How do you check 52 divided by 7?

1 Answer

Answer :

7.4286

Related questions

Description : In how many ways can a pack of 52 cards be divided equally among four players in order? -Maths 9th

Last Answer : Distribution of 52 cards can be equally divided among four players. Hence, number of ways is (13!)4! 52! ​ 4!= (13!) 52! ​

Description : In how many ways can a pack of 52 cards be divided into 4 sets, three of them having 16 cards each and the fourth just 4 cards? -Maths 9th

Last Answer : First we divide 52 cards into two sets which contains 1 and 51 cards respectively is 1! 51! 52! Now 51 cards can be divided equally in three sets each contains 17 cards (Here order of sets is not important) in 3!(17!) ... ways Hence, the required number of ways = 1! 51! 52! 3! (17!) 3 51!

Description : How many ways can 52 deck cards be divided into equal piles?

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Description : How many ways can 52 deck cards be divided into equal piles?

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Description : What is the correct way to check 4358 divided by 7 is 622 remainder 4?

Last Answer : You do the math by your own or you use a calculator.

Description : The heights of 7 students are given below (in cm) : 120, 126, 132.41, 121.52, 120.35, 132, 125. Find the median height of the students.

Last Answer : The heights of 7 students are given below (in cm) : 120, 126, 132.41, 121.52, 120.35, 132, 125. Find the median height of the students.

Description : A saturated soil sample has water content of 40% and specific gravity of soil particles 2.7. The void ratio of the soil, is (A) 0.4 (B) 0.52 (C) 1.08 (D) None of these

Last Answer : (C) 1.08

Description : A cantilever of length 3m carries a point load of 60 KN at a distance of 2m from the fixed end.If E= 2×105 and I=108, what is the deflection at the free end?. a.7 mm b.14 mm c.26 mm d.52 mm.

Last Answer : b.14 mm

Description : Consider the example of finding the probability of selecting a red card or a 9 from a deck of 52 cards. A) 15/26 B) 26/15 C) 7/13 D) 13/7

Last Answer : Answer: C) We need to find out P(R or 6) Probability of selecting a Red card = 26/52 Probability of selecting a 9 = 4/52 Probability of selecting both a red card and a 9 = 2/52  P(R or 9) = P(R) + P(9) – P(R and 9) = 26/52 + 4/52 – 2/52 = 28/52 = 7/13.