`intcos(logx)dx`

Last Answer : (d) \(a^{-rac{4}{3}}\)Since logaxa = \(rac{1}{log_aax}\) = \(rac{1}{log_aa+log_ax}\) = \(rac{1}{1+log_ax}\) andloga2x a = \(rac{1}{log_aa^2x}\) = \(rac{1}{log_aa^2+log_{ax}x}\) = \(rac{1}{2log_aa+log_{ax}x}\)= \( ... 2}}\)When t = \(-rac{4}{3}\), logax = \(-rac{4}{3}\) ⇒ \(x\) = \(a^{-rac{4}{3}}\)

If logx a, a^(x/2) and logbx are in GP, then x is equal to : -Maths 9th

Description : If logx a, a^(x/2) and logbx are in GP, then x is equal to : -Maths 9th

Last Answer : (b) loga (loge a) - loga (loge b) logxa, \(a^{rac{x}{2}}\), logbx are in GP ⇒ \(\big[a^{rac{x}{2}}\big]^2\) = logxa . logbx⇒ ax = \(rac{ ext{log}\,a}{ ext{log}\,x}.rac{ ext{log}\,x}{ ext{log}\,b ... ⇒ x = loga (logba)= log a = \(rac{ ext{log}_e\,a}{ ext{log}_e\,b}\) = loga (loge a) - loga (loge b)

If logx (a – b) – logx (a + b) = logx (b/a), find a^2/b^2 + b^2/a^2. -Maths 9th

Description : If logx (a – b) – logx (a + b) = logx (b/a), find a^2/b^2 + b^2/a^2. -Maths 9th

Last Answer : answer:

What is the least value of the expression 2 log10x – logx (1/100) for x > 1 ? -Maths 9th

Description : What is the least value of the expression 2 log10x – logx (1/100) for x > 1 ? -Maths 9th

Last Answer : answer:

`intcos(logx)dx`

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