Let p(x) = ax³ + bx² + x - 6 A/C to question, (x + 2) is the factor of p(x) , and we know this is possible only when p(-2) = 0 So, p(2) = a(-2)³ + b(-2)² - 2 - 6 = 0 ⇒-8a + 4b - 8 = 0 ⇒ 2a - b + 2 = 0 -------------(1) again, question said that if we p(x) is divided by ( x -2) then it leaves remainder 4. so, P(2) = a(2)³ + b(2)² + 2 - 6 = 4 ⇒8a + 4b - 4 = 4 2a + b -2 = 0 -------------(2) solve equations (1) and (2), 4a = 0 ⇒a = 0 and b = 2 Then, equation will be 2x² + x - 6