`int cot^(3) x. cosec^(2) x dx `

1 Answer

Answer :

`int cot^(3) x. cosec^(2) x dx `

Related questions

Description : `int e^(x). "(cot x- cosec"^(2)" x) dx "`

Last Answer : `int e^(x). "(cot x- cosec"^(2)" x) dx "`

Description : (i) `int(sec x* cosec x)/(log cot x) dx` (ii) `int tan^(4) x dx`

Last Answer : (i) `int(sec x* cosec x)/(log cot x) dx` (ii) `int tan^(4) x dx`

Description : `int cosec^(2)x. sqrt(cot) dx`

Last Answer : `int cosec^(2)x. sqrt(cot) dx`

Description : `int_(pi//6)^(pi//2) (" cosec x cot x")/(1+" cosec "^(2) x)dx`

Last Answer : `int_(pi//6)^(pi//2) (" cosec x cot x")/(1+" cosec "^(2) x)dx`

Description : `int " cosec"^(3) " x dx "`

Last Answer : `int " cosec"^(3) " x dx "`

Description : `int e^x (logsin x + cot x)dx`

Last Answer : `int e^x (logsin x + cot x)dx`

Description : `int cot^(-1)x dx`

Last Answer : `int cot^(-1)x dx`

Description : `int(cot x)/(1+sinx) dx`

Last Answer : `int(cot x)/(1+sinx) dx`

Description : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Last Answer : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Description : `int(1)/(cos x . cot x ) dx`

Last Answer : `int(1)/(cos x . cot x ) dx`

Description : `int " cosec"^(4) 2x dx`

Last Answer : `int " cosec"^(4) 2x dx`

Description : If cosec |=3x and cot |=3/x. then find the value of (x2-1/x2) -Maths 9th

Last Answer : cosecβ = = 3X and cotβ = 3/X , to find value ( X2 - 1/X2 ) . we know , cosec2β = cot2β +1 putting value , (3X )2 = ( 3/X )2 +1 , OR 9X2 = 9 /X2 + 1 , OR 9X2 – 9/X2 = 1, OR 9( X2 - 1/X2 ) = 1, SO (X2 – 1/X2 ) = 1/9

Description : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),(cosec^(-1)x,tan^(-1)x,cot^(-1)x):}]` and `B =

Last Answer : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),( ... )=-A(x)` D. `A(x) + A(-x) = - piI_(3)`

Description : Reciprocal of sin A is ————- a. cosec A b. sec A c. cot A d.Tan a

Last Answer : a. cosec A

Description : If cosec A = 5/4 ,then cot A = (a) ) 4/5 (b) 50/40 (c) 3/4 (d) 4/3

Last Answer : (c) 3/4

Description : `int_(0)^(pi//2) " cosec "(x-(pi)/(3)) " cosec "(x-(pi)/(6)) dx=?`

Last Answer : `int_(0)^(pi//2) " cosec "(x-(pi)/(3)) " cosec "(x-(pi)/(6)) dx=?` A. `-log 3` B. `-2 log 3` C. `2 log 3` D.

Description : `int_(0)^(pi) sin (n+(1)/(2))x. " cosec ".(x)/(2) dx=?`

Last Answer : `int_(0)^(pi) sin (n+(1)/(2))x. " cosec ".(x)/(2) dx=?` A. `(pi)/(2)` B. `pi` C. `2pi` D.

Description : `(i) int_(0)^(pi//4) e^(tanx) . sec^(2) x dx` `(ii) int_(0)^(pi//4) (sin (cos 2x))/(" cosec " 2x)dx`

Last Answer : `(i) int_(0)^(pi//4) e^(tanx) . sec^(2) x dx` `(ii) int_(0)^(pi//4) (sin (cos 2x))/(" cosec " 2x)dx`

Description : `int_(-pi//4)^(pi//4) "cosec"^(2) x dx`

Last Answer : `int_(-pi//4)^(pi//4) "cosec"^(2) x dx`

Description : `intsec^(6//5) x. "cosec"^(4//5) x dx`

Last Answer : `intsec^(6//5) x. "cosec"^(4//5) x dx`

Description : `int_(0)^(1) cot^(-1) (1-x+x^(2)) dx=?`

Last Answer : `int_(0)^(1) cot^(-1) (1-x+x^(2)) dx=?` A. `(pi)/(2) +log 2` B. `(pi)/(2) -log 2` C. `-(pi)/(2) - log 2` D.

Description : `int_(0)^(pi//4) sqrt(cot x dx) =?`

Last Answer : `int_(0)^(pi//4) sqrt(cot x dx) =?` A. `(Pi sqrt(2))/(4)+(1)/(sqrt(2)) log (sqrt(2)-1)` B. `(- ... (pisqrt(2))/(4) -(1)/(sqrt(2))log (sqrt(2)-1)` D.

Description : `int (4x^(2) +x+1)/(x^(3) -1) dx=?`

Last Answer : `int (4x^(2) +x+1)/(x^(3) -1) dx=?` A. `log (x-1) -log (x^(3) -1) +c` B. `log (x^(3) -1) +log (x-1)+c` C. None of the above D.

Description : `int (x^(2))/((a+bx)^(2))dx=?`

Last Answer : `int (x^(2))/((a+bx)^(2))dx=?` A. `(-x^(2))/(b(a+bx))+(2)/(b^(2)) [x-(a)/(b) log (a+bx)]+c` ... ^(2)) [x-(a)/(b)log (a+bx)]+c` C. None of the above D.

Description : Evaluate: `int((x-1)e^x)/((x+1)^3)dx`

Last Answer : Evaluate: `int((x-1)e^x)/((x+1)^3)dx` A. `(e^(x))/((x+1)^(2))+c` B. `(e^(x))/((x+1)^(3))+c` C. `(e^(x))/((x+1)^(4))+c` D.

Description : `int (1-sinx )/ (1-cos x) dx=?`

Last Answer : `int (1-sinx )/ (1-cos x) dx=?` A. `cot .(x)/(2) -2 log sin .(x)/(2) +c` B. `-cot .(x)/(2) -2 log sin .(x)/(2) +c` C. None of the above D.

Description : `int log (x^(2) +a^(2)) dx=?`

Last Answer : `int log (x^(2) +a^(2)) dx=?` A. `x log (x^(2)+a^(2)) -2x +2a tan^(-1).(x)/(a)+c` B. `x log ... 2x -2a tan^(-1) . (x)/(a) +c` C. None of the above D.

Description : `int {1+2 tan x (tan x + sec x )}^(1//2) dx=?`

Last Answer : `int {1+2 tan x (tan x + sec x )}^(1//2) dx=?` A. `log {cosec x(sec x+tan x)}+c` B. `log {sec x (sec x+ tan x)} +c` C. None of the above D.

Description : `"The integral " int(dx)/(x^(2)(x^(4)+1)^(3//4))" equals"`

Last Answer : `"The integral " int(dx)/(x^(2)(x^(4)+1)^(3//4))" equals"` A. `(1+x^(4)) ^(1//4)+c` B. `(1-x^(-4))^(1//4) +c` C. `-(1+x^(-4))^(1//4)+c` D.

Description : `int (1)/(sqrt(sin^(3) x cos x))dx =?`

Last Answer : `int (1)/(sqrt(sin^(3) x cos x))dx =?` A. `-2sqrt(tan x) +c` B. `(2)/(sqrt(tan x)) +c` C. `(-2)/(sqrt(tan x)) +c` D.

Description : `int (x)/( 1+cos x) dx=?`

Last Answer : `int (x)/( 1+cos x) dx=?` A. `x tan (x)/(2) + 2 log cos (x)/(2) + c` B. ` x tan (x)/(2) + 2 log sin (x)/(2)+c` C. None of the above D.

Description : `int sin^(3) x cos^(3) x dx =?`

Last Answer : `int sin^(3) x cos^(3) x dx =?` A. `(1)/(4) sin^(4) x + (1)/(6) sin^(6) x+c` B. `(1)/(4) cos^(4)x-(1)/(6) cos^(6) x+c` C. none of the above D.

Description : `int(sin(x-alpha)/(sin(x+alpha)) dx`

Last Answer : `int(sin(x-alpha)/(sin(x+alpha)) dx` A. `x cos 2alpha +sin 2alpha log| sin (x+alpha)|+c` B. `x cos ... log |sin (x+alpha)|+c` C. None of the above D.

Description : `int (e^(m tan^(-1) x))/(1+x^(2)) dx=?`

Last Answer : `int (e^(m tan^(-1) x))/(1+x^(2)) dx=?` A. `(1)/(m) e^(m tan^(-1)x) +c` B. `e^(m tan^(-1)x) +c` C. None of these D.

Description : `int(tan^(-1)x)/(1+x^(2)) dx=?`

Last Answer : `int(tan^(-1)x)/(1+x^(2)) dx=?` A. `(1)/(3) (tan^(-1) x)^(2)+c` B. `(tan^(-1) x)^(2) +c` C. `(tan^(-1) x)^(3) +c` D.

Description : `int (x^(2))/(x^(2) +4) dx=?`

Last Answer : `int (x^(2))/(x^(2) +4) dx=?` A. `x+4 tan^(-1) ((x)/(2))+c` B. `x-2 tan^(-1) ((x)/(2))+c` C. None of the above D.

Description : `int (1-cos x)/(1+cos x) dx=?`

Last Answer : `int (1-cos x)/(1+cos x) dx=?` A. `2 tan ((x)/(2))+ x+c` B. ` tan ((x)/(2)) + x+c` C. `tan ((x)/(2)) + 2x + c` D. none of these

Description : `int(sin x)/( sqrt(1+cos x))dx=?`

Last Answer : `int(sin x)/( sqrt(1+cos x))dx=?` A. `sqrt(1+cos x) +c` B. `-2sqrt(1+ cos x)+c` C. `2sqrt(1+ cos x) +c` D.

Description : `int (1)/(sin^(2) x cos^(2)x) dx=?`

Last Answer : `int (1)/(sin^(2) x cos^(2)x) dx=?` A. `tan x-cot x+c` B. `sec x+ cosec x+c` C. `sec x- cosec x+c` D.

Description : ` int (3-4 sin x)/(cos^(2) x) dx=?`

Last Answer : ` int (3-4 sin x)/(cos^(2) x) dx=?` A. `4 tan x +4 sec x+c` B. ` 3 tan x + 4 sec x+ c` C. ` 4 tan x +3 sec x+c` D.

Description : Evaluate: `int(x^2-1)/(x^4+x^2+1) dx`

Last Answer : Evaluate: `int(x^2-1)/(x^4+x^2+1) dx`

Description : `int (x^2+1)/(x^4+1) dx`

Last Answer : `int (x^2+1)/(x^4+1) dx`

Description : `int(x^(2)+1)/(x^(4)-2x^(2)+1)dx`

Last Answer : `int(x^(2)+1)/(x^(4)-2x^(2)+1)dx`

Description : `int(1)/(3+4 sin x)dx`

Last Answer : `int(1)/(3+4 sin x)dx`

Description : `int(x^2+1)/(x^4+x^2+1)`dx

Last Answer : `int(x^2+1)/(x^4+x^2+1)`dx

Description : Evaluate: `int(x^2+4)/(x^4+16)dx`

Last Answer : Evaluate: `int(x^2+4)/(x^4+16)dx`

Description : `int(1)/(3+2 sin x +cos x)dx`

Last Answer : `int(1)/(3+2 sin x +cos x)dx`

Description : `int(1)/(5-4 sin x)dx`

Last Answer : `int(1)/(5-4 sin x)dx`

Description : `int(1)/(5+2 cos x)dx`

Last Answer : `int(1)/(5+2 cos x)dx`

Description : `int(1)/((sin x-2 cos x) (2 sin x+c osx))dx`

Last Answer : `int(1)/((sin x-2 cos x) (2 sin x+c osx))dx`