The maximum demand of consumer is 2 kW and his daily energy consumption is 20 units. Its Load Factor is

The maximum demand of consumer is 2 kW and his daily energy consumption is 20 units. Its Load Factor is (1) 10.15% (2) 41.6 % (3) 50 % (4) 60% 
by

1 Answer

Answer :

Total maximum demand of energy in a day = 2kw*24= 48 units

Consumer consumption is 20 units .

Load factor = (number of units utilizing)/(total max. demand) 

    = 20/48 = 41.6%
by
by
Load factor = average load / max demand


Average demand =2/24hours

Max demand = 20
Load factor = (2/24) / 20 = 4.16
And in % =41.6

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