Description : Evaluate: `lim_(x rarr oo) (x^(5)+3x^(4)-4x^(3)-3x^(2)+2x+1)/(2x^(5)+4x^(2)-9x+16)`.
Last Answer : Evaluate: `lim_(x rarr oo) (x^(5)+3x^(4)-4x^(3)-3x^(2)+2x+1)/(2x^(5)+4x^(2)-9x+16)`.
Description : `lim_(x rarr 1) (sqrt(x+1)-sqrt(5x-3))/(sqrt(2x+3)-sqrt(4x+1))=`_________.
Last Answer : `lim_(x rarr 1) (sqrt(x+1)-sqrt(5x-3))/(sqrt(2x+3)-sqrt(4x+1))=`_________.
Description : `lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))=`_______.
Last Answer : `lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))=`_______.
Description : What is the value of `lim_(x rarr 1) (x^(3)+1)(x^(2)-2x+4)`?
Last Answer : What is the value of `lim_(x rarr 1) (x^(3)+1)(x^(2)-2x+4)`?
Description : Evaluate: `lim_(x rarr 1) [(x^(2)+3x+2)/(x^(2)-5x+3)]`.
Last Answer : Evaluate: `lim_(x rarr 1) [(x^(2)+3x+2)/(x^(2)-5x+3)]`.
Description : If `0
Last Answer : If `0
Description : Evaluate: `lim_(x rarr 1) [(x^(4)-2x^(3)-x^(2)+2x)/(x-1)]`.
Last Answer : Evaluate: `lim_(x rarr 1) [(x^(4)-2x^(3)-x^(2)+2x)/(x-1)]`.
Description : Evaluate: `lim_(x rarr 2) [(2x^(2)-9x+10)/(5x^(2)-5x-10)]`.
Last Answer : Evaluate: `lim_(x rarr 2) [(2x^(2)-9x+10)/(5x^(2)-5x-10)]`.
Description : Evaluate `lim_(x rarr 2) (2x-2)`.
Last Answer : Evaluate `lim_(x rarr 2) (2x-2)`.
Description : Let `f : [-1, -1/2] rarr [-1, 1]` is defined by `f(x)=4x^(3)-3x`, then `f^(-1) (x)` is
Last Answer : Let `f : [-1, -1/2] rarr [-1, 1]` is defined by `f(x)=4x^(3)-3x`, then `f^(-1) (x)` is A. `cos (1/3 ... /3+1/3 cos^(-1) x)` D. `sin (1/3 sin^(-1) x)`
Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0
Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0
Description : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`
Last Answer : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`
Description : `int(4x-3)/(3x^2+2x-5)dx`
Last Answer : `int(4x-3)/(3x^2+2x-5)dx`
Description : If `y(x)` is the solution of the differential equation `(dy)/(dx)=-2x(y-1)` with `y(0)=1`, then `lim_(xrarroo)y(x)` equals
Last Answer : If `y(x)` is the solution of the differential equation `(dy)/(dx)=-2x(y-1)` with `y(0)=1`, then `lim_(xrarroo)y(x)` equals
Description : If `lim_(x rarr -3) (x^(k)+3^(k))/(x+3)=405`, where k is an odd natural number then, k = ________.
Last Answer : If `lim_(x rarr -3) (x^(k)+3^(k))/(x+3)=405`, where k is an odd natural number then, k = ________.
Description : In finding `lim_(x rarr a) f(x)`, we replace x by `(1)/(n)`, then the limit becomes _____.
Last Answer : In finding `lim_(x rarr a) f(x)`, we replace x by `(1)/(n)`, then the limit becomes _____.
Description : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.
Last Answer : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.
Description : Evaluate: `lim_(x rarr 0) (sqrt(5+x)-sqrt(5-x))/(sqrt(10+x)-sqrt(10-x))`.
Last Answer : Evaluate: `lim_(x rarr 0) (sqrt(5+x)-sqrt(5-x))/(sqrt(10+x)-sqrt(10-x))`.
Description : `lim_(x rarr 0^(-))(|x|)/(x)=`_______.
Last Answer : `lim_(x rarr 0^(-))(|x|)/(x)=`_______.
Description : `lim_(x rarr 0) (x^(2)+8x)/(x)=`_________.
Last Answer : `lim_(x rarr 0) (x^(2)+8x)/(x)=`_________.
Description : The roots of the equation `2x^(2) + 3x + c = 0` (where `x lt 0`) could be `"______"`.
Last Answer : The roots of the equation `2x^(2) + 3x + c = 0` (where `x lt 0`) could be `"______"`.
Description : If `f(x)=3x^(2)+4x-1`, then find the approximate value of `f(3.1)`.
Last Answer : If `f(x)=3x^(2)+4x-1`, then find the approximate value of `f(3.1)`.
Description : If sin^4x + sin^2x = 1 then what is 1 are the value of cot^4 x + cot^2 x? -Maths 9th
Last Answer : answer:
Description : Evaluate: `lim_(x rarr a) (sqrt(x+a)-sqrt(2a))/(x-a)`.
Last Answer : Evaluate: `lim_(x rarr a) (sqrt(x+a)-sqrt(2a))/(x-a)`.
Description : `lim_(x rarr oo) (x^(n)+a^(n))/(x^(n)-a^(n))=`________.
Last Answer : `lim_(x rarr oo) (x^(n)+a^(n))/(x^(n)-a^(n))=`________.
Description : Evaluate: `lim_(x rarr 2) (x-2)/(sqrt(x+2)-2)`.
Last Answer : Evaluate: `lim_(x rarr 2) (x-2)/(sqrt(x+2)-2)`.
Description : Evaluate: `lim_(x rarr a) (x^(14)-a^(14))/(x^(-7)-a^(-7))`.
Last Answer : Evaluate: `lim_(x rarr a) (x^(14)-a^(14))/(x^(-7)-a^(-7))`.
Description : `lim_(x rarr 4^(-)) (|x-4|)/(x-4)=` ________.
Last Answer : `lim_(x rarr 4^(-)) (|x-4|)/(x-4)=` ________.
Description : Evaluate: `lim_(x rarr 5) sqrt(25-x^(2))`.
Last Answer : Evaluate: `lim_(x rarr 5) sqrt(25-x^(2))`.
Description : Evaluate: `lim_(x rarr -2) (x^(7)+128)/(x+2)`.
Last Answer : Evaluate: `lim_(x rarr -2) (x^(7)+128)/(x+2)`.
Description : Evaluate: `lim_(x rarr a) (x^(1//4)-a^(1//4))/(x^(4)-a^(4))`.
Last Answer : Evaluate: `lim_(x rarr a) (x^(1//4)-a^(1//4))/(x^(4)-a^(4))`.
Description : Evaluate: `lim_(x rarr oo) [(x^(2)+x+6)/(x+1)]`.
Last Answer : Evaluate: `lim_(x rarr oo) [(x^(2)+x+6)/(x+1)]`.
Description : Evaluate: `lim_(x rarr 3) [(x^(3)-27)/(x-3)]`.
Last Answer : Evaluate: `lim_(x rarr 3) [(x^(3)-27)/(x-3)]`.
Description : `lim_(x rarr 5) (sqrt(x)-sqrt(5))/(x-5)=`_______.
Last Answer : `lim_(x rarr 5) (sqrt(x)-sqrt(5))/(x-5)=`_______.
Description : Evaluate: `lim_(x rarr a) [(x^(n)-a^(n))/(x^(m)-a^(m))]`.
Last Answer : Evaluate: `lim_(x rarr a) [(x^(n)-a^(n))/(x^(m)-a^(m))]`.
Description : Evaluate: `lim_(x rarr 3) (|x-3|)/(x-3)`.
Last Answer : Evaluate: `lim_(x rarr 3) (|x-3|)/(x-3)`.
Description : `lim_(x rarr 3)sqrt(9-x^(2))=`_______.
Last Answer : `lim_(x rarr 3)sqrt(9-x^(2))=`_______.
Description : Evaluate: `lim_(x rarr 3)(x^(5)-243)/(x-3)`.
Last Answer : Evaluate: `lim_(x rarr 3)(x^(5)-243)/(x-3)`.
Description : Evaluate: `lim_(x rarr oo) (11|x|+7)/(8|x|-9)`.
Last Answer : Evaluate: `lim_(x rarr oo) (11|x|+7)/(8|x|-9)`.
Description : `lim_(x rarr oo) (7x-3)/(8x-10)=`_______.
Last Answer : `lim_(x rarr oo) (7x-3)/(8x-10)=`_______.
Description : `lim_(x rarr -a) (x^(n)+a^(n))/(x+a)` (where n is an odd natural number)
Last Answer : `lim_(x rarr -a) (x^(n)+a^(n))/(x+a)` (where n is an odd natural number)
Description : `lim_(x rarr 1) (root(5)(x)-1)/(root(4)(x)-1)=`_______.
Last Answer : `lim_(x rarr 1) (root(5)(x)-1)/(root(4)(x)-1)=`_______.
Description : `lim_(x rarr a)x^(n) + ax^(n-1) +a^(2)x^(n-2) + .........+a^(n)=`________.
Last Answer : `lim_(x rarr a)x^(n) + ax^(n-1) +a^(2)x^(n-2) + .........+a^(n)=`________.
Description : Evaluate: `lim_(n rarr oo) (sum_(r=0)^( n) (1)/(2^(r)))`.
Last Answer : Evaluate: `lim_(n rarr oo) (sum_(r=0)^( n) (1)/(2^(r)))`.
Description : For the equation `2x^(2) - 3x + 5 = 0` sum of the roots is `"______"`.
Last Answer : For the equation `2x^(2) - 3x + 5 = 0` sum of the roots is `"______"`.
Description : If the expressions (px^3 + 3x^2 – 3) and (2x^3 – 5x + p) when divided by (x – 4) leave the same remainder, then what is the value of p ? -Maths 9th
Last Answer : Given that the following polynomials leave the same remainder when divided by (x - 4) : We are to find the value of a. Remainder theorem: When (x - b) divides a polynomial p(x), then the remainder is p(b). So, from (i) and (ii), we get Thus, the required value of a is 1.
Description : For what value of m will the expression 3x^3 + mx^2 + 4x – 4m be divisible by x + 2 ? -Maths 9th
Last Answer : f(x) = 3x3 + mx2 + 4x – 4m f(x) is divisible by (x + 2) if f(–2) = 0 Now f(–2) = 3(–2)3 + m(–2)2 + 4(–2) – 4m = – 24 + 4m – ... ; 4m = – 32 ≠ 0 ∴ No such value of m exists for which (x + 2) is a factor of the given expression
Description : For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th
Last Answer : Given f(x) = 3x³ - kx² + 4x + 16. Since (x - k/2) is a factor of polynomial. This means x = k/2 is the zero of the given polynomial. ⇒ f(k/2) = 3(k/2)³ - k(k/2)² + 4(k/2) + 16 ⇒ 0 ... - 4k + 32) + 4(k² - 4k + 32) ⇒ 0 = (k + 4)(k² - 4k + 32) ⇒ k = -4.
Description : If the polynomials ax^3 + 4x^2 + 3x – 4 and x^3 – 4x + a leave the same remainder when divided by (x – 3), the value of a is : -Maths 9th
Last Answer : Given ax^3 + 4x^2 + 3x - 4 and x^3 - 4x + a leave the same remainder when divided by x - 3. Let p(x) = ax^3 + 4x^2 + 3x - 4 and g(x) = x^3 - 4x + a By remainder theorem, if f(x) is divided by (x − a) then ... 4 27a+41 g(3)=27-4(3)+a 15+a f(3)=G(3) 27a+41=15+a 26a=15-41 a=15-41/26 a=-26/26 a=-1
Description : If `5^(3x+2)=25xx5^((4x-1))`, find the value of x.
Last Answer : If `5^(3x+2)=25xx5^((4x-1))`, find the value of x.