What would the final freezing point of water be if 3 mol of sugar were added to 1 kg of water kf1.86 c molkg for water and I 1 for sugar?

What would the final freezing point of water be if 3 mol of sugar were added to 1 kg of water kf1.86 c molkg for water and I 1 for sugar?
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How much would the boiling point of water increase if 4 mol of sugar were added to 1 kg of water kb0.51c cmolkgfor water nd I1 for sugar?

Description : How much would the boiling point of water increase if 4 mol of sugar were added to 1 kg of water kb0.51c cmolkgfor water nd I1 for sugar?

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How much would the boiling of water increase if 4 mol of NaCl were added to 1 kg of water?

Description : How much would the boiling of water increase if 4 mol of NaCl were added to 1 kg of water?

Last Answer : 4.08 C

In Celsius, the freezing point of a one-molal water solution of sodium phosphate, chemical formula Na3PO4, is expected to be: w) - 0.93 degrees Celsius x) - 1.86 degrees Celsius y) - 7.44 degrees Celsius z) - 3.72 degrees Celsius

Description : In Celsius, the freezing point of a one-molal water solution of sodium phosphate, chemical formula Na3PO4, is expected to be: w) - 0.93 degrees Celsius x) - 1.86 degrees Celsius y) - 7.44 degrees Celsius z) - 3.72 degrees Celsius

Last Answer : ANSWER: C -- (- 7.44 DEGREES CELSIUS)

How much would the boiling point of water increase if 4 mol of NaCl were added to 1kg of water?

Description : How much would the boiling point of water increase if 4 mol of NaCl were added to 1kg of water?

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An aeroplane of 110,000kg has its CG at 22.6m aft of the datum. The CG limits are 18m to 22m aft of the datum. How much mass must be removed from a hold 30m aft of the datum to bring the CG to its mid point? a. 26,800 kg b. 28,600 kg c. 86,200 kg d. 62,800 kg

Description : An aeroplane of 110,000kg has its CG at 22.6m aft of the datum. The CG limits are 18m to 22m aft of the datum. How much mass must be removed from a hold 30m aft of the datum to bring the CG to its mid point? a. 26,800 kg b. 28,600 kg c. 86,200 kg d. 62,800 kg

Last Answer : b. 28,600 kg

An aeroplane of 110,000kg has its CG at 22.6m aft of the datum. The CG limits are 18m to 22m aft of the datum. How much mass must be removed from a hold 30m aft of the datum to bring the CG to its mid point? a. 26,800 kg b. 28,600 kg c. 86,200 kg d. 62,800 kg

Description : An aeroplane of 110,000kg has its CG at 22.6m aft of the datum. The CG limits are 18m to 22m aft of the datum. How much mass must be removed from a hold 30m aft of the datum to bring the CG to its mid point? a. 26,800 kg b. 28,600 kg c. 86,200 kg d. 62,800 kg

Last Answer : b. 28,600 kg

In cold countries ethylene glycol is added to water in car radiators. This helps to (a) Reduce the viscosity (b) Make water a better lubricant (c) Lower the freezing point (d) Lower the boiling poin

Description : In cold countries ethylene glycol is added to water in car radiators. This helps to (a) Reduce the viscosity (b) Make water a better lubricant (c) Lower the freezing point (d) Lower the boiling poin

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How do i Calculate the mass of 2.50 mol of CH3OH(l). Show my work and Use the appropriate number of significant digits in your final answer.?

Description : How do i Calculate the mass of 2.50 mol of CH3OH(l). Show my work and Use the appropriate number of significant digits in your final answer.?

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Tetraethyl lead (TEL) is added to petrol to (a) prevent its freezing (b) increase its boiling point (c) increase its flash point (d) increase its anti-knocking rating

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Last Answer : Ans:(d)

__________ of SBR is adversely affected, if more quantity of styrene is added to butadiene during its co-polymerisation to produce SBR. (A) Percent elongation (B) Resilience (C) Freezing point (D) Strength

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What is the molality of a solution the has 3 mol of glucose on 6 kg of water?

Description : What is the molality of a solution the has 3 mol of glucose on 6 kg of water?

Last Answer : Molality (m) is moles of solute per kg of solvent. 3 moles/6 kg= 0.5 molal.

A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Description : A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Last Answer : (B) 11.77 kPa

A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is the partial pressure of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Description : A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is ... of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Last Answer : 84.6

if my sugar is 86 is that to low?

Description : if my sugar is 86 is that to low?

Last Answer : if my sugar is 86 is that to low

A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill. On examination her blood pressure was 110/70 mmHg and her body mass index was 21.5 kg/m2 (18 - 25). Investigations sodium 135 mmol/l potassium 2.1 mmol/l bicarbonate 42 mmol/l urea 2.6 mol/L corrected calcium 2.08 mmol/ alkaline phosphatase 201 iu/l (50-110) What is the most likely diagnosis? 1) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Description : A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill ... ) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Last Answer : Answers-5 This patient has tooth erosion associated with hypokalaemic metabolic alkalosis and hypocalcaemia. This suggests a diagnosis of hypoparathyroidism. Conn's is unlikely in this age group, is ... raised alkaline phosphatase would not be expected. Early pregnancy would not fit this picture.

Unit of luminous intensity is A. m B. kg C. cd D. mol

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Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Description : Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Last Answer : Answer : a

Glycol is added to aviation gasoline because it (1) reduces evaporation of petrol (2) increases efficiency of petrol (3) prevents freezing of petrol (4) reduces consumption of petrol

Description : Glycol is added to aviation gasoline because it (1) reduces evaporation of petrol (2) increases efficiency of petrol (3) prevents freezing of petrol (4) reduces consumption of petrol

Last Answer : prevents freezing of petrol

Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` and boiling point of ethanol is `78.5^(@)`.

Description : Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` and boiling point of ethanol is `78.5^(@)`.

Last Answer : Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` ... KJ mol^(-1)` D. Some more data is required

From a vessel containing 100 litres of ****,10 litres are drawn out and an equal amount of water is added. From the mixture,10 litres is again drawn out and same quantity of water is added. What is the final ratio of **** and water? a) 91 : 9 b) 81 : 19 c) 80 : 20 d) 90 : 10 e) None of these

Description : From a vessel containing 100 litres of wine,10 litres are drawn out and an equal amount of water is added. From the mixture,10 litres is again drawn out and same quantity of water is added. What is the final ratio of wine and water? a) 91 : 9 b) 81 : 19 c) 80 : 20 d) 90 : 10 e) None of these

Last Answer : Quantity of wine after two replacements = 100 l × (90/100)2 =81 l Required ratio = 81 : ( 100 – 81 )= 81 : 19 Answer: b)

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

Prior to using an analog type ohmmeter, the leads are purposely shorted together. Which of the following actions should be taken if, when adjusting to 'zero' ohms, the indicating needle can not be returned to 'zero' on the scale? A. The lead clips should be replaced. B. The batteries should be replaced. C. The test reading should be added to each final reading. D. The test reading should be subtracted from each final reading.

Description : Prior to using an analog type ohmmeter, the leads are purposely shorted together. Which of the following actions should be taken if, when adjusting to 'zero' ohms, the indicating needle can not be ... be added to each final reading. D. The test reading should be subtracted from each final reading.

Last Answer : Answer: B

Filter aids like asbestos, kieselguhr, diatomaceous earth etc. are used to increase the porosity of the final filter cake & reducing the cake resistance during filtration. Filter aid is (A) Added to the feed slurry (B) Pre-coated on the filter medium prior to filtration (C) Separated from the cake by dissolving solids or by burning it off (D) All 'a', 'b' & 'c'

Description : Filter aids like asbestos, kieselguhr, diatomaceous earth etc. are used to increase the porosity of the final filter cake & reducing the cake resistance during filtration. Filter aid is (A) Added to the feed slurry (B) Pre ... the cake by dissolving solids or by burning it off (D) All 'a', 'b' & 'c'

Last Answer : (D) All 'a', 'b' & 'c'

In the SMTP herder field_____ is added by the final transport system that delivers the mail. a. Reply-to b. Return-path c. Subject d. From

Description : In the SMTP herder field_____ is added by the final transport system that delivers the mail. a. Reply-to b. Return-path c. Subject d. From

Last Answer : b. Return-path

Intermediate goods are not included to calculate the final output because: a) they do not have value b) they have unknown value c) their value is included in final goods so they are not added to avoid the problem of double counting d) none of the above

Description : Intermediate goods are not included to calculate the final output because: a) they do not have value b) they have unknown value c) their value is included in final goods so they are not added to avoid the problem of double counting d) none of the above

Last Answer : : c) their value is included in final goods so they are not added to avoid the problem of double counting

To make a solution for filling radiator one bag of washing soda and 0.5 kg of kerosene oil should be added in water amounting a) 6 kg b) 8 k8 c ) 10 kg d) 12 kg

Description : To make a solution for filling radiator one bag of washing soda and 0.5 kg of kerosene oil should be added in water amounting a) 6 kg b) 8 k8 c ) 10 kg d) 12 kg

Last Answer : c ) 10 kg

A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

In a boiler enthalpy of water supplied was 2000 kJ/kg. Enthalpy being added by fuel combustion is 3200 kJ/kg. Using first law of thermodynamics, find amount of heat supplied if steam generation rate is 10 tons per hour.

Description : In a boiler enthalpy of water supplied was 2000 kJ/kg. Enthalpy being added by fuel combustion is 3200 kJ/kg. Using first law of thermodynamics, find amount of heat supplied if steam generation rate is 10 tons per hour.

Last Answer : Heat supplied Q = m (h2-h1) …….(Steady flow energy equation for boiler) ; h2=3200 KJ/kg h1=2000 KJ/kg m = 10 Tons /hour = (10 x 1000)/3600 kg/sec = 2.77 Kg/sec Q = 2.77(3200-2000) = 3324 KJ/sec heat supplied for 10 Tons/hr steam generation

Calculate quantity of water to be added for casting cubes in laboratory by 12.5 kg cement if w/c ratio 0.45.

Description : Calculate quantity of water to be added for casting cubes in laboratory by 12.5 kg cement if w/c ratio 0.45. 

Last Answer : As w/c = (weight of water / weight of cement)  w/c = (Ww / Wc)  0.45 = (Ww / 12.5)  Ww = (0.45x12.5)  Ww = 5.625 kg or 5.625 Litres

. Kick's law assumes that the energy required for size reduction is proportional to the logarithm of the ratio between the initial and the final diameters. The unit of Kick's constant is (A) kW. sec/kg (B) kWh/kg (C) kWh/sec. kg (D) kg/sec

Description : . Kick's law assumes that the energy required for size reduction is proportional to the logarithm of the ratio between the initial and the final diameters. The unit of Kick's constant is (A) kW. sec/kg (B) kWh/kg (C) kWh/sec. kg (D) kg/sec

Last Answer : (A) kW. sec/kg

One kg of gas occupying 0.1m^3 at pressure of 14 bar is expanded at constant pressure to 0.2m^3. Determine an initial and final temperature of gas. Take Cp=1.008KJ/KgK, Cv =0.72KJ/KgK.

Description : One kg of gas occupying 0.1m^3 at pressure of 14 bar is expanded at constant pressure to 0.2m^3. Determine an initial and final temperature of gas. Take Cp=1.008KJ/KgK, Cv =0.72KJ/KgK.

Last Answer : V1=0.1m^3 V2=0.2 m^3 P1=P2=14 bar Cp=1.008 KJ/KgK Cv=0.72 KJ/KgK R=Cp-Cv R=1.008-0.72 R=0.288KJ/KgK Characteristic gas equation,  P1V1=mRT1 14*10^5*0.1=1*288*T1 T1=486.11K For constant pressure process, V1/T1=V2/T2 0.1/486.11=0.2/T2 T2=972.22K

Assertion: Coacervates are believed to be precursors of life. Reason: Coacervates were self duplicating aggregates of proteins surrounded by lipid mol

Description : Assertion: Coacervates are believed to be precursors of life. Reason: Coacervates were self duplicating aggregates of proteins surrounded by lipid mol

Last Answer : Assertion: Coacervates are believed to be precursors of life. Reason: Coacervates were self duplicating ... both the assertion and reason are false.

Besides drinking pure (no sugar added) Cranberry juice and a crapload of water, is there any way to take care of a bladder infection, so, that it will disappear?

Description : Besides drinking pure (no sugar added) Cranberry juice and a crapload of water, is there any way to take care of a bladder infection, so, that it will disappear?

Last Answer : Cranberry caplets are available where vitamins are sold. It's like drinking lots and lots of the juice, but without having to taste it. I recommend them, but this is not medical advice. :) Let's just say it ... of them all day, though - but that's as good as it gets for home remedies. Good luck.

The mass of a box measured by a grocer’s balance is 2.3 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box.

Description : The mass of a box measured by a grocer’s balance is 2.3 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box.

Last Answer : The mass of a box measured by a grocer's balance is 2.3 kg. Two gold pieces of masses ... in the masses of the pieces to correct significant figures?

There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat. Determine t2. (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

The average weight of 45 passenger on board an aircraft is 50 kg. If the weight of 5 members of the crew is added, the average is reduced by half kilogram . What is the average weight of the crew members?

Description : The average weight of 45 passenger on board an aircraft is 50 kg. If the weight of 5 members of the crew is added, the average is reduced by half kilogram . What is the average weight of the crew members?

Last Answer : Total weight of 45 passenger = 45 x 50 = 2250 kg Total weight of 45 passenger and 5 crews = 50 x 49.5 = 2475 kg Total weight of 5 crews = 2475-2250 = 225kg Average weight of 5 crews = 225/5 = 45kg.

In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg

Description : In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg 

Last Answer : Constant pressure process Final condition of steam is dry saturated Enthalpy of dry steam = hg= hf + hfg =2776.2 KJ/Kg .Given Latent heat of vaporization = hfg = hg - hf =2776.2-762.6 =2013.6 KJ/Kg Initial condition ... hfg = 762.6+0.8 X 2013.6 =2373.48 KJ/Kg Heat added = hg-hw = 402.72 KJ/kg

In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%? a) 1 kg b) 200 gms c) 800 gms d) 1.8 kg e) None of these

Description : In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%? a) 1 kg b) 200 gms c) 800 gms d) 1.8 kg e) None of these

Last Answer : Answer: A If we add x grams of sand, the total amount would be 1,000 + x grams of mixture and we need 200 grams of iron to be 10% of that: 0.1(1,000 + x) = 200 --> x = 1,000. 

By mixing two brands of dal and selling the mixture at the rate of Rs.354 per kg a shopkeeper makes a profit of 36%. If to every 4 kg of one brand costing Rs.400 per kg, 6kg of other brand is added. Then how much per kg does the other brand cost?

Description : By mixing two brands of dal and selling the mixture at the rate of Rs.354 per kg a shopkeeper makes a profit of 36%. If to every 4 kg of one brand costing Rs.400 per kg, 6kg of other brand is added. Then how much per kg does the other brand cost?

Last Answer : Let the cost price of other brand be Rs x' per kg  cost price of 10 kg = Rs (4 * 400 + 6 * x)  = Rs (1600 +6x)  Selling price of 10 kg = Rs (10 * 354 )  = Rs.3540  Therefore 3540 -(1600 + 6x)/ ... 6x/1600 + 6x = 0.36  1940 - 6x = 576 + 2.16x  x=167.15  so the cost of other brand = Rs.167.15

In 1 kg mixture of iron and carbon, 40% is carbon. How much iron should be added so that the proportion of carbon becomes 20% a)1.5kg b)2kg c)3kg d)5kg

Description :  In 1 kg mixture of iron and carbon, 40% is carbon. How much iron should be added so that the proportion of carbon becomes 20% a)1.5kg b)2kg c)3kg d)5kg e)1kg

Last Answer : E Quantity of the mixture : Quantity of iron = 20 : 20 = 1 : 1 Given that quantity of the mixture = 1 kg Hence quantity of iron to be added = 1 kg

What is the freezing point of water ?

Description : What is the freezing point of water ?

Last Answer : The freezing point of water is 0 degree Celsius.

When water is filled in a bottle and is allowed to freeze, the bottle breaks because _____? A. Water expands on freezing B. Bottle contracts at freezing point C. Temperature outside the bottle is less than that inside the bottle D. None of them

Description : When water is filled in a bottle and is allowed to freeze, the bottle breaks because _____? A. Water expands on freezing B. Bottle contracts at freezing point C. Temperature outside the bottle is less than that inside the bottle D. None of them

Last Answer : ANSWER: A

(3) prevents freezing of petrol Explanation: Ethylene glycol (IUPAC name: ethane-1,2-diol) is an organic compound widely used as an automotive antifreeze and a precursor to polymers. In its pure form, it is an odorless, colourless, syrupy, sweettasting liquid. Ethylene glycol is toxic, and ingestion can result in death. Due to its low freezing point ethylene glycol resists freezing. A mixture of 60% ethylene glycol and 40% water freezes at -45 degree C (- 49 degree F).

Description : (3) prevents freezing of petrol Explanation: Ethylene glycol (IUPAC name: ethane-1,2-diol) is an organic compound widely used as an automotive antifreeze and a precursor to polymers. In its pure form, it is ... A mixture of 60% ethylene glycol and 40% water freezes at -45 degree C (- 49 degree F).

Last Answer : Rust is - (1) A mixture of Fe₂O₃ and Fe(OH) ₂ (2) A mixture of FeO and Fe(OH)₂ (3) FeO only (4) A mixture of Fe₂O₃, 3H₂O and FeO

The freezing point of fresh water is - (1) 0°C (2) 4°C (3) 3°C (4) 5 C

Description : The freezing point of fresh water is - (1) 0°C (2) 4°C (3) 3°C (4) 5 C

Last Answer : (1) 0°C Explanation: Ocean water freezes just like freshwater, but at lower temperatures. Fresh water freezes at 32 degrees Fahrenheit but seawater freezes at about 28.4 degrees Fahrenheit, because of the salt in it.

Which of the following is not a property of heavy water? (1) Boiling point of heavy water is lower than that or ordinary water (2) Density of heavy water is higher than that of ordinary water (3) Freezing point of heavy water is higher than that of ordinary water (4) It produces corrosion

Description : Which of the following is not a property of heavy water? (1) Boiling point of heavy water is lower than that or ordinary water (2) Density of heavy water is higher than that of ordinary water (3) Freezing point of heavy water is higher than that of ordinary water (4) It produces corrosion

Last Answer : (1) Boiling point of heavy water is lower than that or ordinary water Explanation: Heavy water, formally called deuterium oxide or 2H90 or D20, is a form of water that contains the hydrogen ... well: for instance heavy water used in CANDLE reactors is 99.75% enriched by hydrogen atom-fraction.

The freezing point of fresh water is - (1) 4°C (2) 3°C (3) 5°C (4) 0°C

Description : The freezing point of fresh water is - (1) 4°C (2) 3°C (3) 5°C (4) 0°C

Last Answer : (4) 0°C Explanation: The freezing point of water is the temperature at which water changes phase from a liquid to a solid. Under normal conditions, ordinary water freezes at 0°C, or 32°F. ... or if there are impurities present in the water which could cause freezing point depression to occur.

Compared to fresh Water, the freezing point of sea water is - (1) Higher (2) Lower (3) Same (4) Depends on the sea from which the water is sourced

Description : Compared to fresh Water, the freezing point of sea water is - (1) Higher (2) Lower (3) Same (4) Depends on the sea from which the water is sourced

Last Answer : (2) Lower Explanation: Ocean water freezes just like freshwater, but at lower temperatures.

Freezing Point of Fresh water is

Description : Freezing Point of Fresh water is

Last Answer : 00C

Pour point and freezing point is equal for (A) Petrol (B) Diesel (C) Water (D) Crude petroleum

Description : Pour point and freezing point is equal for (A) Petrol (B) Diesel (C) Water (D) Crude petroleum

Last Answer : (C) Water

Freezing point of water is-----? A. 0 °C (Answer) B. -2 °C C. -4 °C D. None of above

Description : Freezing point of water is-----? A. 0 °C (Answer) B. -2 °C C. -4 °C D. None of above

Last Answer : A. 0 °C (Answer)