If a, b, c are distinct positive integers, then ax^(b–c) + bx^(c–a) + cx^(a–b) is -Maths 9th

If a, b, c are distinct positive integers, then ax^(b–c) + bx^(c–a) + cx^(a–b) is -Maths 9th
by

1 Answer

Answer :

answer:
by

Related questions

If (x^2 – 1) is a factor of ax^4 + bx^3 + cx^2 + dx + e, then : -Maths 9th

Description : If (x^2 – 1) is a factor of ax^4 + bx^3 + cx^2 + dx + e, then : -Maths 9th

Last Answer : answer:

In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

Description : In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

Last Answer : NEED ANSWER

In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

Description : In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

Last Answer : This answer was deleted by our moderators...

If x(square) - 1 is a factor of ax(cube) + bx(square) + cx + d,show that a+c=0. -Maths 9th

Description : If x(square) - 1 is a factor of ax(cube) + bx(square) + cx + d,show that a+c=0. -Maths 9th

Last Answer : Solution :-

If the roots of the equation x^3 – ax^2 + bx – c = 0 are three consecutive integers, then what is the smallest possible value of b ? -Maths 9th

Description : If the roots of the equation x^3 – ax^2 + bx – c = 0 are three consecutive integers, then what is the smallest possible value of b ? -Maths 9th

Last Answer : Let the roots of the equation x3 – ax2 + bx – c = 0 be (α – 1), α, (α + 1) ∴ S2 = (α – 1)α + α(α + 1) + (α + 1) ( ... ; 1 = b ⇒ 3α2 – 1 = b ∴ Minimum value of b = – 1, when α = 0.

If (x + k) is the HCF of ax^2 + ax + b and x^2 + cx + d, then what is the value of k ? -Maths 9th

Description : If (x + k) is the HCF of ax^2 + ax + b and x^2 + cx + d, then what is the value of k ? -Maths 9th

Last Answer : answer:

If the roots of the equation ax^2 + bx + c = 0 are equal in magnitude but opposite in sign, then which one of the following is correct ? -Maths 9th

Description : If the roots of the equation ax^2 + bx + c = 0 are equal in magnitude but opposite in sign, then which one of the following is correct ? -Maths 9th

Last Answer : answer:

If the sum of the roots of the equation ax^2 + bx + c = 0 is equal to the sum of their squares, then which one of the following is correct ? -Maths 9th

Description : If the sum of the roots of the equation ax^2 + bx + c = 0 is equal to the sum of their squares, then which one of the following is correct ? -Maths 9th

Last Answer : Given equation: ax2+bx+c=0 Let α and β be the roots of given quadratic equation Sum of the roots i.e. α+β=a−b Product of roots i.e. αβ=ac It is given that, Sum of the roots = Sum of squares of the roots i ... )2−2αβ i.e. a−b =(a−b )2−a2c i.e. −ab=b2−2ac i.e. ab+b2=2ac Hence, C is the correct option.

If (x – 2) is a common factor of the expressions x^2 + ax + b and x^2 + cx + d, -Maths 9th

Description : If (x – 2) is a common factor of the expressions x^2 + ax + b and x^2 + cx + d, -Maths 9th

Last Answer : answer:

Find the condition that one root of ax^2 + bx + c = 0 may be four times the other. -Maths 9th

Description : Find the condition that one root of ax^2 + bx + c = 0 may be four times the other. -Maths 9th

Last Answer : answer:

In quadratic equation ax^2 + bx + c = 0 , Identities the sum and product of Roots? -Maths 9th

Description : In quadratic equation ax^2 + bx + c = 0 , Identities the sum and product of Roots? -Maths 9th

Last Answer : If the two roots of the quadratic equation ax2 + bx + c = 0 obtained by the quadratic formula be denoted by a and b, then we have α = \(\frac{-b+\sqrt{b^2-4ac}}{2a},\) β = \(\frac{-b-\sqrt{b^2-4ac}}{2a}\) ∴ Sum of roots ... then α + β = - (- \(\frac{5}{6}\)) = \(\frac{5}{6}\), ab = \(\frac{7}{6}\).

Which one of the following is the equation whose roots are respectively three times the roots of the equation ax^2 + bx + c = 0 ? -Maths 9th

Description : Which one of the following is the equation whose roots are respectively three times the roots of the equation ax^2 + bx + c = 0 ? -Maths 9th

Last Answer : answer:

If the expression ax^2 + bx + c is equal to 4, when x = 0, leaves a remainder 4 when divided by x + 1 and leaves a -Maths 9th

Description : If the expression ax^2 + bx + c is equal to 4, when x = 0, leaves a remainder 4 when divided by x + 1 and leaves a -Maths 9th

Last Answer : Given exp. f(x) = ax2 + bx + c ∴ When x = 0, a.0 + b.0 + c = 4 ⇒ c = 4. The remainders when f(x) is divided by (x + 1) and (x + 2) respectively are f(–1) and f(–2). ∴ f( ... 2b = 2 ...(ii) Solving (i) and (ii) simultaneously we get, a = 1, b = 1.

If (x – 1) is a factor of Ax^3 + Bx^2 – 36x + 22 and 2^B = 64^A, find A and B ? -Maths 9th

Description : If (x – 1) is a factor of Ax^3 + Bx^2 – 36x + 22 and 2^B = 64^A, find A and B ? -Maths 9th

Last Answer : Solution:- x - 1 = 0 x = 1 Let p(x) = Ax³ + Bx² - 36x + 22 p(1) = A(1)³ + B(1)² - (36 × 1) + 22 ⇒ A + B - 36 + 22 =0 ⇒ A + B - 14 = 0 ⇒ A + B = 14 ....... ... 22 p(1) = 2(1)³ + 12(1)² - (36 × 1) + 22 ⇒ 2 + 12 - 36 + 22 ⇒ 36 - 36 = 0

The values of a, b and c respectively for the expression f(x) = x^3 + ax^2 + bx + c, if f(1) = f(2) = 0 and f(4) = f(0) are : -Maths 9th

Description : The values of a, b and c respectively for the expression f(x) = x^3 + ax^2 + bx + c, if f(1) = f(2) = 0 and f(4) = f(0) are : -Maths 9th

Last Answer : f′(x)=3x2+2ax+6 f(x)⇒f′(x)≥0 3x2+2ax+6≥0 ⇒D≤0 4[a2−3b]≤0 a2≤3b ∴P=6×6×6(16)×6​=3616​=94​ Answer.

If ax^3 + bx^2 + x – 6 has (x + 2) as a factor and leaves a remainder 4, when divided by (x – 2), the value of a and b respectively are : -Maths 9th

Description : If ax^3 + bx^2 + x – 6 has (x + 2) as a factor and leaves a remainder 4, when divided by (x – 2), the value of a and b respectively are : -Maths 9th

Last Answer : Let p(x) = ax³ + bx² + x - 6 A/C to question, (x + 2) is the factor of p(x) , and we know this is possible only when p(-2) = 0 So, p(2) = a(-2)³ + b(-2)² - 2 - 6 = 0 ⇒ ... --(2) solve equations (1) and (2), 4a = 0 ⇒a = 0 and b = 2 Then, equation will be 2x² + x - 6

If the equation x2 minus ax plus 2b equals 0 has prime roots where a and b are positive integers then a minus b is equal to?

Description : If the equation x2 minus ax plus 2b equals 0 has prime roots where a and b are positive integers then a minus b is equal to?

Last Answer : I think you mean the roots are prime numbers.Let the two roots be primes p and qThen the equation factorises to (x - p)(x - q) = 0 which can beexpanded to give:x² - (p + q)x + pq = 0Which comparing ... = 2(It doesn't matter if the other prime is even (2) or not as itcancels out from a - b.)

If a^2 + b^2 + c^2 = 1, x^2 + y^2 + z^2 = 1, where a, b, c, x, y, z are positive reals then ax + by + cz is -Maths 9th

Description : If a^2 + b^2 + c^2 = 1, x^2 + y^2 + z^2 = 1, where a, b, c, x, y, z are positive reals then ax + by + cz is -Maths 9th

Last Answer : answer:

If a, b, c, d are four distinct positive real numbers and if 3s = a + b + c + d, then -Maths 9th

Description : If a, b, c, d are four distinct positive real numbers and if 3s = a + b + c + d, then -Maths 9th

Last Answer : answer:

If a1, a2, ....., an are distinct positive real numbers such that a1 + a2 + ..... + an = 1, then -Maths 9th

Description : If a1, a2, ....., an are distinct positive real numbers such that a1 + a2 + ..... + an = 1, then -Maths 9th

Last Answer : answer:

For three distinct positive numbers p, q and r, if p + q + r = a, then -Maths 9th

Description : For three distinct positive numbers p, q and r, if p + q + r = a, then -Maths 9th

Last Answer : answer:

If ax + by = a2 – b2 and bx + ay = 0, find the value of (x + y). -Maths 10th

Description : If ax + by = a2 – b2 and bx + ay = 0, find the value of (x + y). -Maths 10th

Last Answer : Given, ax+by=a2−b2......(1) bx+ay=0.......(2). Now adding (1) and (2) we get, x(a+b)x+(a+b)y=a2−b2 or, (a+b)(x+y)=a2−b2 or, x+y=a−b.

The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Description : An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Last Answer : As there are 200 integers, total number of exhaustive, mutually exclusive and equally likely cases, i.e, n(S) = 200 Let A : Event of integer chosen from 1 to 200 being divisible by 6⇒ n(A) = 33 \(\bigg(rac{200}{6}=33rac{1}{3}\ ... (rac{25}{200}\) - \(rac{8}{200}\) = \(rac{50}{200}\) = \(rac{1}{4}\).

Let ABCD be a parallellogram. Let m and n be positive integers such that n < m < 2n. Let AC = 2 mn -Maths 9th

Description : Let ABCD be a parallellogram. Let m and n be positive integers such that n < m < 2n. Let AC = 2 mn -Maths 9th

Last Answer : answer:

If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.

Description : If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.

Last Answer : If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.

If the roots of a quadratic equation `ax^(2) + bx + c` are complex, then `b^(2) lt "____"`

Description : If the roots of a quadratic equation `ax^(2) + bx + c` are complex, then `b^(2) lt "____"`

Last Answer : If the roots of a quadratic equation `ax^(2) + bx + c` are complex, then `b^(2) lt "____"`

If the discriminant of the equation `ax^(2) + bx + c = 0` is greater than zero, then the roots are `"______"`.

Description : If the discriminant of the equation `ax^(2) + bx + c = 0` is greater than zero, then the roots are `"______"`.

Last Answer : If the discriminant of the equation `ax^(2) + bx + c = 0` is greater than zero, then the roots are `"______"`.

If `x = 1` is a solution of the quadratic equation `ax^(2) - bx + c = 0`, then b is equal to `"_______"`.

Description : If `x = 1` is a solution of the quadratic equation `ax^(2) - bx + c = 0`, then b is equal to `"_______"`.

Last Answer : If `x = 1` is a solution of the quadratic equation `ax^(2) - bx + c = 0`, then b is equal to `"_______"`.

The roots of a quadratic equation `ax^(2) + bx + c=0` are 1 and `c/a`, then `a + b = "_____"`.

Description : The roots of a quadratic equation `ax^(2) + bx + c=0` are 1 and `c/a`, then `a + b = "_____"`.

Last Answer : The roots of a quadratic equation `ax^(2) + bx + c=0` are 1 and `c/a`, then `a + b = "_____"`.

If x, y, z are distinct positive numbers different from 1, such that -Maths 9th

Description : If x, y, z are distinct positive numbers different from 1, such that -Maths 9th

Last Answer : (d) 1logy x. logz x - logx x = \(rac{ ext{log}\,x}{ ext{log}\,y}\) . \(rac{ ext{log}\,x}{ ext{log}\,z}\) - 1 = \(rac{ ext{(log}\,x^2)}{ ext{log}\,y.\, ext{log}\,z}\) - 1Similarly, logx y.logz y - logy y = ... log z = 0 (if a + b + c = 0, then a3 + b3 + c3 = 3abc) ⇒ log xyz = 0 ⇒ xyz = 1.

For three distinct positive real numbers a, b, c (1 + a^3) (1 + b^3) (1 + c^3) is greater than -Maths 9th

Description : For three distinct positive real numbers a, b, c (1 + a^3) (1 + b^3) (1 + c^3) is greater than -Maths 9th

Last Answer : answer:

How would you answer this questionSketch the graph of y = I ax+b I and y = I cx+d ISolve I ax+b I > or equal to I cx+d I?

Description : How would you answer this questionSketch the graph of y = I ax+b I and y = I cx+d ISolve I ax+b I > or equal to I cx+d I?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

X, Y are the mid-points of opposite sides AB and DC of a parallelogram ABCD. AY and DX are joined intersecting in P. CX and BY are joined -Maths 9th

Description : X, Y are the mid-points of opposite sides AB and DC of a parallelogram ABCD. AY and DX are joined intersecting in P. CX and BY are joined -Maths 9th

Last Answer : answer:

If the roots of the equation `ax^(2) + bx + c = 0` are in the ratio of `3 : 4`,

Description : If the roots of the equation `ax^(2) + bx + c = 0` are in the ratio of `3 : 4`,

Last Answer : If the roots of the equation `ax^(2) + bx + c = 0` are in the ratio of `3 : 4`,

A body is projected from ground with speed 20 m/s making an angle of `45^(@)` with horizontal. The equation of path is `h = Ax-Bx^(2)`, where h is hei

Description : A body is projected from ground with speed 20 m/s making an angle of `45^(@)` with horizontal. The equation of path is `h = Ax-Bx^(2)`, where h is hei

Last Answer : A body is projected from ground with speed 20 m/s making an angle of `45^(@)` with horizontal. The equation of path ... B. 5 : 1 C. 1 : 40 D. 40 : 1

3a plus 3b plus ax plus bx?

Description : 3a plus 3b plus ax plus bx?

Last Answer : 6a square plus b square

MOVE AX BX in this LINES OF CODE what type of error is declared: a. Undeclared identifier MOVE b. undeclared identifier AX c. Accept as a command d. Not look in symbol table

Description : MOVE AX BX in this LINES OF CODE what type of error is declared: a. Undeclared identifier MOVE b. undeclared identifier AX c. Accept as a command d. Not look in symbol table

Last Answer : a. Undeclared identifier MOVE

What is the output of the following code AL= -28 decimal, BL=59 decimal IMUL BL AX=? , MSB=? a) AX= F98CH, MSB=1. b) AX= 1652, MSB=1. c) BX F9C8H, MSB=1. d) BX= 1652, MSB=1.

Description : What is the output of the following code AL= -28 decimal, BL=59 decimal IMUL BL AX=? , MSB=? a) AX= F98CH, MSB=1. b) AX= 1652, MSB=1. c) BX F9C8H, MSB=1. d) BX= 1652, MSB=1.

Last Answer : a) AX= F98CH, MSB=1.

If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Description : If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Last Answer : Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point. Now, put x = 3 and y = 4 in given equation, we get 3(4) = a (3)+7 ⇒ 12 = 3a+7 ⇒ 3a = 12 – 7 ⇒ 3a = 5 Hence, the value of a is 5/3.

If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Description : If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Last Answer : Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point. Now, put x = 3 and y = 4 in given equation, we get 3(4) = a (3)+7 ⇒ 12 = 3a+7 ⇒ 3a = 12 – 7 ⇒ 3a = 5 Hence, the value of a is 5/3.

If one root of the equation ax^2 + x – 3 = 0 is –1, then what is the other root ? -Maths 9th

Description : If one root of the equation ax^2 + x – 3 = 0 is –1, then what is the other root ? -Maths 9th

Last Answer : answer:

If a^2 = by + cz, b^2 = cz + ax, c^2 = ax + by, then the value of -Maths 9th

Description : If a^2 = by + cz, b^2 = cz + ax, c^2 = ax + by, then the value of -Maths 9th

Last Answer : answer:

Let R be a relation on the set of integers given by a = 2^k .b for some integer k. Then R is -Maths 9th

Description : Let R be a relation on the set of integers given by a = 2^k .b for some integer k. Then R is -Maths 9th

Last Answer : (c) equivalence relationGiven, a R b = a = 2k .b for some integer. Reflexive: a R a ⇒ a = 20.a for k = 0 (an integer). True Symmetric: a R b ⇒ a = 2k b ⇒ b = 2-k . a ⇒ b R a as k, -k are both ... = 2k1 + k2 c, k1 + k2 is an integer. ∴ a R b, b R c ⇒ a R c True ∴ R is an equivalence relation.

If n integers taken at random are multiplied together, then the probability that the last digit of the product is 1, 3, 7 or 9 is -Maths 9th

Description : If n integers taken at random are multiplied together, then the probability that the last digit of the product is 1, 3, 7 or 9 is -Maths 9th

Last Answer : (d) 226 × 52C26 | 104C26Since there are 52 distinct cards in a deck and each distinct card is 2 in number.∴2 decks will also contain only 52 distinct cards, two each.∴ Probability that the player gets all distinct cards = \(rac{^{52}C_{26} imes2^{26}}{^{104}C_{26}}\).

Express X+2=0 in the form of ax+by+C=0 -Maths 9th

Description : Express X+2=0 in the form of ax+by+C=0 -Maths 9th

Last Answer : 1[x] + 0[y] + 2=0

Express x+2=0 in ax+by+c=0 -Maths 9th

Description : Express x+2=0 in ax+by+c=0 -Maths 9th

Last Answer : x+2y-c=0 is the answer of x+2

When f(x) = x4 - 2x3 + 3x2 - ax is divided by x + 1 and x - 1 , we get remainders as 19 and 5 respectively . -Maths 9th

Description : When f(x) = x4 - 2x3 + 3x2 - ax is divided by x + 1 and x - 1 , we get remainders as 19 and 5 respectively . -Maths 9th

Last Answer : When f(x) is divided by (x+1) and (x-1) , the remainders are 19 and 5 respectively . ∴ f(-1) = 19 and f(1) = 5 ⇒ (-1)4 - 2 (-1)3 + 3(-1)2 - a (-1) + b = 19 ⇒ 1 +2 + 3 + a + b = 19 ∴ a + b = 13 ------- ... + 3x2 - 5x + 8 ⇒ f(3) = 34 - 2 33 + 3 32 - 5 3 + 8 = 81 - 54 + 27 - 15 + 8 = 47

ABCD is a parallelogram and line segments AX, CY bisect the angles A and C, respectively. -Maths 9th

Description : ABCD is a parallelogram and line segments AX, CY bisect the angles A and C, respectively. -Maths 9th

Last Answer : Since opposite angles are equal in a parallelogram . Therefore , in parallelogram ABCD , we have ∠A = ∠C ⇒ 1 / 2 ∠A = 1 / 2 ∠C ⇒ ∠1 = ∠2 ---- i) [∵ AX and CY are bisectors of ∠A and ∠C ... intersects AX and YC at A and Y such that ∠1 = ∠3 i.e. corresponding angles are equal . ∴ AX | | CY .