Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Steam is throttled to 0.1 MPa with
20 degrees of superheat. (a) What is the quality of throttled steam if its pressure
is 0.75 MPa (b) What is the enthalpy of
the process?
 a) 97.6%,2713 kJ/kg
 b) -97.6%, 2713 kJ/kg
 c) 87.6%,3713 kJ/kg
 d) -87.6%, 3713 kJ/kg
by

1 Answer

Answer :

97.6%,2713 kJ/kg
by

Related questions

Wet steam at 1 MPa flowing through a pipe is throttled to a pressure of 0.1 MPa. If the throttling temperature is110°C, What is the quality of the steam in the pipe?  a) 96%  b) 86%  c) 76%  d) 66%

Description : Wet steam at 1 MPa flowing through a pipe is throttled to a pressure of 0.1 MPa. If the throttling temperature is110°C, What is the quality of the steam in the pipe?  a) 96%  b) 86%  c) 76%  d) 66%

Last Answer : 96%

A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Description : A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Last Answer : 265.4°C, 430.7kJ/kg, 71.4kJ/kg, 1.0327kJ/(kg)(K),502.1 kJ/kg

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 x10^6 kJ  D. 2 x10^6 kJ Formula: fromthe steamtable vƒ = 0.001043 m^3 / kg vg = 1.6940 m^3 / kg u ƒ= 417.3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Description : A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 ... 3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Last Answer : 2 x10^6 kJ

____________is the difference between the saturation temperature for the given pressure and the actual sub cooled liquid temperature.  a) Degrees of Superheat, °SH  b) Degrees of Sub cooled, °SB  c) Both a and b  d) None of the above

Description : ____________is the difference between the saturation temperature for the given pressure and the actual sub cooled liquid temperature.  a) Degrees of Superheat, °SH  b) Degrees of Sub cooled, °SB  c) Both a and b  d) None of the above

Last Answer : Degrees of Sub cooled, °SB

_____________ is the difference between the actual temperature of superheated vapor and the saturation temperature for the existing pressure.  a) Degrees of Superheat, °SH  b) Degrees of Sub cooled, °SB  c) Both a and b  d) None of the above

Description : _____________ is the difference between the actual temperature of superheated vapor and the saturation temperature for the existing pressure.  a) Degrees of Superheat, °SH  b) Degrees of Sub cooled, °SB  c) Both a and b  d) None of the above

Last Answer : Degrees of Superheat, °SH

Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Description : Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Last Answer : -1384.7 kJ

What is defined as the ratio of the change in temperature to the change in pressure when a real gas is throttled?  A. Rankine coefficient  B. Kelvin coefficient  C. Maxwell-Boltzmann coefficient  D. Joule-Thomson coefficient

Description : What is defined as the ratio of the change in temperature to the change in pressure when a real gas is throttled?  A. Rankine coefficient  B. Kelvin coefficient  C. Maxwell-Boltzmann coefficient  D. Joule-Thomson coefficient

Last Answer : Joule-Thomson coefficient

There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat. Determine t2. (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water?  A. 0.043 K/s  B. 0.179 K/s  C. 0.357 K/s  D. 1.50 K/s Formula: Q = mcv ( T)

Description : Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water?  A. 0.043 K/s  B. 0.179 K/s  C. 0.357 K/s  D. 1.50 K/s Formula: Q = mcv ( T)

Last Answer : 0.179 K/s

Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam.  A.2500 lbf-ft/lbm  B.3300 lbf-ft/lbm  C.5400 lbf-ft/lbm  D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV

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Specific heat capacity in SI unit.  a. kJ / kg.k  b. kJ / kg  c. kN / kg  d. None of the above

Description : Specific heat capacity in SI unit.  a. kJ / kg.k  b. kJ / kg  c. kN / kg  d. None of the above

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The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Description : The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Last Answer : 300 kJ

What is the latent heat of vaporization of water at 1 atm?  A. 2314.8 kJ/kg  B. 2257.1 kJ/kg  C. 2511.7 kJ/kg  D. 2429.8 kJ/kg

Description : What is the latent heat of vaporization of water at 1 atm?  A. 2314.8 kJ/kg  B. 2257.1 kJ/kg  C. 2511.7 kJ/kg  D. 2429.8 kJ/kg

Last Answer : 2257.1 kJ/kg

What is the latent heat of fusion of water at 1 atm?  A. 331.1 kJ/kg  B. 332.6 kJ/kg  C. 333.7 kJ/kg  D. 330.7 kJ/kg

Description : What is the latent heat of fusion of water at 1 atm?  A. 331.1 kJ/kg  B. 332.6 kJ/kg  C. 333.7 kJ/kg  D. 330.7 kJ/kg

Last Answer : 333.7 kJ/kg

What is the unit of the total energy of the system?  A. Kj  B. Kj/Kg  C. Kg  D. g

Description : What is the unit of the total energy of the system?  A. Kj  B. Kj/Kg  C. Kg  D. g

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Oxygen at 15ºC and 10.3 Mpa gauge pressure occupies 600L. What is the occupied by the oxygen at 8.28 Mpa gauge pressure and 35ºC?  a. 789.32 L  b. 796.32 L  c. 699 L  d. 588 L V2= P1V1/T1P2

Description : Oxygen at 15ºC and 10.3 Mpa gauge pressure occupies 600L. What is the occupied by the oxygen at 8.28 Mpa gauge pressure and 35ºC?  a. 789.32 L  b. 796.32 L  c. 699 L  d. 588 L V2= P1V1/T1P2

Last Answer : 796.32 L

Which of the following is the other term used for enthalpy-entropy diagram?  a. Enthalpy diagram  b. Mollier diagram  c. Steam diagram  d. Entropy chart

Description : Which of the following is the other term used for enthalpy-entropy diagram?  a. Enthalpy diagram  b. Mollier diagram  c. Steam diagram  d. Entropy chart

Last Answer : Mollier diagram

For which of the following substances, the internal energy and enthalpy are the functions of temperature only  (a) any gas  (b) saturated steam  (c) water  (d) perfect gas  (e) superheated steam.

Description : For which of the following substances, the internal energy and enthalpy are the functions of temperature only  (a) any gas  (b) saturated steam  (c) water  (d) perfect gas  (e) superheated steam.

Last Answer : Answer : d

Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Description : A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Last Answer : 12 kJ

Saturated steam at a pressure of 25 kg/cm2is throttled to attain 5 kg/cm2. Then the outcoming steam will be (A) Wet (B) Saturated (C) Superheated (D) None of these

Description : Saturated steam at a pressure of 25 kg/cm2is throttled to attain 5 kg/cm2. Then the outcoming steam will be (A) Wet (B) Saturated (C) Superheated (D) None of these

Last Answer : C) Superheated

Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Description : Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Last Answer : 9.86 x 10^4 N/m^2

An adiabatic process in which there is no change in system enthalpy but for which there is a significant decrease in pressure is called _____.  A. Isochoric process  B. Isobaric process  C. Throttling process  D. Quasistatic process

Description : An adiabatic process in which there is no change in system enthalpy but for which there is a significant decrease in pressure is called _____.  A. Isochoric process  B. Isobaric process  C. Throttling process  D. Quasistatic process

Last Answer : Throttling process

Change in enthalpy in a closed system is equal to heat transferred if the reversible process takes place at constant  (a) pressure  (b) temperature  (c) volume  (d) internal energy  (e) entropy.

Description : Change in enthalpy in a closed system is equal to heat transferred if the reversible process takes place at constant  (a) pressure  (b) temperature  (c) volume  (d) internal energy  (e) entropy.

Last Answer : Answer : a

If value of n is infinitely large in a polytropic process pV” = C, then the process is known as constant  (a) volume  (b) pressure  (c) temperature  (d) enthalpy  (e) entropy

Description : If value of n is infinitely large in a polytropic process pV” = C, then the process is known as constant  (a) volume  (b) pressure  (c) temperature  (d) enthalpy  (e) entropy

Last Answer : Answer : a

A gas is compressed in a cylinder by a movable piston to a volume onehalf its original volume. During the process 300 kJ heat left the gas and internal energy remained same. The work done on gas in Nm will be  (a) 300 Nm  (b) 300,000 Nm  (c) 30 Nm  (d) 3000 Nm  (e) 30,000 Nm.

Description : A gas is compressed in a cylinder by a movable piston to a volume onehalf its original volume. During the process 300 kJ heat left the gas and internal energy remained same. The work done on gas in Nm will be  (a) 300 Nm  (b) 300,000 Nm  (c) 30 Nm  (d) 3000 Nm  (e) 30,000 Nm.

Last Answer : Answer : b

A perfect gas has a value of R= 319.2 J/ kf.K and k= 1.26. If 120 kJ are added to 2.27 kf\g of this gas at constant pressure when the initial temp is 32.2°C? Find T2.  a. 339.4 K  b. 449.4 K  c. 559.4K  d. 669.4K formula: cp = kR/ k-1 Q= mcp(T2-T1)

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Last Answer : 339.4 K

The flow energy of 150 L of a fluid passing a boundary to a system is 110 kJ. Determine the pressure at this point  a. 733.33 kPa  b. 833.33 kPa  c. 933.33 kPa  d. 633.33 kPa

Description : The flow energy of 150 L of a fluid passing a boundary to a system is 110 kJ. Determine the pressure at this point  a. 733.33 kPa  b. 833.33 kPa  c. 933.33 kPa  d. 633.33 kPa

Last Answer : 733.33 kPa

The efficiency of superheat Rankine cycle is higher than that of simple Rankine cycle because [GATE-2002] (a) The enthalpy of main steam is higher for superheat cycle (b) The mean temperature of heat addition is higher for superheat cycle (c) The temperature of steam in the condenser is high (d) The quality of stem in the condenser is low

Description : The efficiency of superheat Rankine cycle is higher than that of simple Rankine cycle because [GATE-2002] (a) The enthalpy of main steam is higher for superheat cycle (b) The mean temperature of heat ... temperature of steam in the condenser is high (d) The quality of stem in the condenser is low 

Last Answer :  (b) The mean temperature of heat addition is higher for superheat cycle  

A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C. 2.54 kg  D. 3.16 kg Formula: from the steam table at 600kPa vƒ = 0.001101 m^3 / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Description : A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C ... / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Last Answer : 3.16 kg

A state occurs in isentropic process  a. The change in entropy is 0  b. The change in entropy is 1  c. The change in enthalpy is 0  d. The change in enthalpy is 1

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Last Answer : The change in entropy is 0

The value of gas constant (R) in S. I. units is  A. 0.287 J/kgK  B. 2.87 J/kgK  C. 28.7 J/kgK  D. 287 J/kgK

Description : The value of gas constant (R) in S. I. units is  A. 0.287 J/kgK  B. 2.87 J/kgK  C. 28.7 J/kgK  D. 287 J/kgK

Last Answer : Answer: D

Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Description : Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Last Answer : 1.1577 BTU/lbm-˚R

2000 kJ of heat is supplied to 500 kg of ice at 0oC. If the latent heat of fusion of ice is 335 kJ/kg then the amount of ice in kg melted will be a) 1.49 b) 83.75 c) 5.97 d) None of the above

Description : 2000 kJ of heat is supplied to 500 kg of ice at 0oC. If the latent heat of fusion of ice is 335 kJ/kg then the amount of ice in kg melted will be a) 1.49 b) 83.75 c) 5.97 d) None of the above

Last Answer : c) 5.97

Sum of the internal energy of a substance and the product of pressure and volume.  a. Specific Heat  b. Specific Gravity  c. Isolated System  d. Enthalpy

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Last Answer : Enthalpy

What predicts the approximate molar specific heat at high temperatures from the atomic weight?  A. Third law of thermodynamics  B. Law of Dulong and Petit  C. Mollier diagram  D. Pressure-enthalpy diagram

Description : What predicts the approximate molar specific heat at high temperatures from the atomic weight?  A. Third law of thermodynamics  B. Law of Dulong and Petit  C. Mollier diagram  D. Pressure-enthalpy diagram

Last Answer : Law of Dulong and Petit

The sum of internal energy (U) and the product of pressure and volume (p.v) is known as  A. workdone  B. entropy  C. enthalpy  D. none of these

Description : The sum of internal energy (U) and the product of pressure and volume (p.v) is known as  A. workdone  B. entropy  C. enthalpy  D. none of these

Last Answer : Answer: C

Change in enthalpy of a system is the heat supplied at  (a) constant pressure  (b) constant temperature  (c) constant volume  (d) constant entropy  (e) N.T.P. condition.

Description : Change in enthalpy of a system is the heat supplied at  (a) constant pressure  (b) constant temperature  (c) constant volume  (d) constant entropy  (e) N.T.P. condition.

Last Answer : Answer : a

Which of the following parameters is constant for a mole for most of the gases at a given temperature and pressure  (a) enthalpy  (b) volume  (c) mass  (d) entropy  (e) specific volume.

Description : Which of the following parameters is constant for a mole for most of the gases at a given temperature and pressure  (a) enthalpy  (b) volume  (c) mass  (d) entropy  (e) specific volume.

Last Answer : Answer : b

Which of the following is the property of a system  (a) pressure and temperature  (b) internal energy  (c) volume and density  (d) enthalpy and entropy  (e) all of the above.

Description : Which of the following is the property of a system  (a) pressure and temperature  (b) internal energy  (c) volume and density  (d) enthalpy and entropy  (e) all of the above.

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Which of the following values characterize the state of the system?  a. cycle  b. process  c. property  d. enthalpy

Description : Which of the following values characterize the state of the system?  a. cycle  b. process  c. property  d. enthalpy

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The change that the system that undergoes from one equilibrium state to another is known as  a. oath  b. process  c. enthalpy change  d. entropy change

Description : The change that the system that undergoes from one equilibrium state to another is known as  a. oath  b. process  c. enthalpy change  d. entropy change

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Which of the following occurs in a reversible polytrophic process?  a. Enthalpy remains constant  b. Internal energy does not change  c. Some heat transfer occurs  d. Entropy remains constant

Description : Which of the following occurs in a reversible polytrophic process?  a. Enthalpy remains constant  b. Internal energy does not change  c. Some heat transfer occurs  d. Entropy remains constant

Last Answer : Some heat transfer occurs

Regardless of the process, the change in enthalpy firm moles of ideal gas is  a. Heat  b. Enthalpy  c. Entropy  d. Density

Description : Regardless of the process, the change in enthalpy firm moles of ideal gas is  a. Heat  b. Enthalpy  c. Entropy  d. Density

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Gas being heated at constant volume is undergoing the process of.  a. isometric  b. specific heat  c. enthalpy  d. isothermal

Description : Gas being heated at constant volume is undergoing the process of.  a. isometric  b. specific heat  c. enthalpy  d. isothermal

Last Answer : isometric

In an isothermal process,  A. there is no change in temperature  B. there is no change in enthalpy  C. there is no change in internal energy  D. all of these

Description : In an isothermal process,  A. there is no change in temperature  B. there is no change in enthalpy  C. there is no change in internal energy  D. all of these

Last Answer : Answer: D

The free expansion process is a constant enthalpy process.  A. Correct  B. Incorrect

Description : The free expansion process is a constant enthalpy process.  A. Correct  B. Incorrect

Last Answer : Answer: A

According to first law of thermodynamics  (a) work done by a system is equal to heat transferred by the system  (b) total internal energy of a system during a process remains constant  (c) internal energy, enthalpy and entropy during a process remain constant  (d) total energy of a system remains constant

Description : According to first law of thermodynamics  (a) work done by a system is equal to heat transferred by the system  (b) total internal energy of a system during a process remains constant  ( ... , enthalpy and entropy during a process remain constant  (d) total energy of a system remains constant

Last Answer : Answer : d