Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

1 Answer

Answer :

Given that the circle of radius ‘a’ touches both axis. So, its centre is (a, a)  So, the equation of required circles is : (x-a)2 + (y-a)2 = a2 ⇒ x2 - 2ax + a2+y2 - 2ay + a2 = a2 ⇒ x2 + y2 - 2ax - 2ay + a2 = 0

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