solve : `16x^(4)- 28x^(2) - 8 = 0`

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solve : `16x^(4)- 28x^(2) - 8 = 0`

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Description : For what value of k , the following system of equations have infinite solutions : kx + 4y = k-4, 16x + ky = k (a) k = 2 (b) k = 4 (c) k = 6 (d) k = 8

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