Description : If p, q, r are positive and are in A.P., the roots of quadratic equation px^2 + qx + r = 0 are real for : -Maths 9th
Last Answer : Given p,q,r are in A.P. then q=2p+r.....(1). Now px2+qx+r=0 will have real root then q2−4pr≥0. or, 4(p+r)2−4pr≥0 or, p2+r2−14pr≥0 or, r2−14rp+49p2≥48p2 or, (r−7p)2≥(43p)2 or, (pr−7)2≥(43)2 [ Since p=0 for the given equation to be quadratic] or, ∣∣∣∣∣pr−7∣∣∣∣∣≥43.