Description : Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3) -Chemistry 9th
Last Answer : Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g No. of moles of CaCO3 = No. of molecules/Avogadro constant = 6.022 × 1023/ 6.022 × 1023 = 1 mole Mass of CaCO3 = No. of moles × molar mass = 1 × 100 g = 100 g
Description : What is the mass percent of nitrogen in ammonium carbonate (NH and Aacute) and iquestCO and Agrave?
Last Answer : Need answer
Description : What Mass Of Calcium Carbonate Is Needed For Complete Reaction With The HCl In 2HCl(aq) plus CaCO 3 (s) CaCl 2 (aq) plus H 2 O(l) plus CO 2 (g)?
Description : Calcium carbonate decomposes into calcium oxide & carbon dioxide Her results:Mass of calcium carbonate before heating = 2.00 g Mass of calcium oxide left after heating = 1.12 g work out the mass of carbon dioxide released during the decomposition?
Last Answer : I am not sure of the answer so can someone help me pls
Description : The total number of protons in 10 g of calcium carbonate is `(N_(0) = 6.023 xx 10^(23))` :-
Last Answer : The total number of protons in 10 g of calcium carbonate is `(N_(0) = 6.023 xx 10^(23))` :- A. `1.5057 ... 3.0115 xx 10^(24)` D. `4.0956 xx 10^(24)`
Description : What is the oxidation number of carbon in magnesium carbonate?
Last Answer : The oxidation number of carbon in magnesium carbonate is 4.