answer:I studied chemistry long ago, but I know the molecular weight of water is 18, so 90 g of water is 5 moles. One mole of C(n)H(2n)O(n) weighs 12n + 2n + 16n = 30n grams. Normally this isn’t enough information, but from the boiling point elevation of water (given that the solution is aqueous) you can calculate the molality of the solution—here’s where I’d have to crack some books. Then you infer how many moles M of solute (weighing 288 grams) are in solution, from which n = 288*M / 30 = 9.6 * M. If your answer is correct (n=45) then M must work out to 4.68 moles.