Let PQ be a chord of a circle with centre O and radius 13cm such that PQ = 24cm. From O, draw OM perpendicular PQ and join OP. As, the perpendicular from the centre of a circle to a chord bisects the chord. ∴ PM = 12cm In △OMP, we have OP2 = OM2 + PM2 ⇒ 132 = OM2 + 122 ⇒ OM = 5cm. Hence, the distance of the chord from the centre is 5cm.