In a spring mass system of mass m and stiffness k, the end of the spring are securely fixed and
mass is attached to intermediate point of spring. The natural frequency of longitudinal vibration of
the system
A) Is maximum when mass is attached to mid point of the spring
B) Is minimum when mass is attached to mid point of the spring
C) Decreases as the distance from the top end where mass is attached decreases
D) Decreases as the distance from the bottom end where mass is attached decreases

1 Answer

Answer :

B) Is minimum when mass is attached to mid point of the spring

Related questions

Description : If the spring mass system with m and spring stiffness k is taken to very high altitude, the natural frequency of longitudinal vibrations * 1 point (A) increases (B) decreases (C) remain unchanged (D) may increase or decrease depending upon the value of the mass

Last Answer : (C) remain unchanged

Description : If the spring mass system with m and spring stiffness k is taken to very high altitude , the natural frequency of longitudinal vibrations A) Increases B) Decreases C) Remain unchanged D) May be increase or decrease depending upon the value of the mass

Last Answer : C) Remain unchanged

Description : In the spring mass system if the mass of the system is doubled with spring stiffness halved, the natural frequency of longitudinal vibration A) Remained unchanged B) Is doubled C) Is halved D) Is quadruped

Last Answer : C) Is halved

Description : A mass of 1 kg is attached to two identical springs each with stiffness k = 20 kN/m as shown in the figure. Under frictionless condition, the natural frequency of the system in Hz is close to * 1 point (A) 32 (B) 23 (C) 16 (D) 11

Last Answer : (A) 32

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Last Answer : C 6.16 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Last Answer : D 60 rad/sec

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Last Answer : C. 6.16 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Last Answer : C. 11.14 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Last Answer : C) 6.16 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

Last Answer : ( C )6.16 Hz

Description : A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

Last Answer : B. 1.59 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

Last Answer : c. 6.16 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Last Answer : (C) 11.14 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

Description : In spring mass experiment, the natural frequency of 10 kg mass was found to be 12 rad/sec. the stiffness of the spring is A. 800 N/m B. 1200 N/m C. 1440 N/m D. 2000 N/m

Last Answer : C. 1440 N/m

Description : Reduction in vibration amplitude after one complete cycle of single degree free vibration with dry friction damping is_____, if where F"= frictional force between mass and surface and k =stiffness of the system. a)4F/k a b) 2f/K C) 3F/k D)8F/k

Last Answer : a)4F/k

Description : A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Last Answer : B 30 rad/sec

Description : The natural frequency of the spring mass is inversely proportional to A. Stiffness B. Mass C. Density D. Deflection

Last Answer : B. Mass

Description : In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Last Answer : C) 30 & 40

Description : A cantilever shaft having 50 mm diameter and length of 300 mm has a disc of mass 100 kg at its free enD. The Young’s modulus for the shaft material is 200 GN/m 2 . Calculate the natural longitudinal frequency in Hz. A. 575B. 625 C. 525 D. 550

Last Answer : A. 575

Description : A cantilever shaft having 50 mm diameter and length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 2 . Calculate the natural longitudinal frequency in Hz. a) 575 b) 625 c) 525 d) 550

Last Answer : a) 575

Description : Critical speed of shaft and disc system A) Is equal to natural frequency of the system in transverse vibration B) Is equal to natural frequency of the system in torsional vibration C) Is ... of the system in longitudinal vibration D) Bears no relationship to any of the system natural frequency

Last Answer : A) Is equal to natural frequency of the system in transverse vibration

Description : A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Last Answer : B. 0.15 m

Description : The natural frequency (in Hz) of free longitudinal vibrations is equal to a) Square root (k/m) / (2π) b) Square root (g/δ) / (2π) c) 0.4985/δ d) all of the mentioned

Last Answer : d) all of the mentioned

Description : A vehicle suspension system consists of a spring and a damper. Stiffness of spring is 3.5 KN/m and damping constant of damper is 400Ns/m. If mass is 50 kg, then damping factor is A 0.606 B 0.10 C 0.666 D 0.471

Last Answer : D 0.471

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : A 9810 N/m

Description : A vibrating system having mass 1kg, a spring of stiffness 1000N/m and damping factor of 0.632 and it is put to harmonic excitation of 10N. Find the amplitude at resonance. A 0.079 B 7.9C 0.056 D 0.00791

Last Answer : D 0.00791

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : D 9801 N/m

Description : A vertical spring-mass system has a mass of 0.5 kg and an initial deflection of 0.2 cm. Find the spring stiffness. A. 345 N/m B. 245 N/m C. 3452 N/mD. 2452 N/m

Last Answer : D. 2452 N/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of A 0.01m. Find the spring stiffness for the same system. (A) 9810 N/m (B) 8910 N/m (C)1098 N/m (D) 9801 N/m

Last Answer : A) 9810 N/m

Description : A gun barrel of mass 600 Kg has a recoil spring of stiffness 294 KN/m. If the barrel recoils 1.3 m on firing, what will be the initial recoil velocity of the barrel? (A) 28.77 m/s (B) 32.77 m/s (C) 35.77 m/s (D) 40.77 m/s

Last Answer : (A) 28.77 m/s

Description : The natural frequency of a system is a function of A The stiffness of the system B The mass of the system C Both A and B D None of the mentioned

Last Answer : C Both A and B

Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Last Answer : A 100

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above

Last Answer : C. 42 x 10 3 N-s/m

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

Last Answer : c. 42 x 10 3 N-s/m

Description : A spring-mass system has a natural frequency of 10 rad/sec. When the spring constant is reduced by 800 N/m, the frequency is altered by 45 percent. Find the mass and spring constant of the original system. a)11.47kg and 1147.95N/m b)8.95kg and 895.25N/m c) 7.265kg and 726.5N/m d)None

Last Answer : a)11.47kg and 1147.95N/m

Description : The natural frequency of a spring-mass system on earth is ωn. The natural frequency of this system on the moon (g of moon = g of earth /6) is * 1 point (A) ωn (B) 0.408ωn (C) 0.204ωn (D) 0.167ωn

Last Answer : (A) ωn

Description : Equivalent stiffness of spring connected in paralled having stiffness k1 and k2 can be given as A) K = k1+ k2 B) K = k1- k2 C) 1/k = 1/k1 + 1/k2 D) 1/k = 1/k1 - 1/k2

Last Answer : A) K = k1+ k2

Description : Which of the following relations is true when springs are connected parallelly? where K = spring stiffness a.Ke= K1 +K2 b. (1/Ke)=(1/K1)+(1/K2) c.Ke= (1/K1)+(1/K2) d.None of the above

Last Answer : a.Ke= K1 +K2

Description : f the mass is of 10 Kg, find the natural frequency in Hz of the free longitudinal vibrations. The displacement is 0.01mm. a) 44.14 b) 49.85 c) 43.43 d) 46.34

Last Answer : b) 49.85

Description : The natural frequency (in Hz) of free longitudinal vibrations is equal to a) 1/2π√s/m b) 1/2π√g/δ c) 0.4985/δ d) all of the mentioned

Last Answer : d) all of the mentioned

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A. 3500 N/m B. 1166 N/mC. 857.63 N/m D. None of the above

Last Answer : C. 857.63 N/m

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A) 3500 N/m B) 1166 N/m C) 857.63 N/m D) None of the above

Last Answer : C) 857.63 N/m

Description : Calculate equivalent stiffness of the spring for the system shown below, which has spring stiffness of 3000 N/m a. 1000 N/m b. 2250 N/m c. 2000 N/m d. None of the above

Last Answer : b. 2250 N/m

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m a. 3500 N/m b. 1166 N/m c. 857.63 N/m d. None of the above

Last Answer : c. 857.63

Description : The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that A Its natural frequency is very low in comparison to the frequency ... is equal to the frequency of vibration D Measurement of vibratory motion is without any reference point

Last Answer : C Its natural frequency is equal to the frequency of vibration

Description : The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that a) its natural frequency is very low in comparison to the frequency ... is equal to the frequency of vibration d) measurement of vibratory motion is without any reference point

Last Answer : c) its natural frequency is equal to the frequency of vibration

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Last Answer : B 600 N/m

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Last Answer : B 600 N/m