The number of degrees of freedom in simple spring mass system is A. Zero B. One C. Two D. Three

The number of degrees of freedom in simple spring mass system is
A. Zero
B. One
C. Two
D. Three
by

1 Answer

Answer :

B. One
by

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Last Answer : False

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Last Answer : A) 9810 N/m

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Last Answer : (B) 1/3

A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

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A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

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Last Answer : a) 0.471 and 1.19 Hz

The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

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Last Answer : a) ω n

While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is a) 1/2 b) 1/3 c) 1/4 d) 3/4

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Last Answer : b) 1/3

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

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Last Answer : c. 6.16 Hz

Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 –3 m 3. Natural frequency of the system = 60 rad/sec a. 100.5 x 10 3 N-s/m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

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Last Answer : c. 42 x 10 3 N-s/m

A spring-mass system has a natural frequency of 10 rad/sec. When the spring constant is reduced by 800 N/m, the frequency is altered by 45 percent. Find the mass and spring constant of the original system. a)11.47kg and 1147.95N/m b)8.95kg and 895.25N/m c) 7.265kg and 726.5N/m d)None

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Last Answer : a)11.47kg and 1147.95N/m

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

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Last Answer : (C) 11.14 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

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Last Answer : a) 0.471 and 1.19 Hz

The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

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Last Answer : a) ω n

While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is a) 1/2 b) 1/3 c) 1/4 d) 3/4

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Last Answer : b) 1/3