(i) Lateral surface area of cubical box = 4a2 = 4 x 102 = 400 cm2 Lateral surface area of cuboidal box = 2h (l + b) = 2 x 8(12.5 +10) = 16 X 22.5 = 360 cm2 Thus, lateral surface area of cubical box is greater by (400 cm2 - 360 cm2) = 40 cm2 (ii) Total surface area of cubical box = 6a2 = 6 x 102 cm2 = 600 cm2 Total surface area of cuboidal box = 2 (lb + bh + hl) = 2(12.5 x 10 + 10 x 8 + 8 x 12.5) = 2(125 + 80 + 100) = 2 x 305cm2 = 610 cm2 Thus, total surface area of cuboidal box is greater by (610 - 600) cm2 = 10 cm2