A spring with a force constant of 100 Newtons per meter is loaded with a mass of 1.0 kilogram. The period of vibration of this system is: w) .03 seconds x) .06 seconds y) .31 seconds z) .63 seconds

A spring with a force constant of 100 Newtons per meter is loaded with a mass of 1.0 kilogram. The period of vibration of this system is: w) .03 seconds x) .06 seconds y) .31 seconds z) .63 seconds
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ANSWER: Z -- .63 SECONDS 
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When a 2 kilogram mass is suspended from a spring, the spring stretches 4 cm. The force constant of the spring is approximately:+ w) .5 newtons per meter x) 5 newtons per meter y) 50 newtons per meter z) 500 newtons per meter

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Description : How much time is needed for a force of 20 Newtons to change the velocity of a 5 kilogram mass by 4 meters per second?  

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A flywheel rotating at 5 revolutions per second is brought to rest by a constant torque in 10 seconds. How many revolutions does the flywheel make while coming to a stop? w) 25 x) 50 y) 75 z) 100

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Newton's second law states that the net force acting on a body is equal to the body's time rate of change of: w) acceleration x) mass y) momentum z) inertia

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Calculate damping ratio from the following data: mass = 200Kg ω = 20rad/s damping coefficient = 800 N/m/s a) 0.03 b) 0.04 c) 0.05 d) 0.06

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