In which quadrant(s), the abscissa of a point is negative? -Maths 9th

1 Answer

Answer :

Solution:- II and III quadrants

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Description : The point in which abscissa and ordinate have different signs will lie in which quadrant (s)? -Maths 9th

Last Answer : Solution :- II and IV quadrants.

Description : Signs of the abscissa and ordinate of a point in the second quadrant are respectively. -Maths 9th

Last Answer : (C) In second quadrant, X-axis is negative and Y-axis is positive. So, sign of abscissa of a point is negative and sign of ordinate of a point is positive.

Description : Signs of the abscissa and ordinate of a point in the second quadrant are respectively. -Maths 9th

Last Answer : (C) In second quadrant, X-axis is negative and Y-axis is positive. So, sign of abscissa of a point is negative and sign of ordinate of a point is positive.

Description : Without plotting the points indicate the quadrant in which they lie, if : (i) ordinate is 5 and abscissa is – 3 (ii) abscissa is -5 and ordinate is – 3 -Maths 9th

Last Answer : answer:

Description : Without plotting the points indicate the quadrant in which they will lie, if (i) the ordinate is 5 and abscissa is – 3 -Maths 9th

Last Answer : (i) In the point (−3,5) abscissa is negative and ordinate is positive, so it lies in the second quadrant. (ii) In the point (−5,−3) abscissa and ordinate both are negative, so it lies in the ... . (iv) In the point (3,5) abscissa and ordinate both are positive, so it lies in the first quadrant

Description : The product of the abscissa and the ordinate of a point P is negative. In which quadrants can the point lie ? -Maths 9th

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Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

Description : Abscissa of a point is positive in -Maths 9th

Last Answer : (b) Abscissa of a point is positive in I and IV quadrants.

Description : Write the linear equation such that each point on its graph has an ordinate 3 times its abscissa. -Maths 9th

Last Answer : Let the abscissa of the point be x, According to the question, Ordinate (y) = 3 x Abscissa ⇒ y=3x When x = 1, then y = 3 x 1 = 3 and when x = 2, then y = 3 x 2 = 6. Here, ... the line AB. Hence, y = 3x is the required equation such that each point on its graph has an ordinate 3 times its abscissa.

Description : Abscissa of a point is positive in -Maths 9th

Last Answer : (b) Abscissa of a point is positive in I and IV quadrants.

Description : Write the linear equation such that each point on its graph has an ordinate 3 times its abscissa. -Maths 9th

Last Answer : Let the abscissa of the point be x, According to the question, Ordinate (y) = 3 x Abscissa ⇒ y=3x When x = 1, then y = 3 x 1 = 3 and when x = 2, then y = 3 x 2 = 6. Here, ... the line AB. Hence, y = 3x is the required equation such that each point on its graph has an ordinate 3 times its abscissa.

Description : Express the given statement in the form of a linear equation in two variables. The sum of the ordinate and abscissa of a point is 6. -Maths 9th

Last Answer : Solution :- x+y = 6

Description : Determine the point on the graph of the linear equation x + y = 6, whose ordinate is 2 times its abscissa. -Maths 9th

Last Answer : Solution :-

Description : Find the point which lies on the line y x = -3 having abscissa 3. -Maths 9th

Last Answer : Solution :- When x=3 then y= -9,thus the point is (3,-9)

Description : linear equation such that each point on its graph has an ordinate one more than 3×1÷2 times its abscissa -Maths 9th

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Description : The ordinate of a point is thrice its abscissa. Express the statement in the form of a linear equation in two variables. -Maths 9th

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Description : The point whose abscissa is equal to its ordinate and which is equidistant from A(–1, 0) and B(0, 5) is -Maths 9th

Last Answer : Putting \(x\) = 0 in equation of one of the lines say 9\(x\) + 40y -20 = 0, we get y = \(rac{1}{2}\)∴ A point on 9\(x\) + 40y - 20 = 0 is \(\big(0,rac{1}{2}\big)\)∴ Distance of \(\big(0,rac{1}{2}\big) ... imesrac{1}{2}+21\big|}{\sqrt{9^2+40^2}}\) = \(rac{|41|}{\sqrt{1681}}\) = \(rac{41}{41}\) = 1.

Description : Name the quadrant in which the point lies : -Maths 9th

Last Answer : (a) A (1, 1) lies in the 1st quadrant, (b) B (2, 4) lies in the 1st quadrant. (c) C (-3, -10) lies in the 3rd quadrant. (d) D (-1, 2) lies in the 2nd quadrant. (e) E (1 , -1) lies in the ... lies in the 3rd quadrant. (g) G (-3, 10) lies in the 2nd quadrant. (h) H (1, -2) lies in the 4th quadrant.

Description : Name the quadrant in which the point lies : -Maths 9th

Last Answer : (a) A (1, 1) lies in the 1st quadrant, (b) B (2, 4) lies in the 1st quadrant. (c) C (-3, -10) lies in the 3rd quadrant. (d) D (-1, 2) lies in the 2nd quadrant. (e) E (1 , -1) lies in the ... lies in the 3rd quadrant. (g) G (-3, 10) lies in the 2nd quadrant. (h) H (1, -2) lies in the 4th quadrant.

Description : In which quadrant does a point both of whose coordinates are positive lie? -Maths 9th

Last Answer : Solution :- I quadrant.

Description : In which quadrant does the point (-1, 2) lie ? -Maths 9th

Last Answer : answer:

Description : If in coordinates of a point B(3, -2), signs of both coordinates are interchanged, then it will lie in which quadrant ? -Maths 9th

Last Answer : answer:

Description : Abscissa of all the points on the X-axis is -Maths 9th

Last Answer : (d) Abscissa of all the points on the X-axis is any number because X-axis is a number line which contains many real numbers on it.

Description : If the coordinates of the two points are P(-2, 3) and Q(-3, 5), then (Abscissa of P) – (Abscissa of Q) is -Maths 9th

Last Answer : (b) We have, points P(- 2, 3) and Q(- 3, 5) Here, abscissa of Pi.e., x-coordinate of Pis -2 and abscissa of Q i.e., x-coordinate of Q is -3. So, (Abscissa of P) – (Abscissa of Q) = - 2 - (-3) = -2 + 3 =1.

Description : The points whose abscissa and ordinate have different signs will lie in -Maths 9th

Last Answer : (d) The points whose abscissa and ordinate have different signs will be of the form (-x, y) or (x, – y)and these points will lie in II and IV quadrants.

Description : Abscissa of all the points on the X-axis is -Maths 9th

Last Answer : (d) Abscissa of all the points on the X-axis is any number because X-axis is a number line which contains many real numbers on it.

Description : If the coordinates of the two points are P(-2, 3) and Q(-3, 5), then (Abscissa of P) – (Abscissa of Q) is -Maths 9th

Last Answer : (b) We have, points P(- 2, 3) and Q(- 3, 5) Here, abscissa of Pi.e., x-coordinate of Pis -2 and abscissa of Q i.e., x-coordinate of Q is -3. So, (Abscissa of P) – (Abscissa of Q) = - 2 - (-3) = -2 + 3 =1.

Description : The points whose abscissa and ordinate have different signs will lie in -Maths 9th

Last Answer : (d) The points whose abscissa and ordinate have different signs will be of the form (-x, y) or (x, – y)and these points will lie in II and IV quadrants.

Description : If the coordinates of two points are P( -2,3) and Q ( -3, 5) then find (abscissa of P)–(abscissa of Q) -Maths 9th

Last Answer : Abscissa of P – Abscissa of Q = (–2) – (–3) = –2 + 3 = 1.

Description : What do you mean by Co-ordinates (Abscissa and Ordinate)? Explain with figure. -Maths 9th

Last Answer : Co-ordinate Geometry is that branch of geometry in which two numbers, called co-ordinates are used to indicate the position of a point in a plane and which make use of algebraic methods in the study of geometric figures.

Description : Without plotting the points indicate the quadrant in which they will lie, if -Maths 9th

Last Answer : (i) The given point is (- 3, 5). Here, abscissa is negative and ordinate is positive, so it lies in II quadrant. (ii) The given point is (-5, - 3). Here, abscissa and ordinate both are negative ... ) The given point is (3, 5). Here, abscissa and ordinate both are positive, so it lies in I quadrant.

Description : In which quadrant or on which axis each of the following points lie ? -Maths 9th

Last Answer : (i) In point (-3, 5), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant. (ii) In point (4,-1), x-coordinate is positive and y-coordinate is negative, so it lies in ... v) In point (-3, - 6), x-coordinate and y-coordinate both are negative, so it lies in III quadrant.

Description : Without plotting the points indicate the quadrant in which they will lie, if -Maths 9th

Last Answer : (i) The given point is (- 3, 5). Here, abscissa is negative and ordinate is positive, so it lies in II quadrant. (ii) The given point is (-5, - 3). Here, abscissa and ordinate both are negative ... ) The given point is (3, 5). Here, abscissa and ordinate both are positive, so it lies in I quadrant.

Description : In which quadrant or on which axis each of the following points lie ? -Maths 9th

Last Answer : (i) In point (-3, 5), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant. (ii) In point (4,-1), x-coordinate is positive and y-coordinate is negative, so it lies in ... v) In point (-3, - 6), x-coordinate and y-coordinate both are negative, so it lies in III quadrant.

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : circle of radius a touches both axis in 1st quadrant so its centre will be (a,a). ∴ Required equation ⇒(x−a)2+(y−a)2=a2 ⇒x2+a2−2ax+y2+a2−2ay=a2 ⇒x2+y2−2ax−2ay+2a2−a2=0 ⇒x2−y2−2ax−2ay+a2=0.

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : Given that the circle of radius ‘a’ touches both axis. So, its centre is (a, a) So, the equation of required circles is : (x-a)2 + (y-a)2 = a2 ⇒ x2 - 2ax + a2+y2 - 2ay + a2 = a2 ⇒ x2 + y2 - 2ax - 2ay + a2 = 0

Description : Without plotting the points indicate the quadrant in which they will lie, if: -Maths 9th

Last Answer : Solution :- (i) III quadrant (iii) IV quadrant

Description : Write the coordinates of the vertices of a rectangle whose lenght and breadth are 7 and 4 units respectively,one vertex atthe the origin,the longer side lies on the x-axis and one of the vertices lies in the third quadrant. -Maths 9th

Last Answer : Solution :-

Description : Write the coordinates of the vertices of a rectangle whose length and breadth are 6 and 3 units respectively, one vertex at the origin, the longer side lies on the y-axis and one of the vertices lies in the second quadrant. -Maths 9th

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Description : If A lies in the third quadrant and 3 tan A – 4 = 0, then what is the value of 5 sin 2 A + 3 sin A + 4 cos A? -Maths 9th

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Description : The angle A lies in the third quadrant and it satisfies the equation 4 (sin^2x + cos x) = 1. What is the measure of angle A? -Maths 9th

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Description : If both coordinates of a point are negative in which quadrant is the point located?

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Description : A point both of whose coordinates are negative will lie in -Maths 9th

Last Answer : (c) A point both of whose coordinates are negative will lie in III quadrant because, in III quadrant x-coordinate and y-coordinate both are negative.

Description : If the perpendicular distance of a point P from the X-axis is 5 units and the foot of the perpendicular lies on the negative direction of X-axis, then the point P has -Maths 9th

Last Answer : (d) We know that, the perpendicular distance of a point from the X-axis gives y-coordinate of that point. Here, foot of perpendicular lies on the negative direction of X-axis, so perpendicular distance can be measure in II quadrant or III quadrant. Hence, the point P has y-coordinate = 5 or -5.

Description : The point which lies on Y-axis at a distance of 5 units in the negative direction of Y-axis is -Maths 9th

Last Answer : (C) Given the point lies on X-axis this shows that its ^-coordinate is zero. Also, it is at a distance of 5 units in negative direction of X-axis, so its y-coordinate” is negative.Hence, the required point is (0, – 5).

Description : A point both of whose coordinates are negative will lie in -Maths 9th

Last Answer : (c) A point both of whose coordinates are negative will lie in III quadrant because, in III quadrant x-coordinate and y-coordinate both are negative.

Description : If the perpendicular distance of a point P from the X-axis is 5 units and the foot of the perpendicular lies on the negative direction of X-axis, then the point P has -Maths 9th

Last Answer : (d) We know that, the perpendicular distance of a point from the X-axis gives y-coordinate of that point. Here, foot of perpendicular lies on the negative direction of X-axis, so perpendicular distance can be measure in II quadrant or III quadrant. Hence, the point P has y-coordinate = 5 or -5.

Description : The point which lies on Y-axis at a distance of 5 units in the negative direction of Y-axis is -Maths 9th

Last Answer : (C) Given the point lies on X-axis this shows that its ^-coordinate is zero. Also, it is at a distance of 5 units in negative direction of X-axis, so its y-coordinate” is negative.Hence, the required point is (0, – 5).

Description : What quadrant is 5 and negative 8?

Last Answer : It is in quadrant IV.