Recent questions tagged alligation

Description : A merchant mixes three varieties of rice costing Rs.40/kg, Rs.48/kg and Rs.60/kg and sells the mixture at a profit of 40% at Rs.60 / kg. How many kgs of the second variety will be in the mixture if 4 kgs of the third variety is there in the mixture? a) 1 kg b) 20 kgs c) 3 kgs d) 6 kgs e) 8kgs

Last Answer : D If the selling price of mixture is Rs.60/kg and the merchant makes a profit of 20%, then the cost price of the mixture = 60/1.2 = Rs.50/kg. We need to find out the ratio in which the three varieties are mixed ... QC in step 1 and step 2 = 1 + 5 = 6 Therefore, the ratio = 1 : 25 : 5

Description :  In what ratio must a person mix three kinds of musted seeds costing Rs.65/kg, Rs.70/kg and Rs.105 /kg so that the resultant mixture when sold at Rs.96/kg yields a profit of 20%? a) 1:2:4 b) 3:7:6 c) 1:4:2 d)1:8:6 e) 40 : 8 : 25

Last Answer : E The resultant mixture is sold at a profit of 20% at Rs.96/kg i.e. 1.2 (cost) = Rs.96 => Cost = = Rs.80 / kg. Let the three varities be A, B, and C costing Rs.65, Rs.70 and Rs.105 respectively. The ... be mixed. A:C=4:5 B:C=2:5 The resultant ratio A : B : C :: 40 : 8 : 25. 

Description : Redgram worth Rs. 112 per kg and Rs.123 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 142 per kg, the price of the third variety per kg will be a) 153 b) 175.50 c) 43.9 d) 227.9 e) 166.5 

Last Answer : E  Since first second varieties are mixed in equal proportions  so their average price = Rs.(112 + 123/2)  = Rs. 117.5  So, the mixture is formed by mixing two varieties, one at Rs. 117.50 per kg and the ... ratio 2 : 2, i.e., 1 : 1. We have to find x.  By the rule of allgation 

Description : A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid P was contained in the container initially? a) 12 b) 21 c) 93 d)17 e) None 

Last Answer : B Let initial quantity of P in the container be 7x and initial quantity of Q in the container be 5x Now 9 litres of mixture is drawn off from the container. Quantity of P in 9 litres of the mixture drawn off ... = 7 : 9 x=16* 21/4*28 Litres of P contained in the container initially =7x = 21

Description : The cost of Type 1 material is Rs. 50per kg and Type 2 material is Rs.75 per kg. If both Type 1 and Type 2 are mixed in the ratio of 3:2 then what is the price per kg of the mixed variety of material? a) 32 b) 38 c) 53 d) 62 e) 60 

Last Answer : E Cost Price (CP) of Type 1 material is Rs. 50 per kg Cost Price (CP) of Type 2 material is Rs. 75 per kg Let Cost Price(CP) of resultant mixture be Rs.x per kg

Description : A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5? a) 2 b) 3 c) 4 d) 7 e) 6 

Last Answer : E Let cost of 1 litre milk be Rs.1 Milk in 1 litre mix in 1st can =3/4 litre Cost Price(CP) of 1 litre mix in 1st can = Rs. 3/4 Milk in 1 litre mix in 2nd can 1/2 litre. Cost Price(CP) of 1 ... 2nd can :mix in 1st can =1/8:1/8=1:1 ie, from each can,1/2* 12 = 6 litre should be taken.

Description : In what ratio must a person mix three kinds of dall costing him Rs 12.25,Rs 12.50 and Rs 12.75 per Kg so that the mixture may be worth Rs 12.65 per Kg? a) 11:7:1 b) 22:3:6 c) 14:3:4 d) 2:7:4 e) 3:12:32

Last Answer : E Step1: Mix dall of first and third kind to get a mixture worth Rs 12.25 per Kg. C.P of 1 Kg dall of 1st kind 1225p C.P of 1 Kg dall of 3rd kind 1275p So they must be mixed in the ... So the Mixed ratio = 3:8 Thus the quantities of dall 1st : 2nd : 3rd  = 3:12:32

Description : Vessel A contains milk and water in the ratio 3:2. Vessel B contains milk and water in the proportion 4:5.In what proportion should quantities be taken from A & B to form a mixture in which milk and water are in the ratio 7:2? a) 3:2 b) 15:2 c) 4:3 d) 8:15 e) 6:18

Last Answer : D For this question, we will consider the proportion of milk in each mixture. In Vessel A, the proportion of milk in 3/((3+2) )=3/5. vessel B, the proportion of milk is 4/(4+5) = 4/9

Description : Two vessels A and B contain sugar and rava in the ratio 4 : 3 and 2 : 3 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing sugar and rava in the ratio 1 : 2? a) 2:9 b) 3:2 c) 7:9 d) 2:7 e) 7:4

Last Answer : E Let Cost Price(CP) of 1 kg sugar be Rs.1 Quantity of sugar in 1kg mixture from vessel A=4/7 Cost Price(CP) of 1kg mixture from vessel A = Rs. =4/7 Quantity of sugar in 1 kg mixture from vessel ... from vessel C=1/2 Cost Price(CP) of 1 kg mixture from vessel C(Mean Price) = Rs.=1/2

Description : A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal ... . What is the value of x? a) 6 litres b) 10 litres c) 30 litres d) None of these

Last Answer : C Another way for solving this sum is by choice The mixture of 60 litres has in it 24 litres of milk and 36 litres of water. (2 : 3 :: milk water) When you remove x litres from it, you ... have 30 litres of milk and 30 litres of water - i.e. milk and water are in equal proportion.

Description : A jar full of whiskey contains 52% alcohol. A part of this whisky is replaced by another containing 31% alcohol and now the percentage of alcohol was found to be 38%. The quantity of whisky replaced is a) 3/2 b) 2/3 c) 4/3 d) 2/7 e) None

Last Answer : B Concentration of alcohol in 1st Jar = 52% Concentration of alcohol in 2nd Jar = 31% After the mixing, Concentration of alcohol in the mixture = 38% By rule of allegation, Hence ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2 i.e., 2/3 part of the whisky is replaced.

Description : A container contains 55 litres of milk. From this container 5.5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? a) 32 b) 29.16 c) 43 d) 27.12 e) 40.09 

Last Answer : E  Where x is the initial quantity of milk in the cask y is the quantity of milk withdrawn in each process and n is the number of processes. Initial quantity:55 Withdrawn quantity=5.5 number of times repeated ... of milk left after the 3rd operation =55*((55-5.5)/55) ^3  =40.09litres.

Description : How many litres of a 36 litre mixture containing milk and water in the ratio of 4 : 6 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion? a) 3 b) 2 c) 4 d) 7 e) 6 

Last Answer :  E  The mixture contains 40% milk and 60% water in it.  That is 14.4 litres of milk and 21.6 litres of water.  Now we are replacing the mixture with pure milk so that the amount of milk and water in the ... containing 60% water,  we need to remove ={3.6}/{0.6} litres of the mixture  = 6 litres

Description :  From a cask of milk containing 45 litres, 9 litres are drawn out and the cask is filled up with water.If the same process is repeated a second, then a third time, what will be the number of litres of milk left in the cask? a) 31.2 b) 20.9 c) 23.04 d) 12.39 e) 15.36

Last Answer : C where x is the initial quantity of milk in the cask y is the quantity of milk withdrawn in each process and n is the number of processes. Initial quantity:45 Withdrawn quantity=9 number of times repeated=3 ... ] Quantity of milk left after the 3rd operation =45*(45-9)/45)^3 = 23.04 litres.

Description : A vessel is filled with liquid, 4 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup? a) 1/3 b) 1/5 c) 1/4 d) 1/7 e) 1/10

Last Answer : E Suppose the vessel initially contains 9 litres of liquid. Let x litres of this liquid be replaced with water. Quantity of water in new mixture = 4 - 4x/9 + x litres Quantity of syrup in new mixture = 5 - 5x /9 (4 ... 9  X = 9 / 10 So part of the mixture replaced = 9 / 10 1 / 9  = 1 / 10

Description : In 20 litres of a mixture, the ratio of sugar syrub to honey syrub is 5:1. In order to make the ratio of sugar syrub to honey syrub as 3:1, the quantity of honey syrub that should be added to the mixture will be A) 5 2/3 B) 4 1/3 C) 6 2/3 D) 2 2/9

Last Answer : D By the rule of alligation Quantity of honey : Quantity of mixture =1/12:3/4}=1:9 Given that quantity of mixture = 20 litre =>Quantity of honey : 20 = 1 : 9 => Quantity of honey = 20 x1/9  = 2 2/9 litre

Description : Find the ratio in which Nuts at Rs. 5.40 a kg be mixed with Nuts at Rs. 3.20 a kg to produce a mixture worth Rs. 4.60 a kg. a) 9:2 b) 2:3 c) 4:3 d) 3:2 e) 7:4

Last Answer : E By the rule of allegation  Required ratio = 140 : 80  = 7:4

Description :  In 1 kg mixture of iron and carbon, 40% is carbon. How much iron should be added so that the proportion of carbon becomes 20% a)1.5kg b)2kg c)3kg d)5kg e)1kg

Last Answer : E Quantity of the mixture : Quantity of iron = 20 : 20 = 1 : 1 Given that quantity of the mixture = 1 kg Hence quantity of iron to be added = 1 kg

Description : How many kg of dal at Rs.8.40 per kg be mixed with32 kg of dall at Rs10.20 per kg to get a mixture worth Rs.9.60 per kg? a) 23 b) 49 c) 43 d) 72 e) 16

Last Answer : E By the rule of allegation ,we have Quantity of 1st kind dall : Quantity of 2nd kind dall = 60 : 120  => Quantity of 1st kind dall:32 = 1:2  Quantity of 1st kind dall =32 *1/2 = 16

Description : In what ratio must water be mixed with milk costing Rs.30 per litre in order to get a mixture worth of Rs.18 per litre? a) 3:2 b) 2:3 c) 4:3 d) 2:7 e) 1:2

Last Answer : B  By the rule of allegation  Ratio of water to milk = 12:18 = 2:3

Description : In what ratio should wheat at Rs12.60 per kg be mixed with wheat at Rs. 14.60 per kg so that the mixture be worth Rs.13 per kg ? a) 6:8 b) 8:7 c) 4:3 d) 2:7 e) 4:1

Last Answer : E Thus the required ratio = 160 :40 = 4:1

Description : Some amount out of Rs.8500 was lent at 5% per annum and the remaining was lent at 3% per annum. If the total simple interest from both the fractions in4 years was Rs.1500, the sum lent at 5% per annum was a) Rs. 2400 b) Rs. 2200 c) Rs. 2000 d) Rs. 6000

Last Answer : D Total simple interest received , I = Rs.1500 Principal , p = 8500 period, n = 4 years Rate of interest, r = ? Simple Interest, I=PNR/100 1500 = ( 8500 4 r )/ 100  = ... total amount is Rs.8500.  Therefore, the amount lent at 5% per annum (part1 amount) = 8500x12/17  = 6000 

Description : In what ratio should a shopkeeper mix two types of rice, one costing 40 rupees/kg and another costing 20 rupees/kg to get a rice variety costing 28 rupees/kg a) 3:2 b) 2:3 c) 4:3 d) 2:7 e) None

Last Answer : B Here also we can use Alligation as follows  X = 40-28 = 4 ; y = 28-20 = 8 The ratio between the type 1 and type 2 rice is 4:6 or 2: 3

To see more, click for the full list of questions or popular tags.