Show that x + a is a factor of xn + an for any odd +ve integer n. -Maths 9th

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Answer :

Let f(x) = xn + an  x + a will be the factor of xn + an  if f(-a) = 0  Now f(-a) = (-a)n + an = 0 (since n is a odd +ve integer)  Thus (x +a) is a factor of xn + an .

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