The A/D converter whose conversion time is independent of the number of bits is (A) Dual slope (B) Counter type (C) Parallel conversion (D) Successive approximation.

The A/D converter whose conversion time is independent of the number of bits is
 (A) Dual slope (B) Counter type
 (C) Parallel conversion (D) Successive approximation.
by

1 Answer

Answer :

Ans: C
 The A/D converter whose conversion time is independent of the Number of bits is
Parallel conversion.
(This type uses an array of comparators connected in parallel and comparators compare
the input voltage at a particular ratio of the reference voltage).
by

Related questions

The speed of conversion is maximum in (A) Successive-approximation A/D converter. (B) Parallel-comparative A/D converter. (C) Counter ramp A/D converter. (D) Dual-slope A/D converter.

Description : The speed of conversion is maximum in (A) Successive-approximation A/D converter. (B) Parallel-comparative A/D converter. (C) Counter ramp A/D converter. (D) Dual-slope A/D converter.

Last Answer : Ans: B The speed of conversion is maximum in Parallel-comparator A/D converter (Speed of conversion is maximum because the comparisons of the input voltage are carried out simultaneously.)

The conversation speed of an analog to digital converter is maximum with the following technique. (A) Dual slope AD converter. (B) Serial comparator AD converter. (C) Successive approximation AD converter. (D) Parallel comparator AD converter.

Description : The conversation speed of an analog to digital converter is maximum with the following technique. (A) Dual slope AD converter. (B) Serial comparator AD converter. (C) Successive approximation AD converter. (D) Parallel comparator AD converter.

Last Answer : (D) Parallel comparator AD converter.

In successive-approximation A/D converter, offset voltage equal to 1/2 LSB is added to the D/A converter’s output. This is done to (A) Improve the speed of operation. (B) Reduce the maximum quantization error. (C) Increase the number of bits at the output. (D) Increase the range of input voltage that can be converted

Description : In successive-approximation A/D converter, offset voltage equal to 1/2 LSB is added to the D/A converter's output. This is done to (A) Improve the speed of operation. (B) Reduce the maximum ... Increase the number of bits at the output. (D) Increase the range of input voltage that can be converted

Last Answer : (B) Reduce the maximum quantization error.

The conversion time of a 12 bit successive approximation A/D converter using a 1 MHz clock is

Last Answer : The conversion time of a 12 bit successive approximation A/D converter using a 1 MHz clock is 12μs.

A weighted resistor digital to analog converter using N bits requires a total of (A) N precision resistors. (B) 2N precision resistors. (C) N + 1 precision resistors. (D) N – 1 precision resistors.

Description : A weighted resistor digital to analog converter using N bits requires a total of (A) N precision resistors. (B) 2N precision resistors. (C) N + 1 precision resistors. (D) N – 1 precision resistors.

Last Answer : (A) N precision resistors.

In successive approximation converter input to the comparator is through

Description : In successive approximation converter input to the comparator is through (A) DAC (B) Latch (C) Flip-flop (D) Sample and hold circuit

Last Answer : In successive approximation converter input to the comparator is through DAC 

For a certain 4 bit successive approximation A/D converter, the maximum ...

Last Answer : For a certain 4 bit successive approximation A/D converter, the maximum ladder output is +8V. if a constant +6V is applied to the analog input the sequence of binary states for the SA register is 0110.

The device which changes from serial data to parallel data is (A) COUNTER (B) MULTIPLEXER (C) DEMULTIPLEXER (D) FLIP-FLOP

Description : The device which changes from serial data to parallel data is (A) COUNTER (B) MULTIPLEXER (C) DEMULTIPLEXER (D) FLIP-FLOP

Last Answer : Ans: C The device which changes from serial data to parallel data is demultiplexer. (A demultiplexer takes in data from one line and directs it to any of its N outputs depending on the status of the select inputs.)

The code where all successive numbers differ from their preceding number by single bit is (A) Binary code. (B) BCD. (C) Excess – 3. (D) Gray.

Description : The code where all successive numbers differ from their preceding number by single bit is (A) Binary code. (B) BCD. (C) Excess – 3. (D) Gray.

Last Answer : Ans: D The code where all successive numbers differ from their preceding number by single bit is Gray Code. (It is an unweighted code. The most important characteristic of this code is that only a single bit change occurs when going from one code number to next.)

The MSI chip 7474 is (A) Dual edge triggered JK flip-flop (TTL). (B) Dual edge triggered D flip-flop (CMOS). (C) Dual edge triggered D flip-flop (TTL). (D) Dual edge triggered JK flip-flop (CMOS).

Description : The MSI chip 7474 is (A) Dual edge triggered JK flip-flop (TTL). (B) Dual edge triggered D flip-flop (CMOS). (C) Dual edge triggered D flip-flop (TTL). (D) Dual edge triggered JK flip-flop (CMOS).

Last Answer : Ans: C MSI chip 7474 dual edge triggered D Flip-Flop.

Which of the following memories stores the most number of bits (A) a 5M×8 memory. (B) a 1M × 16 memory. (C) a 5M × 4 memory. (D) a 1M ×12 memory.

Description : Which of the following memories stores the most number of bits (A) a 5M×8 memory. (B) a 1M × 16 memory. (C) a 5M × 4 memory. (D) a 1M ×12 memory.

Last Answer : Ans: A 5Mx8 = 5 x 220 x 8 = 40M (max)

Words having 8-bits are to be stored into computer memory. The number of lines required for writing into memory are (A) 1. (B) 2. (C) 4. (D) 8.

Description : Words having 8-bits are to be stored into computer memory. The number of lines required for writing into memory are (A) 1. (B) 2. (C) 4. (D) 8.

Last Answer : Ans: D Because 8-bit words required 8 bit data lines.

How many address bits are required to represent 4K memory (A) 5 bits. (B) 12 bits. (C) 8 bits. (D) 10 bits.

Description : How many address bits are required to represent 4K memory (A) 5 bits. (B) 12 bits. (C) 8 bits. (D) 10 bits.

Last Answer : (B) 12 bits.

How many address bits are required to represent a 32 K memory (A) 10 bits. (B) 12 bits. (C) 14 bits. (D) 16 bits.

Description : How many address bits are required to represent a 32 K memory (A) 10 bits. (B) 12 bits. (C) 14 bits. (D) 16 bits.

Last Answer : (D) 16 bits.

A 4-bit synchronous counter uses flip-flops with propagation delay times of 15 ns each. The maximum possible time required for change of state will be (A) 15 ns. (B) 30 ns. (C) 45 ns. (D) 60 ns.

Description : A 4-bit synchronous counter uses flip-flops with propagation delay times of 15 ns each. The maximum possible time required for change of state will be (A) 15 ns. (B) 30 ns. (C) 45 ns. (D) 60 ns.

Last Answer : Ans: A 15 ns because in synchronous counter all the flip-flops change state at the same time.

An eight stage ripple counter uses a flip-flop with propagation delay of 75 nanoseconds. The pulse width of the strobe is 50ns. The frequency of the input signal which can be used for proper operation of the counter is approximately (A) 1 MHz. (B) 500 MHz. (C) 2 MHz. (D) 4 MHz.

Description : An eight stage ripple counter uses a flip-flop with propagation delay of 75 nanoseconds. The pulse width of the strobe is 50ns. The frequency of the input signal which can be used for proper operation of the counter is approximately (A) 1 MHz. (B) 500 MHz. (C) 2 MHz. (D) 4 MHz.

Last Answer : Maximum time taken for all flip-flops to stabilize is 75ns x 8 + 50 = 650ns. Frequency of operation must be less than 1/650ns = 1.5 MHz.

How many flip-flops are required to construct mod 30 counter (A) 5 (B) 6 (C) 4 (D) 8

Description : How many flip-flops are required to construct mod 30 counter (A) 5 (B) 6 (C) 4 (D) 8

Last Answer : (A) 5

How many flip flops are required to construct a decade counter (A) 10 (B) 3 (C) 4 (D) 2

Description : How many flip flops are required to construct a decade counter (A) 10 (B) 3 (C) 4 (D) 2

Last Answer : Ans: C Decade counter counts 10 states from 0 to 9 ( i.e. from 0000 to 1001 ) Thus four FlipFlop's are required.

A ring counter consisting of five Flip-Flops will have (A) 5 states (B) 10 states (C) 32 states (D) Infinite states.

Description : A ring counter consisting of five Flip-Flops will have (A) 5 states (B) 10 states (C) 32 states (D) Infinite states.

Last Answer : Ans: A A ring counter consisting of Five Flip-Flops will have 5 states.

How many Flip-Flops are required for mod–16 counter? (A) 5 (B) 6 (C) 3 (D) 4

Description : How many Flip-Flops are required for mod–16 counter? (A) 5 (B) 6 (C) 3 (D) 4

Last Answer : (D) 4

Where are the successive approximation type ADC’s used?

Description : Where are the successive approximation type ADC’s used?

Last Answer : The Successive approximation ADCs are used in applications such as data loggers & instrumentation where conversion speed is important.

A 12 bit counter type A/D converter uses a 1 MHz clock. Its maximum conversion time is

Last Answer : A 12 bit counter type A/D converter uses a 1 MHz clock. Its maximum conversion time is 4096μs.

Where can I find the detailed information about Successive Approximation method and discrete newton method？?

Description : Where can I find the detailed information about Successive Approximation method and discrete newton method？?

Last Answer : answer:A DISCRETE NEWTON ALGORITHM FOR MINIMIZING A FUNCTION OF MANY VARIABLES SUCCESSIVE APPROXIMATIONS

Explain in brief the principle of operation of successive Approximation ADC.

Description : Explain in brief the principle of operation of successive Approximation ADC.

Last Answer : The circuit of successive approximation ADC consists of a successive approximation register (SAR), to find the required value of each bit by trial & error.With the arrival of START command, SAR sets the MSB ... /P signal. This O/P is low or High. This process continues until all bits are checked.

Draw block diagram of successive approximation digital voltmeter. State its two advantages and two disadvantages

Description : Draw block diagram of successive approximation digital voltmeter. State its two advantages and two disadvantages

Last Answer : Block diagram Or Advantages: o It is economical method of analog to digital conversion. o The resolution is up to 5 important digits are obtained. Disadvantages: o ... depends on which type of switches are used. o The conversion time required for digital to analog converter.

Successive approximation technique is used for

Description : Successive approximation technique is used for

Last Answer : Successive approximation technique is used for A to D Conversion

Classification of protocol that interprets a frame of data as a group of successive bit combined into predetermined pattern of fixed length, usually 8 bits each.

Description : Classification of protocol that interprets a frame of data as a group of successive bit combined into predetermined pattern of fixed length, usually 8 bits each.

Last Answer : Character and Byte-oriented protocols

What are the different types of shift type?

Description : What are the different types of shift type?

Last Answer : There are five types. They are, Serial In Serial Out Shift Register Serial In Parallel Out Shift Register Parallel In Serial Out Shift Register Parallel In Parallel Out Shift Register Bidirectional Shift Register

Contour interval on a map sheet denotes (a) Vertical distance of contour lines above the datum plane (b) Vertical distance between two successive contour lines (c) Slope distance between two successive contour lines (d) Horizontal distance between two successive contour lines

Description : Contour interval on a map sheet denotes (a) Vertical distance of contour lines above the datum plane (b) Vertical distance between two successive contour lines (c) Slope distance between two successive contour lines (d) Horizontal distance between two successive contour lines

Last Answer : (b) Vertical distance between two successive contour lines

Convert the decimal number 3.375 to binary. 132) A) 0101.1100 B) 0011.1010 C) 0011.0011 D) 0011.01

Description : Convert the decimal number 3.375 to binary. 132) A) 0101.1100 B) 0011.1010 C) 0011.0011 D) 0011.01

Last Answer : D) 0011.01

Any number with an exponent of one is equal to 128) A) two. B) itself. C) zero. D) on

Description : Any number with an exponent of one is equal to 128) A) two. B) itself. C) zero. D) on

Last Answer : B) itself.

Convert the binary number 0001.0010 to decimal. 121) A) 1.20 B) 1.40 C) 1.125 D)

Description : Convert the binary number 0001.0010 to decimal. 121) A) 1.20 B) 1.40 C) 1.125 D)

Last Answer : C) 1.125

How many different symbols are used in the octal number system? 108) A) ten B) two C) seven D) eight

Description : How many different symbols are used in the octal number system? 108) A) ten B) two C) seven D) eight

Last Answer : D) eight

Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Description : Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Last Answer : B) 18.25

Convert the decimal number 0.0625 to binary. 100) A) 0000.0111 B) 0000.1110 C) 0000.0011 D) 0000.0001

Description : Convert the decimal number 0.0625 to binary. 100) A) 0000.0111 B) 0000.1110 C) 0000.0011 D) 0000.0001

Last Answer : D) 0000.0001

Which numbering formats are really codes rather than true number systems? 96) A) hexadecimal and octal B) binary and octal C) decimal and binary D) BCD and ASCII

Description : Which numbering formats are really codes rather than true number systems? 96) A) hexadecimal and octal B) binary and octal C) decimal and binary D) BCD and ASCII

Last Answer : Which numbering formats are really codes rather than true number systems?

Convert the decimal number 10.5 to binary. 92) A) 1100.1000 B) 1010.0101 C) 1010.1000 D) 1011.1000

Description : Convert the decimal number 10.5 to binary. 92) A) 1100.1000 B) 1010.0101 C) 1010.1000 D) 1011.1000

Last Answer : C) 1010.1000

Convert the decimal number 14.875 to binary. 87) A) 1110.0111 B) 1110.1110 C) 1111.1011 D) 1100.1100

Description : Convert the decimal number 14.875 to binary. 87) A) 1110.0111 B) 1110.1110 C) 1111.1011 D) 1100.1100

Last Answer : B) 1110.1110

What numeric symbols are used in the binary number system? 58) A) 0 through 8 B) 0, 1, 2 C) 1, 2 D) 0, 1

Description : What numeric symbols are used in the binary number system? 58) A) 0 through 8 B) 0, 1, 2 C) 1, 2 D) 0, 1

Last Answer : D) 0, 1

How many unique numeric symbols are used in the decimal number system? 47) A) unlimited B) nine C) one D) ten

Description : How many unique numeric symbols are used in the decimal number system? 47) A) unlimited B) nine C) one D) ten

Last Answer : D) ten

How many symbols are used in the hexadecimal number system? 15) A) sixteen B) six C) ten D) twelve

Description : How many symbols are used in the hexadecimal number system? 15) A) sixteen B) six C) ten D) twelve

Last Answer : A) sixteen

Convert the decimal number 6.75 to binary. 14) A) 0110.1100 B) 0111.1100 C) 0110.0110 D) 0110.1010

Description : Convert the decimal number 6.75 to binary. 14) A) 0110.1100 B) 0111.1100 C) 0110.0110 D) 0110.1010

Last Answer : A) 0110.1100

Convert the decimal number 12.125 to binary. 12) A) 1100.0110 B) 1110.0010 C) 1100.0010 D) 1010.1100

Description : Convert the decimal number 12.125 to binary. 12) A) 1100.0110 B) 1110.0010 C) 1100.0010 D) 1010.1100

Last Answer : C) 1100.0010

Convert the binary number 0000.1010 to decimal. 6) A) 0.10 B) 0.55 C) 0.50 D) 0.625

Description : Convert the binary number 0000.1010 to decimal. 6) A) 0.10 B) 0.55 C) 0.50 D) 0.625

Last Answer : D) 0.625

Any number with an exponent of zero is equal to 2) A) itself. B) ten. C) zero. D) one.

Description : Any number with an exponent of zero is equal to 2) A) itself. B) ten. C) zero. D) one.

Last Answer : D) one.

The decimal equivalent of Binary number 10101 is (A) 21 (B) 31 (C) 26 (D) 28

Description : The decimal equivalent of Binary number 10101 is (A) 21 (B) 31 (C) 26 (D) 28

Last Answer : (A) 21

The 2’s complement of the number 1101110 is (A) 0010001. (B) 0010001. (C) 0010010. (D) None.

Description : The 2’s complement of the number 1101110 is (A) 0010001. (B) 0010001. (C) 0010010. (D) None.

Last Answer : Ans: C 1’s complement of 1101110 is = 0010001 Thus 2’s complement of 1101110 is = 0010001 + 1 = 0010010

The information in ROM is stored (A) By the user any number of times. (B) By the manufacturer during fabrication of the device. (C) By the user using ultraviolet light. (D) By the user once and only once.

Description : The information in ROM is stored (A) By the user any number of times. (B) By the manufacturer during fabrication of the device. (C) By the user using ultraviolet light. (D) By the user once and only once.

Last Answer : (B) By the manufacturer during fabrication of the device.

The result of adding hexadecimal number A6 to 3A is (A) DD. (B) E0. (C) F0. (D) EF.

Description : The result of adding hexadecimal number A6 to 3A is (A) DD. (B) E0. (C) F0. (D) EF.

Last Answer : (B) E0.

The number of control lines for 32 to 1 multiplexer is (A) 4. (B) 5. (C) 16. (D) 6.

Description : The number of control lines for 32 to 1 multiplexer is (A) 4. (B) 5. (C) 16. (D) 6.

Last Answer : Ans: B The number of control lines for 32 (2^5) and to select one input among them total 5 select lines are required.