PNP Transistor Working
The circuit connection of PNP transistor with supply voltages is given below. Here the base terminal has negative bias with respect to emitter and the emitter terminal has positive bias voltage with respect to both base and collector because of PNP transistor.
The polarities and current directions are reversed here compared to NPN transistor. If the transistor is connected to all the voltage sources as shown above then the base current flows through the transistor but here the base voltage needs to be more negative with respect to the emitter to operate transistor. Here the base- emitter junction acts as a diode. The small amount of current in the base controls the flowing of large current through emitter to collector region. The base voltage is generally 0.7V for Si and 0.3V for Germanium devices. Here the base terminal acts as input and the emitter- collector region acts as output. The supply voltage VCC is connected to the emitter terminal and a load resistor (RL) is connected to the collector terminal. This load resistor (RL) is used to limits the maximum current flow through the device. One more resistor (RB) is connected to the base terminal which is used to limit the maximum current flow through the base terminal and also a negative voltage is applied to the base terminal. Here the collector current is always equal to the subtraction of base current from emitter current. Like NPN transistor, the PNP transistor also has the current gain value β. Now let us see the relation between the currents and current gain β.
The collector current (IC) is given by,
IC = IE – IB
The DC current gain (β) for the PNP transistor is same as the NPN transistor.
DC current gain = β = Output current/Input current
Here output current is collector current and input current is base current.
β = IC/IB
From this equation we get,
IB = IC/β
IC = β IB
And also we define the current gain as,
Current gain = Collector current/ Emitter current (In common base transistor)
α = IC/IE
The relation between α and β is given by,
The collector current in PNP transistor is given by,
IC = – α IE + ICBO where ICBO is the saturation current.
Since IE = -(IC + IB)
IC = – α (-(IC + IB)) + ICBO
IC – α IC = α IB + ICBO
IC (1- α) = α IB + ICBO
IC = (α/ (1- α)) IB + ICBO/ (1- α)
Since β = α / (1- α)
Now we get the equation for collector current
IC = β IB + (1+ β) ICBO