Description : Find the equation of the tangent to the curve `x=theta+sin theta ,y=1+cos theta` at `theta=pi/4`
Last Answer : Find the equation of the tangent to the curve `x=theta+sin theta ,y=1+cos theta` at `theta=pi/4` A. ` ... 1+sqrt2)x+(sqrt2-1) pi` D. None of the above
Description : Let `cos(alpha+beta)=(4)/(5)` and let `sin(alpha-beta)=(5)/(13)`, where `0 le alpha`, `beta=(pi)/(4)`. Then`tan2alpha=`
Last Answer : Let `cos(alpha+beta)=(4)/(5)` and let `sin(alpha-beta)=(5)/(13)`, where `0 le alpha`, `beta=(pi)/(4)`. Then ... 19)/(12)` C. `(20)/(7)` D. `(25)/(16)`
Description : Solve the following equation `(i) 5cos2theta+2cos^(2)"(theta)/(2)+1=0`, `-(pi)/(2) lt theta lt (pi)/(2)` `(ii) sin7theta+sin4theta+sintheta=0`, `0 le
Last Answer : Solve the following equation `(i) 5cos2theta+2cos^(2)"(theta)/(2)+1=0`, `-(pi)/(2) lt theta ... iii) tantheta+sectheta=sqrt(3)`, `0 le theta le 2pi`
Description : If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1. -Maths 9th
Last Answer : xsin3θ+ycos3θ=sinθcosθ (xsinθ)sin2θ+(ycosθ)cos2θ=sinθcosθ (xsinθ)sin2θ+(xsinθ)cos2θ=sinθcosθ xsinθ=sinθcosθ x=cosθ Again, ycosθ=xsinθ ycosθ=cosθsinθ y=sinθ Therefore, x2+y2=sin2θ+cos2θ=1.
Description : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) cos phi -1, tan(2pi-theta) > 0 and -1 <
Last Answer : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) ... (3pi)/(2)` D. `(3pi)/(2) lt phi lt 2pi`
Description : If `2cosec theta - cos theta cot theta >= k AA theta in (0,pi),` then value of `k` is
Last Answer : If `2cosec theta - cos theta cot theta >= k AA theta in (0,pi),` then value of `k` is
Description : The sum of all values of `theta in (0,pi/2)` satisfying `sin^(2)2theta+cos^(4)2theta=3/4` is
Last Answer : The sum of all values of `theta in (0,pi/2)` satisfying `sin^(2)2theta+cos^(4)2theta=3/4` is A. `pi` B. `(pi)/(2)` C. `(3pi)/(8)` D. `(5pi)/(4)`
Description : No. of solutions of `16^(sin^2x)+16^(cos^2x)=10, 0 le x le 2 pi` is
Last Answer : No. of solutions of `16^(sin^2x)+16^(cos^2x)=10, 0 le x le 2 pi` is
Description : Let `-1/6 < theta < -pi/12` Suppose `alpha_1 and beta_1`, are the roots of the equation `x^2-2xsectheta + 1=0` and `alpha_2 and beta_2` are the
Last Answer : Let `-1/6 < theta < -pi/12` Suppose `alpha_1 and beta_1`, are the roots of the equation `x^2-2xsectheta ... )` B. `2sectheta` C. `-2tantheta` D. `0`
Description : The number of values of `theta` in the interval `(-pi/2,pi/2)` such that `theta != npi/5` for `ninN` and `tan theta = cot 5theta` as well as `sin2thet
Last Answer : The number of values of `theta` in the interval `(-pi/2,pi/2)` such that `theta != npi/5` for ... = cot 5theta` as well as `sin2theta = cos 4theta` is
Description : Which of the following represents shearing? a.(x, y) → (x+shx, y+shy) b.(x, y) → (ax, by) c.(x, y) → (x cos(θ)+y sin(θ), -x sin(θ)+y cos(θ)) d.(x, y) → (x+shy, y+shx)
Last Answer : d.(x, y) → (x+shy, y+shx)
Description : Find the curl of A = (y cos ax)i + (y + e x )k a) 2i – ex j – cos ax k b) i – ex j – cos ax k c) 2i – ex j + cos ax k d) i – ex j + cos ax k
Last Answer : b) i – ex j – cos ax k
Description : If `sin theta+ sin^2theta+ sin^3theta=1` ,prove that `cos^6theta-4 cos^4theta+8cos^2= 4`
Last Answer : If `sin theta+ sin^2theta+ sin^3theta=1` ,prove that `cos^6theta-4 cos^4theta+8cos^2= 4`
Description : What are both solutions between 0 degrees and 360 degrees of the equation cos theta 911?
Last Answer : They are 35.1 and 324.9 degrees.
Description : If a cos theta plus b sin theta equals 8 and a sin theta - b cos theta equals 5 show that a squared plus b squared equals 89?
Last Answer : There is a hint to how to solve this in what is required to be shown: a and b are both squared.Ifa cos θ + b sin θ = 8a sin θ - b cos θ = 5then square both sides of each to get:a² cos² θ + 2ab cos ... + sin² θ) + b² (sin² θ + cos² θ) = 89using cos² θ + sin² θ = 1â†' a² + b² = 89
Description : If cos and theta 0.65 what is the value of sin and theta?
Last Answer : You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
Description : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of the triangle is maximum when `theta=pi
Last Answer : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of ... pi/4` C. `pi/6` D. None of these.
Description : for `0ltthetaltpi/2 ` the solution(s) of ` sum_(m=1)^6c o s e c(theta+((m-1)pi)/4)c o s e c(theta+(mpi)/n)=4sqrt(2)` is (are):
Last Answer : for `0ltthetaltpi/2 ` the solution(s) of ` sum_(m=1)^6c o s e c(theta+((m-1)pi)/4)c o s e c(theta+(mpi)/n ... (pi)/(6)` C. `(pi)/(12)` D. `(5pi)/(12)`
Description : Find the value of 4x2 + y2 + 25z2 + 4xy – 10yz – 20zx when x = 4, y = 3 and z = 2. -Maths 9th
Last Answer : 4x²+y²+25z²+4xy-10yz-20zx when x=4, y=3 &z=2 so =>4(4)²+(3)²+ 25(2)²+4(4)(3)-10(3)(2)-20(2)(4) =>64+9+100+48-60-160 =>221-220 =>1
Description : If a relation `R` on the set `N` of natural numbers is defined as `(x,y)hArrx^(2)-4xy+3y^(2)=0,Aax,yepsilonN`. Then the relation `R` is
Last Answer : If a relation `R` on the set `N` of natural numbers is defined as `(x,y)hArrx^(2) ... symmetric B. reflexive C. transitive D. an equivalence relation.
Description : Let X be any point within a square ABCD. On AX a square AXYZ is described such that D is within it. Which one of the following is correct? -Maths 9th
Last Answer : answer:
Description : Solve the following inequations `(i) (sinx-2)(2sinx-1) lt 0` `(ii) (2cosx-1)(cosx) le 0` `(iii) sinx+sqrt(3)cosx ge 1` `(iv) cos^(2)x+sinx le 2` `(v)
Last Answer : Solve the following inequations `(i) (sinx-2)(2sinx-1) lt 0` `(ii) (2cosx-1)(cosx) le 0` `(iii) sinx+sqrt(3) ... ^(2)x+sinx le 2` `(v) tan^(2)x gt 3`
Description : Find the curl of the vector A = yz i + 4xy j + y k a) xi + j + (4y – z)k b) xi + yj + (z – 4y)k c) i + j + (4y – z)k d) i + yj + (4y – z)k
Last Answer : d) i + yj + (4y – z)k
Description : Let `P={theta:sintheta-costheta=sqrt2cos theta}and Q={theta:sintheta+costheta=sqrt2sintheta}` be two ses. Then,
Last Answer : Let `P={theta:sintheta-costheta=sqrt2cos theta}and Q={theta:sintheta+costheta=sqrt2sintheta}` be two ses. ... QcancelsubeP` C. `PcancelsubeQ` D. `P=Q`
Description : `int_(0)^(pi//2) (sin x -cos x)/(1+sin x cos x) dx=?`
Last Answer : `int_(0)^(pi//2) (sin x -cos x)/(1+sin x cos x) dx=?` A. `0` B. `1` C. None of the above D.
Description : `int_(0)^(pi//2) x sin cos x dx=?`
Last Answer : `int_(0)^(pi//2) x sin cos x dx=?` A. `(pi)/(4)` B. `(pi)/(8)` C. `(pi)/(12)` D.
Description : `int_(0)^(pi) x sin x. cos^(2) x dx`
Last Answer : `int_(0)^(pi) x sin x. cos^(2) x dx`
Description : `int_(0)^(pi//2) (dx)/(1+2 cos x)`
Last Answer : `int_(0)^(pi//2) (dx)/(1+2 cos x)`
Description : `int_(0)^(pi//2) x sin x cos x dx`
Last Answer : `int_(0)^(pi//2) x sin x cos x dx`
Description : `int_(0)^(pi//2) e^(x) (sin x + cos x) dx`
Last Answer : `int_(0)^(pi//2) e^(x) (sin x + cos x) dx`
Description : `int_(0)^(pi) (1)/(5+2 cos x)dx`
Last Answer : `int_(0)^(pi) (1)/(5+2 cos x)dx`
Description : `int_(0)^(pi//2) (1)/(4+3 cos x)dx`
Last Answer : `int_(0)^(pi//2) (1)/(4+3 cos x)dx`
Description : `(i) int_(0)^(pi//4) e^(tanx) . sec^(2) x dx` `(ii) int_(0)^(pi//4) (sin (cos 2x))/(" cosec " 2x)dx`
Last Answer : `(i) int_(0)^(pi//4) e^(tanx) . sec^(2) x dx` `(ii) int_(0)^(pi//4) (sin (cos 2x))/(" cosec " 2x)dx`
Description : `int_(0)^(pi//2) (dx)/(4sin^(2) x + 5 cos^(2)x)`
Last Answer : `int_(0)^(pi//2) (dx)/(4sin^(2) x + 5 cos^(2)x)`
Description : `int_(0)^(pi//2) sin^(2) x cos ^(2) x dx`
Last Answer : `int_(0)^(pi//2) sin^(2) x cos ^(2) x dx`
Description : `int_(0)^(pi//2) (a cos^(2) x+b sin^(2) x) dx`
Last Answer : `int_(0)^(pi//2) (a cos^(2) x+b sin^(2) x) dx`
Description : ` int_(0)^(pi//6) cos x cos 3x dx`
Last Answer : ` int_(0)^(pi//6) cos x cos 3x dx`
Description : `(i) int_(0)^(pi//2) x sin x cos x dx` `(ii) int_(0)^(pi//6) (2+3x^(2)) cos 3x dx`
Last Answer : `(i) int_(0)^(pi//2) x sin x cos x dx` `(ii) int_(0)^(pi//6) (2+3x^(2)) cos 3x dx`
Description : `(i) int_(0)^(pi//2) x cos x dx` (i) `int_(1)^(3) x. log x dx`
Last Answer : `(i) int_(0)^(pi//2) x cos x dx` (i) `int_(1)^(3) x. log x dx`
Description : `int_(0)^(pi//2) x^(2) cos x dx`
Last Answer : `int_(0)^(pi//2) x^(2) cos x dx`
Description : `int_(pi//6)^(pi//2) cos x dx`
Last Answer : `int_(pi//6)^(pi//2) cos x dx`
Description : The value of definite integral `int_(-pi)^(pi) (cos 2x. cos2^(2)x.cos2^(3)x.cos 2^(4)x.cos2^(5)x)dx` is
Last Answer : The value of definite integral `int_(-pi)^(pi) (cos 2x. cos2^(2)x.cos2^(3)x.cos 2^(4)x.cos2^(5)x)dx` is A. 1 B. `-1` C. 0 D. 2
Description : If the sum of all the solutions of the equation `8 cosx.(cos(pi/6+x)cos(pi/6-x)-1/2)=1` in `[0,pi]` is `k pi` then k is equal to
Last Answer : If the sum of all the solutions of the equation `8 cosx.(cos(pi/6+x)cos(pi/6-x)-1/2)=1` in `[0,pi]` is `k pi` ... (20)/(9)` C. `(2)/(3)` D. `(13)/(9)`
Description : If the arithmetic mean of the roots of the equation `4cos^(3)x-4cos^(2)x-cos(pi+x)-1=0` in the interval `[0,315]` is equal to `kpi`, then the value of
Last Answer : If the arithmetic mean of the roots of the equation `4cos^(3)x-4cos^(2)x-cos(pi+x)-1=0` in the interval `[0,315 ... is A. `10` B. `20` C. `50` D. `80`
Description : \( Q: \int_{\frac{5 \pi}{4}}^{\frac{3 \pi}{2}} \frac{\frac{x}{x}-\frac{x \cdot x}{2}+\frac{(x 2)^{2}}{24}-\frac{x^{4} x 2}{720}+\cdots \infty}{\sqrt{\frac{1-\cos 2 x}{8}}} \)
Last Answer : (a) \( \infinite \) (b) \( \ln 2 \) (C) 0 (d) \( -2 \ln \sqrt{2} \) (e) \( e^{2} \)
Description : In quadrilateral ABCD of the given figure, X and Y are points on diagonal AC such that AX = CY and BXDY ls a parallelogram. -Maths 9th
Last Answer : This answer was deleted by our moderators...
Description : Let R1 and R2 be the remainders when the polynomials x^3 + 2x^2 – 5ax – 7 and x^2 + ax^2 – 12x + 6 are divided by (x + 1) and (x – 2) respectively. -Maths 9th
Description : Find the equation of the normal to the curve `x = acostheta` and `y = b sintheta` at `theta`
Last Answer : Find the equation of the normal to the curve `x = acostheta` and `y = b sintheta` at `theta`
Description : `int_(0)^(pi//4) cos 0. " cosec"^(2) 0 do`
Last Answer : `int_(0)^(pi//4) cos 0. " cosec"^(2) 0 do`