If one angle of a triangle is equal to the sum of the other two angles, then the triangle is -Maths 9th

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(d) Let the angles of a AABC be ∠A, ∠B and ∠C. Given, ∠A = ∠B+∠C …(i) InMBC, ∠A+ ∠B+ ∠C-180° [sum of all angles of a triangle is 180°]…(ii) From Eqs. (i) and (ii), ∠A+∠A = 180° ⇒ 2 ∠A = 180° ⇒ 180° /2 ∠A = 90° Hence, the triangle is a right triangle.

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Description : If one angle of a triangle is equal to the sum of the other two angles, then the triangle is -Maths 9th

Last Answer : (d) Let the angles of a AABC be ∠A, ∠B and ∠C. Given, ∠A = ∠B+∠C …(i) InMBC, ∠A+ ∠B+ ∠C-180° [sum of all angles of a triangle is 180°]…(ii) From Eqs. (i) and (ii), ∠A+∠A = 180° ⇒ 2 ∠A = 180° ⇒ 180° /2 ∠A = 90° Hence, the triangle is a right triangle.

Description : An exterior angle of a triangle is 110° and the two interior opposite angles are equal find the interior opposite angels -Maths 9th

Last Answer : each interior opposite angles are 55

Description : An exterior angle of a triangle is 110° and the two interior opposite angles are equal find the interior opposite angels -Maths 9th

Last Answer : each interior opposite angles are 55

Description : An exterior angle of a triangle is 110° and its two interior opposite angles are equal. Find each of these equal angles. -Maths 9th

Last Answer : 2x=110 X=55 x+x+y=180 110+y=180 Y=70

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Description : ABC is an isosceles triangle in which AB=AC.AD bisects exterior angles PAC and CD parallel AB.Prove that-i)angle DAC=angle BAC ii)∆BCD is a parallelogram -Maths 9th

Last Answer : AB =AC(given) Angle ABC =angle ACB (angle opposite to equal sides) Angle PAC=Angle ABC +angle ACB (Exterior angle property) Angle PAC =2 angle ACB - - - - - - (1) AD BISECTS ANGLE PAC. ANGLE ... AND AC IS TRANSVERSAL BC||AD BA||CD (GIVEN ) THEREFORE ABCD IS A PARALLEGRAM. HENCE PROVED........

Description : Angles of a triangle are in the ratio 2:4:3. The smallest angle of the triangle is -Maths 9th

Last Answer : (b) Given, the ratio of angles of a triangle is 2 : 4 : 3. Let the angles of a triangle be ∠A, ∠B and ∠C. ∠A = 2x, ∠B = 4x ∠C = 3x , ∠A+∠B+ ∠C= 180° [sum of all the angles of a triangle is 180°] 2x ... ∠B = 4x = 4 x 20° = 80° ∠C = 3x = 3 x 20° = 60° Hence, the smallest angle of a triangle is 40°.

Description : ABC is an isosceles triangle in which AB=AC.AD bisects exterior angles PAC and CD parallel AB.Prove that-i)angle DAC=angle BAC ii)∆BCD is a parallelogram -Maths 9th

Last Answer : AB =AC(given) Angle ABC =angle ACB (angle opposite to equal sides) Angle PAC=Angle ABC +angle ACB (Exterior angle property) Angle PAC =2 angle ACB - - - - - - (1) AD BISECTS ANGLE PAC. ANGLE ... AND AC IS TRANSVERSAL BC||AD BA||CD (GIVEN ) THEREFORE ABCD IS A PARALLEGRAM. HENCE PROVED........

Description : Angles of a triangle are in the ratio 2:4:3. The smallest angle of the triangle is -Maths 9th

Last Answer : (b) Given, the ratio of angles of a triangle is 2 : 4 : 3. Let the angles of a triangle be ∠A, ∠B and ∠C. ∠A = 2x, ∠B = 4x ∠C = 3x , ∠A+∠B+ ∠C= 180° [sum of all the angles of a triangle is 180°] 2x ... ∠B = 4x = 4 x 20° = 80° ∠C = 3x = 3 x 20° = 60° Hence, the smallest angle of a triangle is 40°.

Description : Sum of the angle of triangle is 180 -Maths 9th

Last Answer : YES SUM OF A TRIANLE IS 180

Description : Sum of the angle of triangle is 180 -Maths 9th

Last Answer : YES SUM OF A TRIANGLE IS 180

Description : state and prove angle sum property of triangle -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Sum of the angle of triangle is 180 -Maths 9th

Last Answer : YES SUM OF A TRIANLE IS 180

Description : Sum of the angle of triangle is 180 -Maths 9th

Last Answer : YES SUM OF A TRIANGLE IS 180

Description : state and prove angle sum property of triangle -Maths 9th

Last Answer : This answer was deleted by our moderators...

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Description : If the angles of a triangle are in the ratio 5:3:7, then the triangle is -Maths 9th

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Description : PQRS is a square. A is a point on PS ,B is a point on PQ,C is a point on QR. ABC is a triangle inside square PQRS. Angle abc = 90° . If AP=BQ=CR then prove that angle BAC =45° -Maths 9th

Last Answer : This is the sketch of the question but its hard to answer.

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