer : Select the correct statements about `Na_(2)S_(2)O_(3).5H_(2)O` : A. It is also called as hypo B ... D. It is used to remove stains of `I_(2)`
Last Answer : Select the correct statements about `Na_(2)S_(2)O_(3).5H_(2)O` : A. It is also called as hypo B ... C. It can be used as antichlor D. All of the above
Description : The two sulphur atoms in `Na_(2)S_(2)O_(3)` have
Last Answer : The two sulphur atoms in `Na_(2)S_(2)O_(3)` have A. `-2` and `+4` oxidation states B. `+4 ... . `+6` and `-2` oxidation states D. same oxidation state
Description : The oxidation number of sulphur in `Na_(2)S_(4)O_(6)` is
Last Answer : The oxidation number of sulphur in `Na_(2)S_(4)O_(6)` is A. `-2.5` B. `+2.5` C. `-10` D. `+10`
Description : Asseration: Number of `S-S` bonds in `H_(2)S_(n)O_(6)` is (n-1). Reason: `H_(2)S_(n)O_(6)` shows `HO_(3)S-underset((n-2))(S)-SO_(3)H`
Last Answer : Asseration: Number of `S-S` bonds in `H_(2)S_(n)O_(6)` is (n-1). Reason: `H_(2)S_(n)O_(6)` shows `HO_(3)S-underset((n-2))(S)-SO_(3)H`
Description : The number of S - S bonds in polythionic acid `(H_(2)S_(n)O_(6))`
Last Answer : The number of S - S bonds in polythionic acid `(H_(2)S_(n)O_(6))` A. n B. n - 1 C. n -2 D. None of these
Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to
Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`
Description : What numbers are from Least to greatest 8.200 ML 0.005 KL 8.1 L?
Last Answer : 0.005KL, 8.1 L, 8.200 ML (ML = megalitres).
Description : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`.
Last Answer : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`. A. 6 B. 1 C. 7 D. 3
Description : A compound 'X' of the formula `C_(3)H_(8)O` gives iodoform test. On oxidation with acidified `K_(2)Cr_(2)O_(7)X` gave Y. Y also gives iodogorm test. T
Last Answer : A compound 'X' of the formula `C_(3)H_(8)O` gives iodoform test. On oxidation with acidified `K_(2)Cr_(2) ... ` D. `CH_(3)COCH_(3), CH_(3)CHOHCH_(3)`
Description : I. `H_(2)S` reduces acidified `KMnO_(4)` to `MnSO_(4)` II. `H_(2)S` reduces acidified `K_(2)Cr_(2)O_(7)` to red colour `Cr_(2)(SO_(4))_(3)` III. `H_(2
Last Answer : I. `H_(2)S` reduces acidified `KMnO_(4)` to `MnSO_(4)` II. `H_(2)S` reduces acidified `K_(2)Cr_(2) ... and III C. only II and III D. I,II,III and IV
Description : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_(2)O_(4)` solution react with o.1 mL of previous `K
Last Answer : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_( ... 15/6 mL B. 13/16 C. `11/14` D. None of these
Description : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04(M)` acidified `KMnO_(4)` solution. Which
Last Answer : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04 ... 3+)rarrZ^(4+)` D. `Z^(2+)rarrZ^(4+)`
Description : In the reaction, `I_(2)+2S_(2)O_(3)^(2-) rarr 2I^(-)+S_(4)O_(6)^(2-)`. Equivalent wieght of iodine will be equal to
Last Answer : In the reaction, `I_(2)+2S_(2)O_(3)^(2-) rarr 2I^(-)+S_(4)O_(6)^(2-)`. Equivalent wieght of iodine ... B. Mol. wt./2 C. Mol. wt./4 D. None of these
Description : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be
Last Answer : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will ... B. 1.6 g C. 3.2 g D. 0.8 g
Description : When equal weight of methyl alcohol and ehtyl alcohol react with excess of sodium metal, the volume of `H_(2)` liberated is more in the case of
Last Answer : When equal weight of methyl alcohol and ehtyl alcohol react with excess of sodium metal, the volume of `H_(2 ... in both D. `H_(2)` is not liberated
Description : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for complete neutralization"),("(B)" 4.9 g H_(3)PO_(4),"(q) 200 mi
Last Answer : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for ... Na_(2)CO_(3),"(s)May react with an oxidising agent"):}`
Description : The oxidation number of sulphur in `H_(2)S_(2)O_(8)` is:
Last Answer : The oxidation number of sulphur in `H_(2)S_(2)O_(8)` is: A. `+2` B. `+6` C. `+7` D. `+12`
Description : Assertion :- A sol of `As_(2)S_(3)` prepared by the action of `H_(2)S` on `As_(2)O_(3)` is negatively charge. Reason :- Due to adsorption of `S^(-2)`
Last Answer : Assertion :- A sol of `As_(2)S_(3)` prepared by the action of `H_(2)S` on `As_(2)O_(3) ... Reason is False. D. If both Assertion & Reason are False.
Description : Thiosulphate ion `(S_(2)O_(3)^(2-))` on acidification changes to `SO_(2)` along the precipitation of sulpur, `.^(35)S^(32) SO_(3)^(2-) + 2H^(+) to H_(
Last Answer : Thiosulphate ion `(S_(2)O_(3)^(2-))` on acidification changes to `SO_(2)` along the precipitation of sulpur, ` ... ` is in both D. `S^(35)` is in none