A problem in mathematics is given to four students A, B, C and D. Their chances of solving the problem -Maths 9th

1 Answer

Answer :

Given, P(A) = \(rac{1}{2}\) ⇒ P(\(\bar{A}\)) = P(A not solving the problem) = 1 - \(rac{1}{2}\) = \(rac{1}{2}\)P(B) = \(rac{1}{3}\) ⇒  P(\(\bar{B}\)) = 1 - \(rac{1}{3}\) = \(rac{2}{3}\)P(C) = \(rac{1}{3}\) ⇒  P(\(\bar{C}\)) = 1 - \(rac{1}{4}\) = \(rac{3}{4}\)P(D) = \(rac{1}{3}\) ⇒  P(\(\bar{D}\)) = 1 - \(rac{1}{5}\) = \(rac{4}{5}\)P(problem will not be solved) = P(\(\bar{A}\)) x  P(\(\bar{B}\)) x P(\(\bar{C}\)) x P(\(\bar{D}\)) = \(rac{1}{2}\)x \(rac{2}{3}\)x \(rac{3}{4}\)x \(rac{4}{5}\) = \(rac{1}{5}\)∴ P(problem will be solved) = 1 - \(rac{1}{5}\) = \(rac{4}{5}\).

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