Description : Evaluate: `intx^2sqrt(a^6-x^6)dx`
Last Answer : Evaluate: `intx^2sqrt(a^6-x^6)dx`
Description : Evaluete `intx/(x^4+x^2+1)dx`
Last Answer : Evaluete `intx/(x^4+x^2+1)dx`
Description : `intx/((x^2-a^2)(x^2-b^2))dx`
Last Answer : `intx/((x^2-a^2)(x^2-b^2))dx`
Description : `intx cos^(3) x^(2) . sin x^(2) dx`
Last Answer : `intx cos^(3) x^(2) . sin x^(2) dx`
Description : `intx^(2) . tan^(2) x^(3). sec^(2) x^(3) dx`
Last Answer : `intx^(2) . tan^(2) x^(3). sec^(2) x^(3) dx`
Description : `intx^(2) . sin x^(3) dx`
Last Answer : `intx^(2) . sin x^(3) dx`
Description : `intx/((1+sinx))dx`
Last Answer : `intx/((1+sinx))dx`
Description : Complete set of solution of inequation `sqrt(x+2sqrt(x-1))+sqrt(x-2sqrt(x-1))>3/2`
Last Answer : Complete set of solution of inequation `sqrt(x+2sqrt(x-1))+sqrt(x-2sqrt(x-1))>3/2` A. `(-oo,1)` B. `(-oo,1]` C. `[1,oo)` D. `(1,oo)`
Description : If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.
Last Answer : If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.
Description : In a certain circuit current changes with time accroding to `i=2sqrt(t)`. r.m.s. value of current between `t=2` to `t=4s` will be
Last Answer : In a certain circuit current changes with time accroding to `i=2sqrt(t)`. r.m.s. value of current between `t=2` to `t=4s` will be
Description : `int_(0)^(pi//2) " cosec "(x-(pi)/(3)) " cosec "(x-(pi)/(6)) dx=?`
Last Answer : `int_(0)^(pi//2) " cosec "(x-(pi)/(3)) " cosec "(x-(pi)/(6)) dx=?` A. `-log 3` B. `-2 log 3` C. `2 log 3` D.
Description : `int_(pi//6)^(pi//2) (" cosec x cot x")/(1+" cosec "^(2) x)dx`
Last Answer : `int_(pi//6)^(pi//2) (" cosec x cot x")/(1+" cosec "^(2) x)dx`
Description : ` int_(0)^(pi//6) cos x cos 3x dx`
Last Answer : ` int_(0)^(pi//6) cos x cos 3x dx`
Description : `(i) int_(0)^(pi//2) x sin x cos x dx` `(ii) int_(0)^(pi//6) (2+3x^(2)) cos 3x dx`
Last Answer : `(i) int_(0)^(pi//2) x sin x cos x dx` `(ii) int_(0)^(pi//6) (2+3x^(2)) cos 3x dx`
Description : `int_(pi//6)^(pi//2) cos x dx`
Last Answer : `int_(pi//6)^(pi//2) cos x dx`
Description : `int(x^2)/(x^6+x^3-2)dx`
Last Answer : `int(x^2)/(x^6+x^3-2)dx`
Description : Evaluate: (i) `int(e^x)/(sqrt(4-e^(2x))) dx` (ii) `int(x^2)/(sqrt(1-x^6)) dx`
Last Answer : Evaluate: (i) `int(e^x)/(sqrt(4-e^(2x))) dx` (ii) `int(x^2)/(sqrt(1-x^6)) dx`
Description : `intsec^(6//5) x. "cosec"^(4//5) x dx`
Last Answer : `intsec^(6//5) x. "cosec"^(4//5) x dx`
Description : `(i) int(sinx)/(sqrt(4+ cos^(2) x)) dx " "(ii) int(x^(2))/(sqrt(9+x^(6)))dx`
Last Answer : `(i) int(sinx)/(sqrt(4+ cos^(2) x)) dx " "(ii) int(x^(2))/(sqrt(9+x^(6)))dx`
Description : `int(x^(2))/(1+x^(6)) dx`
Last Answer : `int(x^(2))/(1+x^(6)) dx`
Description : `int (x^(6) -(1)/(x) +e^(x) +3)dx`
Last Answer : `int (x^(6) -(1)/(x) +e^(x) +3)dx`
Description : `int x^(-6) " dx "`
Last Answer : `int x^(-6) " dx "`
Description : The demand function of a product x is as dx = 12-2Px, where Px stand for price. The quantity demanded corresponding to price of `2 will be ……………. (a) 8 ; (b) 6 ; (c) 5 ; (d) 10
Last Answer : (a) 8 ;