Description : The endpoint A of a line segment AB is (3 , -1). If midpoint of AB is (5,7) then the coordinates of the point B are: (a) (7,13) (b) (7,15) (c) (4,3) (d) (4,4)
Last Answer : (b) (7,15)
Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th
Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm
Description : In the given figure, AB is the diameter where AP = 12 cm and PB = 16 cm. If the value of π is taken 3, what is the perimeter of the shaded region? (a) 58 cm (b) 116 cm (c) 29 cm (d) 156 cm
Last Answer : (a) 58 cm
Description : A (5,-1) , B (-3,-2) and C (-1,8) are the vertices of ∆ ABC . The median from A meets BC at D ,then the coordinates of the point D are: (a) (-4,6) (b) (2,7/2) (c) (1,-3/2) (d) (-2,3)
Last Answer : (d) (-2,3)
Description : Points P,Q,R(in this order) divide the line joining the points A(-2,2) and B(2,8) into four equal parts. The coordinates of the point Q are: (a) (-1,7/2) (b) (1,13/2) (c) (0,5) (d) (5,1/2)
Last Answer : (c) (0,5)
Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2
Last Answer : (c) 77 cm 2
Description : If b = 4 units ,the coordinates of point A on the side PQ which divides PQ internally in the ratio 1: 3 are: (a) (1,0) (b) (3,3) (c) (3,0) (d) (1,1)
Last Answer : (a) (1,0)
Description : The coordinates of the point X are: (a) ( - 3,3) (b) (3, - 3) (c) (3,3) (d) (-3,-3)
Last Answer : (c) (3,3)
Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th
Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.
Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th
Last Answer : ∵ The perpendicular drawn from the centre to the chord bisects it. ∴ AM = 1/2 AB = 1/2 × 30 cm = 15 cm Also, OA = 1/2 AD = 1/2 × 34 cm = 17 cm In rt. △OAM, we have OA2 = OM2 + AM2 172 = OM2 + 152 ⇒ 289 = OM2 + 225 ⇒ OM2 = 289 - 225 ⇒ OM2 = 64 ⇒ OM = √64 = 8 cm
Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th
Last Answer : (d) Given, AD = 34 cm and AB = 30 cm In figure, draw OL ⊥ AB. Since, the perpendicular from the centre of a circle to a chord bisects the chord.
Description : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.
Last Answer : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.
Description : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.
Last Answer : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.
Description : In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is a) 4/3 b) 14/3 c) 11/3 d) 9/12
Last Answer : a) 4/3
Description : The coordinates of the vertices of region bounded by lines 3x - y = 5; x+ 2y = 4 and Y-axis are: (a) A(2,0); B(5,0) and C(1,2) (b) A(2,0); B(-5,0) and C(1,2) (c) A(0,2); B(0,-5) and C(2,1) (d) A(0,2); B(0,5) and C(2,1)
Last Answer : (c) A(0,2); B(0,-5) and C(2,1)
Description : The area of the circle that can be inscribed in a square of side 6 cm is (a) 36 π cm 2 (b) 18 π cm 2 (c) 12 π cm 2 (d) 9 π cm 2
Last Answer : (d) 9 π cm 2
Description : How can I obtain the volume of an irregular body if I just know the vertex coordinates of the irregular body?
Last Answer : answer:There isn't an easy formula, otherwise you would have most likely gotten an answer last time you asked this. So if you have coordinates for vertices, from there you can start to create regular objects ... where you have measured the volume of the total space. It is not easy, but it is doable.
Description : The coordinates of the points where 2x + 5y – 10 =0 meets y axis is e) (0 , 2) f) (0 , -2) g) (2 , 2) h) (-2 , -2)
Last Answer : e) (0 , 2)
Description : The coordinates of the points where 2x + 5y – 10 =0 meets y axis is a) (0 , 2) b) (0 , -2) c) (2 , 2) d) (-2 , -2)
Last Answer : a) (0 , 2)
Description : The coordinates of the vertex R of the square PQRS are: (a) (0,b) (b) (b,0) (c) (0,0) (d) (b,b)
Last Answer : (d) (b,b)
Description : The coordinates of the points A and B are a) (0,4) and (2,0) b) (4,0) and (0,2) c) (0,4) and (0,2) d) (4,0) and (2,0)
Last Answer : b) (4,0) and (0,2)
Description : Point A(5, 1) is the centre of the circle with radius 13 units. AB ⊥ chord PQ. B is (2, –3). The length of chord PQ is -Maths 9th
Last Answer : (c) ParallelogramAB = \(\sqrt{(4-7)^2+(5-6)^2}\) = \(\sqrt{9+1}\) = \(\sqrt{10}\)BC = \(\sqrt{(7-4)^2+(6-3)^2}\) = \(\sqrt{9+9}\) = \(3\sqrt2\)CD =\(\sqrt{(4-1)^2+(3-2) ... = \(2\sqrt{13}\)AB = CD, BC = AD and AC ≠ BD ⇒ opposite sides are equal and diagonals are not equal. ⇒ ABCD is a parallelogram.
Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th
Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.
Description : In given figure, AD = 3 cm, AE = 5 cm, BD = 4 cm, CE = 4 cm, CF = 2 cm, BF = 2.5 cm, then (a) DE || BC (b) DF || AC (c) EF || AB (d) none of
Last Answer : (c) EF || AB
Description : D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE || BC. Then, length of DE (in cm) is (a) 2.5 (b) 3 (c) 5 (d) 6
Last Answer : (b) 3
Description : In|| AB. If CD = 3 cm, EC = 4 cm, BE = 6 cm, then DA is equal to (a) 7.5 cm (b) 3 cm (c) 4.5 cm (d) 6 cm
Last Answer : (c) 4.5 cm
Description : The distance AB is: (a) 7 units (b) 5 units (c) 3 units (d) 2 units
Last Answer : (b) 5 units
Description : ABCD is a parallelogram with diagonal AC If a line XZ is drawn such that XZ ∥ AB, then BX/XC = ? (a) (AY/AC) (b) DZ/AZ (c) AZ/ZD (d) AC/AY Answer: (c) AZ/ZD 13. In the given figure, value of x (in cm) is (a) 5cm (b) 3.6 cm (c) 3.2 cm (d) 10 cm
Last Answer : (a) 5cm
Description : If ΔABC ~ ΔEDF and ΔABC is not similar to ΔDEF then which of the following is not true? (a) BC.EF = AC.FD (b) AB.EF = AC.DE (c) BC.DE = AB.EF (d) BC.DE = AB.FD
Last Answer : (c) BC.DE = AB.EF
Description : In the adjoining figure, if ∠BAC = 90° and AD ⊥ BC, then (а) BD.CD = BC2 (b) AB.AC = BC2 (c) BD.CD = AD2 (d) AB.AC = AD2
Last Answer : (c) BD.CD = AD2
Description : The pair of equations ax+by+c=0 and dx+ey+c=0 represent the equations with infinitely many solutions if (a)ad=be (b)ae=bd (c)ab=de (d)ac=de
Last Answer : (b)ae=bd
Description : The pair of equations ax+2y=7 and 3x+by=16 represent parallel lines if (a)a=b (b)3a=2b (c)ab=6 (d)2a=3b
Last Answer : (c)ab=6
Description : In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. The value of tan C is: a 12/7 b 24/7 c 20/7 d 7/24
Last Answer : b 24/7
Description : ABCE is an isosceles trapezoid and ACDE is a rectangle. AB = 10 and EC = 20. What is the length of AE?
Last Answer : Answer: AE = 10.
Description : If AOB is a diameter of a circle [Fig. 10.8] and C is a point on the circle, then prove that AC* +BC*=AB*. -Maths 9th
Last Answer : Solution :- As, ∠ C = 90° (Angle in the semicircle) ∴ AC2 + BC2 = AB2 (By Pythagoras Theorem)
Description : If the radius of a circle is doubled, what about its area?(a) Area is 2 times (b) Area is 4 times (c) Area is half (d) does not change
Last Answer : (b) Area is 4 times
Description : In the given figure, OACB is a quadrant of a circle of radius 7 cm. The perimeter of the quadrant is (a) 11 cm (b) 18 cm (c) 25 cm (d) 36 cm
Last Answer : (c) 25 cm
Description : What is the area of the corresponding major sector of a circle of radius 28 cm and the central angle 45 o ? (a) 4312 cm 2 (b) 2156 cm 2 (c) 1256 cm 2 (d) 3412 cm 2
Last Answer : (b) 2156 cm 2
Description : A thin wire is in the shape of a circle of radius 77 cm. It is bent into a square. What is the side of the square? (a) 168 cm (b) 242 cm (c) 121 cm (d) 336 cm
Last Answer : (c) 121 cm
Description : If the perimeter of a circle is equal to that of a square, then the ratio of their areas is (a) 22:7 (b) 14:11 (c) 7:22 (d) 11:14
Last Answer : (b) 14:11
Description : Two persons of masses 55 kg and 65 kg respectively, are at the opposite ends of a boat. The length of the boat is 3.0 m and weighs 100 kg. The 55 kg man walks up to the 65 kg man and sits with him. If the boat is in still water the centre of mass of the system shifts by
Last Answer : (4) zero
Description : Draw a circle of diameter 6.4 cm. Then draw two tangents to the circle from a point P at a distance 6.4 cm from the centre of the circle. -Maths 9th
Last Answer : clear .
Description : If diameter of a wheel is 1.26 m, what the distance covered in 500 revolutions? (a) 1.38 km (b) 4.64 km (c) 2.46 km (d) 1.98 km
Last Answer : (d) 1.98 km
Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th
Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm
Description : A line AB with end point A (2,3) & B (7,8) is to be rotated about origin by 300 inclockwise direction. Determine the coordinates of end points S of rotated line. a.(3.232, 2.598) b.(5.232, 3.598) c.(3.232, 1.298) d.(3.232, 1.598)
Last Answer : d.(3.232, 1.598)
Description : Find the smallest number in a GP whose sum is 38 and product 1728? (a) 12 (b) 20 (c) 8 (d) none of these
Last Answer : (c) 8