Description : If x = log2a a, y = log3a2a, z = log4a3a, then xyz – 2yz equals -Maths 9th
Last Answer : (d) -1\(x\) = log2a a = \(rac{ ext{log}\,a}{ ext{log}\,2a}\), y = log3a 2a = \(rac{ ext{log}\,2a}{ ext{log}\,3a}\)z = log4a 3a = \(rac{ ext{log}\,3a}{ ext{log}\,4a}\)∴ xyz - 2yz = \(rac{ ext{log}\ ... \(rac{ ext{log}\,(4a)^{-1}}{ ext{log}\,(4a)}\) = \(rac{-1. ext{log}\,4a}{ ext{log}\,4a}\) = -1.