1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for

1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for
by

1 Answer

Answer :

1.250 g of metal carbonate `(MCO_(3))` was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl ... the metal M A. Mg B. Ca C. Sr D. Ba
by
selected by

Related questions

25 ml of the given HCl solution requires 30 mL of 0.1M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of

Description : 25 ml of the given HCl solution requires 30 mL of 0.1M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of

Last Answer : 25 ml of the given HCl solution requires 30 mL of 0.1M sodium carbonate solution. What is the volume of this HCl ... 5 mL B. 75 mL C. 50 mL D. 25 mL

A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`

The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150

What volume in mL of a 0.10 M NaOH solution would be required to neutralize 0.0091 moles of CH3COOH in a given vinegar sample?

Description : What volume in mL of a 0.10 M NaOH solution would be required to neutralize 0.0091 moles of CH3COOH in a given vinegar sample?

Last Answer : The volume of NaOH is 99 mL.

Compound (A) when reacted with PCl5 and then with ammonia gave (B). Compound (B) when treated with bromine and NaOH, produced (C). Compound (C) on treatment with NaNO2/HCl at 0°C and then boiling with H2O produced ocresol. Compound (A) is (a) o-Toluic acid (b) o-Chlorotoluene (c) m-Toluic acid (d) o-Bromotoluene

Description : Compound (A) when reacted with PCl5 and then with ammonia gave (B). Compound (B) when treated with bromine and NaOH, produced (C). Compound (C) on treatment with NaNO2/HCl at 0°C and then boiling with H2O ... Compound (A) is (a) o-Toluic acid (b) o-Chlorotoluene (c) m-Toluic acid (d) o-Bromotoluene

Last Answer : o-Toluic acid

Bauxide ore is made up of `Al_(2)O_(3) + SiO_(2) + TiO_(2) + Fe_(2) O_(3)`. This ore is treated with conc. `NaOH` solution at `500 K` and `35` bar pre

Description : Bauxide ore is made up of `Al_(2)O_(3) + SiO_(2) + TiO_(2) + Fe_(2) O_(3)`. This ore is treated with conc. `NaOH` solution at `500 K` and `35` bar pre

Last Answer : Bauxide ore is made up of `Al_(2)O_(3) + SiO_(2) + TiO_(2) + Fe_(2) O_(3)`. This ore is treated with ... `Na_(2)SiO_(3)` both D. `Na_(2)SiO_(3)` Only

Compound `A,C_(7)H_(8)O`, is insoluble in water, dilute `HCl`, and aquenous `NaHCO_(3)`, it dissolves in dilute `NaOH`. When `A` is treated with bromi

Description : Compound `A,C_(7)H_(8)O`, is insoluble in water, dilute `HCl`, and aquenous `NaHCO_(3)`, it dissolves in dilute `NaOH`. When `A` is treated with bromi

Last Answer : Compound `A,C_(7)H_(8)O`, is insoluble in water, dilute `HCl`, and aquenous `NaHCO_(3)`, it ... . o-cresol B. m-cresol C. p-cresol D. anisole

Beryllium oxide is treated separately with aqueous HCl and aqueous NaOH solutions.

Description : Beryllium oxide is treated separately with aqueous HCl and aqueous NaOH solutions.

Last Answer : Write balanced chemical equations : Beryllium oxide is treated separately with aqueous HCl and aqueous NaOH solutions.

How to prepare 250 g of 3% sodium carbonate solution? Thanks :)

Description : Could someone write me how it is calculated? Please write and calculate :)

Last Answer : I'll try, I just don't know if I'm allowed to contribute. In your case, these are weight percentages. Weight percentages indicate the number of grams of solute in 100 grams of solution. Thus: 3 g of ... water gives 250 g 3% sodium carbonate solution I don't know why I don't want to print in bold.

Mercury electrolytic cell produces 50-70% NaOH solution. Its operating temperature is __________ °C. (A) 25 (B) 60-70 (C) 150-200 (D) 250-300

Description : Mercury electrolytic cell produces 50-70% NaOH solution. Its operating temperature is __________ °C. (A) 25 (B) 60-70 (C) 150-200 (D) 250-300

Last Answer : (B) 60-70

Benzoic acid and diphenyl ketone are both solids insoluble in water. A mixture of these compounds can be separated if we (a) add the mixture to a solution of NaOH in water, and filter. (b) add the mixture to a solution of HCl in water, and filter. (c) dissolve the mixture in benzene and boil off the benzene. (d) It is impossible to separate a mixture of two solids when both are insoluble in water.

Description : Benzoic acid and diphenyl ketone are both solids insoluble in water. A mixture of these compounds can be separated if we (a) add the mixture to a solution of NaOH in water, and filter. (b) add ... benzene. (d) It is impossible to separate a mixture of two solids when both are insoluble in water.

Last Answer : add the mixture to a solution of NaOH in water, and filter

What Mass Of Calcium Carbonate Is Needed For Complete Reaction With The HCl In 2HCl(aq) plus CaCO 3 (s) CaCl 2 (aq) plus H 2 O(l) plus CO 2 (g)?

Description : What Mass Of Calcium Carbonate Is Needed For Complete Reaction With The HCl In 2HCl(aq) plus CaCO 3 (s) CaCl 2 (aq) plus H 2 O(l) plus CO 2 (g)?

Last Answer : Need answer

For the just coagultion of 250 mL of `Fe(OH)_(3)` sol, 2 mL of `1 M Na_(2)SO_(4)` electrolyte is required. What is the coagulating value of `Na_(2)SO_

Description : For the just coagultion of 250 mL of `Fe(OH)_(3)` sol, 2 mL of `1 M Na_(2)SO_(4)` electrolyte is required. What is the coagulating value of `Na_(2)SO_

Last Answer : For the just coagultion of 250 mL of `Fe(OH)_(3)` sol, 2 mL of `1 M Na_(2)SO_(4)` ... What is the coagulating value of `Na_(2)SO_(4)` electrolyte.

The maximum permissible chloride content in treated water of public water supplies should not exceed (A) 50 P.P.M. (B) 100 P.P.M. (C) 150 P.P.M. (D) 250 P.P.M.

Description : The maximum permissible chloride content in treated water of public water supplies should not exceed (A) 50 P.P.M. (B) 100 P.P.M. (C) 150 P.P.M. (D) 250 P.P.M.

Last Answer : (D) 250 P.P.M.

HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Description : HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Last Answer : Dissolve 6 g dry sodium hydroxide in 200 mL water.

The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Description : The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Last Answer : 400 mL(Explanation): again boyle's law PV=PV. Since the pressure is halved (500 to 250), then the volume must be doubled in order to maintain this equation. 200 x2=400 so that's the answer

The amount of air breathed in and out in a single quiet respiration is about (a) 250 ml (b) 500 ml (c) 750 ml (d) 1000 ml

Description : The amount of air breathed in and out in a single quiet respiration is about (a) 250 ml (b) 500 ml (c) 750 ml (d) 1000 ml

Last Answer : Ans:(d)

100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the solution after adsorption is 0.125 M. Th

Description : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the solution after adsorption is 0.125 M. Th

Last Answer : 100 mL of 0.3 M acetic acid is shaken with 0.8 g wood charcoal. The final concentration of acetic acid in the ... g` C. `1.31 g` D. `0.131 g`

What is the recommended minimum range of illumination required by BS EN 970 for inspection of a welded surface? a) 90 to 125 lux b) 150 to 250 lux c) 350 to 500 lux d) 35 to 50 lux

Description : What is the recommended minimum range of illumination required by BS EN 970 for inspection of a welded surface? a) 90 to 125 lux b) 150 to 250 lux c) 350 to 500 lux d) 35 to 50 lux

Last Answer : c) 350 to 500 lux

2 ml each of concentrated HCl, HNO3 and a mixture of concentrated hydrochloric acid and Concentrated nitric acid in the ratio of 3:1were taken in test tubes labelled as A, B and C, A small piece of metal was put in each test tube. No change occurred in test tubes A and B but the metal dissolved in test tube C. The metal could be: A) Al B) Au C) Pt D) Cu

Description : 2 ml each of concentrated HCl, HNO3 and a mixture of concentrated hydrochloric acid and Concentrated nitric acid in the ratio of 3:1were taken in test tubes labelled as A, B and C, A small piece of metal was put in ... the metal dissolved in test tube C. The metal could be: A) Al B) Au C) Pt D) Cu

Last Answer : B) Au

Number of equivalents of HCl present in 100 mL of its solution whose pH is 4:

Description : Number of equivalents of HCl present in 100 mL of its solution whose pH is 4:

Last Answer : Number of equivalents of HCl present in 100 mL of its solution whose pH is 4: A. `10^(-4)` B. `10^(-3)` C. `10^(-2)` D. `10^(-5)`

`25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04(M)` acidified `KMnO_(4)` solution. Which

Description : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04(M)` acidified `KMnO_(4)` solution. Which

Last Answer : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04 ... 3+)rarrZ^(4+)` D. `Z^(2+)rarrZ^(4+)`

What is the molarity of 5.60 mol of sodium carbonate in 1500 ml of solution?

Description : What is the molarity of 5.60 mol of sodium carbonate in 1500 ml of solution?

Last Answer : Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...

When formaldehyde is treated with 50% NaOH solution, it undergoes (a) Cannizzaro reaction (b) Wurtz reaction (c) Aldol condensation (d) Hydrolysis

Description : When formaldehyde is treated with 50% NaOH solution, it undergoes (a) Cannizzaro reaction (b) Wurtz reaction (c) Aldol condensation (d) Hydrolysis

Last Answer : Cannizzaro reaction

If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic medium is x g and to neutralise 100 mL of

Description : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic medium is x g and to neutralise 100 mL of

Last Answer : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic ... y is 1g D. If x is 11g then y is 5.5g

25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M

`50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium sulphite. The half reaction for the oxidation of sulphite ion

Description : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium sulphite. The half reaction for the oxidation of sulphite ion

Last Answer : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium ... was `3`, what would be the new oxidation number of metal:

25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu

Description : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu

Last Answer : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_ ... is the molarity of the `Fe^(2+)` solution ?

How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.

Description : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.

Last Answer : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.

A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the solution In which (C) contains oxygen. The mixture

Description : A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the solution In which (C) contains oxygen. The mixture

Last Answer : A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the ... ) into red colour compound D. (D) All of these

A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the solution in which (C) contains oxygen. The mixture

Description : A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the solution in which (C) contains oxygen. The mixture

Last Answer : A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the solution ... (A) and (B) both D. (D) None of these

A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the solution In which (C) contains oxygen. The mixture

Description : A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in the solution In which (C) contains oxygen. The mixture

Last Answer : A red liquid (A) when treated with sodium carbonate gives a mixture of two sails (B) and (C) in ... orange red spots on starch paper D. (D) None

The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst(NaNO_(2)//HCl)underset(ul(" "0-5^(

Description : The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst(NaNO_(2)//HCl)underset(ul(" "0-5^(

Last Answer : The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst( ... 5^(@)C" "))toB` A. B. C. D.

Take a 250 mL beaker/glass tumbler. Fill half of it with water. Now carefully cut a small piece of sodium metal. Dry it using filter paper and wrap it in a small piece of cotton. Put the sodium piece wrapped in cotton into the beaker. Observe carefully. -Science

Description : Take a 250 mL beaker/glass tumbler. Fill half of it with water. Now carefully cut a small piece of sodium metal. Dry it using filter paper and wrap it in a small piece of cotton. Put the sodium piece wrapped in cotton into the beaker. Observe carefully. -Science

Last Answer : On touching the beaker, it was felt hot. The solution turns the red litmus paper to blue which shows it is basic in nature. Blue litmus paper do not show any colour change with the solution.

Extra widening required at a horizontal curve on a single lane hill road of radius 80 m for a design speed of 50 km ph and for a vehicle with wheel base 6.0 m is (A) 0.225 m (B) 0.589 m (C) 1.250 m (D) None of these

Description : Extra widening required at a horizontal curve on a single lane hill road of radius 80 m for a design speed of 50 km ph and for a vehicle with wheel base 6.0 m is (A) 0.225 m (B) 0.589 m (C) 1.250 m (D) None of these

Last Answer : Answer: Option B

The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-

Description : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-

Last Answer : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1 ... ))` D. `m = (1000M)/(1000rho -MM_(1))`

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Description : What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Description : What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?

Last Answer : moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml= 0.25 Lmolarity = moles/liter = 1.34 moles/0.25 L = 5.37 MSince KCl dissociates completely into K+ and Cl-, you have 5.37M of each = total of 10.74 osmolar

A 100 mL sample of water was treated to convert any iron present to `Fe^(2+)`. Addition of 25 mL of 0.002 M `K_(2)Cr_(2)O_(7)` resulted in the reactio

Description : A 100 mL sample of water was treated to convert any iron present to `Fe^(2+)`. Addition of 25 mL of 0.002 M `K_(2)Cr_(2)O_(7)` resulted in the reactio

Last Answer : A 100 mL sample of water was treated to convert any iron present to `Fe^(2+)`. Addition of 25 ... parts per million (ppm) of iron in the water sample.

Potassium content of muscle tissue in mg/100 ml is about (A) 50–100 (B) 100–150 (C) 250–400 (D) 150–200

Description : Potassium content of muscle tissue in mg/100 ml is about (A) 50–100 (B) 100–150 (C) 250–400 (D) 150–200

Last Answer : Answer : C

The total serum testosterone in adult men is (A) 50–100 ng/100 ml (B) 150–250 ng/100 ml (C) 300–1000 ng/100 ml (D) 1000–3000 ng/100 ml

Description : The total serum testosterone in adult men is (A) 50–100 ng/100 ml (B) 150–250 ng/100 ml (C) 300–1000 ng/100 ml (D) 1000–3000 ng/100 ml

Last Answer : Answer : C

If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l

Description : If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l

Last Answer : ANS: D

A drug (200 mg dose) administered in tablet form and as intravenous injection (50 mg dose) showed AUG of 100 and 200 microgram hr/mL, respectively. The absolute availability of the drug through oral administration is : (A) 125% (B) 250 % (C) 12.5% (D) 1.25%

Description : A drug (200 mg dose) administered in tablet form and as intravenous injection (50 mg dose) showed AUG of 100 and 200 microgram hr/mL, respectively. The absolute availability of the drug through oral administration is : (A) 125% (B) 250 % (C) 12.5% (D) 1.25%

Last Answer : (C) 12.5%

Perday secretion of bile juice is (a) 50 ml. (b) 100 ml. (c) 250 ml (d) 600 ml

Description : Perday secretion of bile juice is (a) 50 ml. (b) 100 ml. (c) 250 ml (d) 600 ml

Last Answer : (d) 600 ml

The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is:

Description : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is:

Last Answer : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is: A. 1.65 kg B. 1.4 kg C. 16.5 kg D. 140 kg

For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute

Description : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute

Last Answer : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating ... A. `200` B. `100` C. `50` D. `25`

The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

Description : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

Last Answer : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

60-year-old patient with creatinine clearance 50 ml/min has to be treated with gentamicin. His daily dose of gentamicin should be reduced to the following percentage of the usual adult dose: A. 70% B. 50% C. 40% D. 30%

Description : 60-year-old patient with creatinine clearance 50 ml/min has to be treated with gentamicin. His daily dose of gentamicin should be reduced to the following percentage of the usual adult dose: A. 70% B. 50% C. 40% D. 30%

Last Answer : B. 50%

A 60-year-old patient with creatinine clearance 50 ml/min has to be treated with gentamicin. His daily dose of gentamicin should be reduced to the following percentage of the usual adult dose: A. 70% B. 50% C. 40% D. 30%

Description : A 60-year-old patient with creatinine clearance 50 ml/min has to be treated with gentamicin. His daily dose of gentamicin should be reduced to the following percentage of the usual adult dose: A. 70% B. 50% C. 40% D. 30%

Last Answer : B. 50%

A patient of liver cirrhosis with ascitis was treated with hydrochlorothiazide 50 mg twice daily. He responded initially, but over a couple of months the diuretic action gradually diminished and ascitis again appeared. Select the measure to reinduce diuresis: A. Increase hydrochlorothiazide dose to 100 mg twice daily B. Add acetazolamide 250 mg twice daily C. Add spironolactone 50 mg thrice daily D. Substitute hydrochlorothiazide by spironolactone 50 mg 6 hourly

Description : A patient of liver cirrhosis with ascitis was treated with hydrochlorothiazide 50 mg twice daily. He responded initially, but over a couple of months the diuretic action gradually diminished ... Add spironolactone 50 mg thrice daily D. Substitute hydrochlorothiazide by spironolactone 50 mg 6 hourly

Last Answer : C. Add spironolactone 50 mg thrice daily