Description : `int(1)/(2x^(2)+5x+3)dx`
Last Answer : `int(1)/(2x^(2)+5x+3)dx`
Description : Evaluate: (i) `int(e^(sqrt(x))cos(e^(sqrt(x))))/(sqrt(x)) dx` (ii) `int(cos^5x)/(sinx) dx`
Last Answer : Evaluate: (i) `int(e^(sqrt(x))cos(e^(sqrt(x))))/(sqrt(x)) dx` (ii) `int(cos^5x)/(sinx) dx`
Description : `int{ 5a^(x)+ 6a cos (5x +1)}dx`
Last Answer : `int{ 5a^(x)+ 6a cos (5x +1)}dx`
Description : `(i) int(1)/(5x+1)dx " "(ii)int(1)/(sqrt(x+1+)sqrt(x))dx`
Last Answer : `(i) int(1)/(5x+1)dx " "(ii)int(1)/(sqrt(x+1+)sqrt(x))dx`
Description : `" if " int (sin 2x- cos 2x) dx=(1)/(sqrt(2)) sin (2x-k)+c " then " k=?`
Last Answer : `" if " int (sin 2x- cos 2x) dx=(1)/(sqrt(2)) sin (2x-k)+c " then " k=?` A. `-(5pi)/(4)` B. `(pi)/(4)` C. `-(pi)/(4)` D.
Description : `int(x^(2)+1)/(x^(4)-2x^(2)+1)dx`
Last Answer : `int(x^(2)+1)/(x^(4)-2x^(2)+1)dx`
Description : `int(2x+5)/(sqrt(x^(2)+3x+1))dx`
Last Answer : `int(2x+5)/(sqrt(x^(2)+3x+1))dx`
Description : `int(x+1)/(sqrt(2x^(2)+x-3))dx`
Last Answer : `int(x+1)/(sqrt(2x^(2)+x-3))dx`
Description : Evaluate: `int(2x+5)/(sqrt(x^2+2x+5)) dx`
Last Answer : Evaluate: `int(2x+5)/(sqrt(x^2+2x+5)) dx`
Description : Evaluate: `int(2x-5)sqrt(2+3x-x^2)dx`
Last Answer : Evaluate: `int(2x-5)sqrt(2+3x-x^2)dx`
Description : `int (e^(x)dx)/(e^(2x)+4e^(x)+3)`
Last Answer : `int (e^(x)dx)/(e^(2x)+4e^(x)+3)`
Description : `int(3x+1)/(2x^(2)+x-1)dx`
Last Answer : `int(3x+1)/(2x^(2)+x-1)dx`
Description : `int(1)/(2x^(2)+x+1)dx`
Last Answer : `int(1)/(2x^(2)+x+1)dx`
Description : `int (x)/(x^(2)+2x+1)dx`
Last Answer : `int (x)/(x^(2)+2x+1)dx`
Description : `int (2x+3)/((x+2)(x-2))dx`
Last Answer : `int (2x+3)/((x+2)(x-2))dx`
Description : Evaluate : `int(2x-3)/(x^2+ 3x-18) dx`
Last Answer : Evaluate : `int(2x-3)/(x^2+ 3x-18) dx`
Description : `int e^(2x) " (tan x+1)"^(2) dx`
Last Answer : `int e^(2x) " (tan x+1)"^(2) dx`
Description : `int e^(" sin x "). " sin 2x dx "`
Last Answer : `int e^(" sin x "). " sin 2x dx "`
Description : `(i) int " x sec"^(2) " 2x dx "" "(ii) int " x sin"^(3) " x dx "`
Last Answer : `(i) int " x sec"^(2) " 2x dx "" "(ii) int " x sin"^(3) " x dx "`
Description : Evaluate: (i) `int(e^x)/(sqrt(4-e^(2x))) dx` (ii) `int(x^2)/(sqrt(1-x^6)) dx`
Last Answer : Evaluate: (i) `int(e^x)/(sqrt(4-e^(2x))) dx` (ii) `int(x^2)/(sqrt(1-x^6)) dx`
Description : `int(sin 2x)/(5-cos^(2) x)dx`
Last Answer : `int(sin 2x)/(5-cos^(2) x)dx`
Description : `int(2x^(3))/((x^(2)+1)^(2))dx`
Last Answer : `int(2x^(3))/((x^(2)+1)^(2))dx`
Description : `int(2x-1)/(sqrt(x^(2)-x-1))dx`
Last Answer : `int(2x-1)/(sqrt(x^(2)-x-1))dx`
Description : Evaluate: (i) `int(sinx)/(1+cos^2x) dx` (ii) `int(2x^3)/(4+x^8) dx`
Last Answer : Evaluate: (i) `int(sinx)/(1+cos^2x) dx` (ii) `int(2x^3)/(4+x^8) dx`
Description : `int (x^(2))/(1-2x^(3))dx`
Last Answer : `int (x^(2))/(1-2x^(3))dx`
Description : `(i) int sin 2x. cos5x dx " "(ii) int(sin 4x)/(sin x) dx`
Last Answer : `(i) int sin 2x. cos5x dx " "(ii) int(sin 4x)/(sin x) dx`
Description : `int (x^(2) +2x -5)/(sqrt(x))dx`
Last Answer : `int (x^(2) +2x -5)/(sqrt(x))dx`
Description : `int((x+1)(2x-3))/(x) dx`
Last Answer : `int((x+1)(2x-3))/(x) dx`
Description : Suppose that we have numbers between 1 and 1000 in a binary search tree and want to search for the number 364. Which of the following sequences could not be the sequence of nodes examined? (A) 925, 221, 912, 245, 899, ... 926, 203, 912, 241, 913, 246, 364 (D) 3, 253, 402, 399, 331, 345, 398, 364
Last Answer : (C) 926, 203, 912, 241, 913, 246, 364
Description : `int (e^(2x)-1)/(e^(2x)+1) dx=?`
Last Answer : `int (e^(2x)-1)/(e^(2x)+1) dx=?` A. `log(1+e^(-2x))+c` B. `log (e^(x) -e^(-x)) +c` C. `log (e^(x)+e^(-x))+c` D.
Description : `int(1)/(sqrt(2x^(2)+3x-2))dx`
Last Answer : `int(1)/(sqrt(2x^(2)+3x-2))dx`
Description : `int(2x-1)/(2x^2+2x+1)dx`
Last Answer : `int(2x-1)/(2x^2+2x+1)dx`
Description : `int(4x-3)/(3x^2+2x-5)dx`
Last Answer : `int(4x-3)/(3x^2+2x-5)dx`
Description : `int(1)/(2x^(2)-4x+1)dx`
Last Answer : `int(1)/(2x^(2)-4x+1)dx`
Description : `int (2x-sin 2x)/(1-cos 2x) dx`
Last Answer : `int (2x-sin 2x)/(1-cos 2x) dx`
Description : Evaluate `int e^(2x) sin 3x dx`.
Last Answer : Evaluate `int e^(2x) sin 3x dx`.
Description : `int e^(3x) " cos 2x dx "`
Last Answer : `int e^(3x) " cos 2x dx "`
Description : `int(1)/(sqrt(1+cos 2x))dx`
Last Answer : `int(1)/(sqrt(1+cos 2x))dx`
Description : `int" cos"^(4) " 2x dx "`
Last Answer : `int" cos"^(4) " 2x dx "`
Description : `int cos 2x . cos 4x . cos 6x dx`
Last Answer : `int cos 2x . cos 4x . cos 6x dx`
Description : `int " cosec"^(4) 2x dx`
Last Answer : `int " cosec"^(4) 2x dx`
Description : `int sqrt(2x-1) dx`
Last Answer : `int sqrt(2x-1) dx`
Description : `int cos 4x. cos 2x dx`
Last Answer : `int cos 4x. cos 2x dx`
Description : `int cos (2x +1) dx`
Last Answer : `int cos (2x +1) dx`
Description : `int(1+cos 2x)/(1-cos 2x)dx`
Last Answer : `int(1+cos 2x)/(1-cos 2x)dx`
Description : `int(1)/(1-cos 2x) dx`
Last Answer : `int(1)/(1-cos 2x) dx`
Description : `int(1)/( 1+cos 2x ) dx`
Last Answer : `int(1)/( 1+cos 2x ) dx`
Description : If the expressions (px^3 + 3x^2 – 3) and (2x^3 – 5x + p) when divided by (x – 4) leave the same remainder, then what is the value of p ? -Maths 9th
Last Answer : Given that the following polynomials leave the same remainder when divided by (x - 4) : We are to find the value of a. Remainder theorem: When (x - b) divides a polynomial p(x), then the remainder is p(b). So, from (i) and (ii), we get Thus, the required value of a is 1.
Description : If x^3 + 5x^2 + 10k leaves remainder – 2x when divided by x^2 + 2, then what is the value of k ? -Maths 9th
Last Answer : x3+5x2+10k =(x2+2)(x+5)+10k−2x−10 ⇒10k−2x−10=−2x ⇒10k−10=0 or k=1.