Give the geometric interpretations of 5x + 3 = 3x – 7 as an equation (i) in one variable (ii) in two variables. -Maths 9th

Give the geometric interpretations of 5x + 3 = 3x – 7 as an equation (i) in one variable (ii) in two variables. -Maths 9th
by

1 Answer

Answer :

Solution   :-
by

Related questions

Give the geometric representation of y = 2 as an equation in one variable. -Maths 9th

Description : Give the geometric representation of y = 2 as an equation in one variable. -Maths 9th

Last Answer : Solution :-

The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Description : The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.

The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Description : The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.

Write a solution of the linear equation 5x + 0y +8 = 0 in two variables. -Maths 9th

Description : Write a solution of the linear equation 5x + 0y +8 = 0 in two variables. -Maths 9th

Last Answer : Solution : -

2x+6 geometric representation on 2 variables -Maths 9th

Description : 2x+6 geometric representation on 2 variables -Maths 9th

Last Answer : 2x+6 = 0in two variables is 2x + 0y + 6 = 0 Here, all the value of y can be taken as product of 0 and y is always 0. Now, x must satisfy the equation 2x+6 = 0 ⇒ 2x = -6 ⇒ x = -3 Thus, x = -3 and y = 0 The graph obtained will be a line parallel to Y-axis at a distance of -3 on X-axis.

2x+6 geometric representation on 2 variables -Maths 9th

Description : 2x+6 geometric representation on 2 variables -Maths 9th

Last Answer : 2x+6 = 0in two variables is 2x + 0y + 6 = 0 Here, all the value of y can be taken as product of 0 and y is always 0. Now, x must satisfy the equation 2x+6 = 0 ⇒ 2x = -6 ⇒ x = -3 Thus, x = -3 and y = 0 The graph obtained will be a line parallel to Y-axis at a distance of -3 on X-axis.

What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

Description : What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

Last Answer : Solution :-

If the expressions (px^3 + 3x^2 – 3) and (2x^3 – 5x + p) when divided by (x – 4) leave the same remainder, then what is the value of p ? -Maths 9th

Description : If the expressions (px^3 + 3x^2 – 3) and (2x^3 – 5x + p) when divided by (x – 4) leave the same remainder, then what is the value of p ? -Maths 9th

Last Answer : Given that the following polynomials leave the same remainder when divided by (x - 4) : We are to find the value of a. Remainder theorem: When (x - b) divides a polynomial p(x), then the remainder is p(b). So, from (i) and (ii), we get Thus, the required value of a is 1.

What is (x^2-3x+2)/(x^2-5x +6)÷(x^2-5x+4)/(x^2-7x+12) equal to? -Maths 9th

Description : What is (x^2-3x+2)/(x^2-5x +6)÷(x^2-5x+4)/(x^2-7x+12) equal to? -Maths 9th

Last Answer : answer:

What is the equation of the line having the y-intercept –1 and parallel to the line y = 5x – 7 ? -Maths 9th

Description : What is the equation of the line having the y-intercept –1 and parallel to the line y = 5x – 7 ? -Maths 9th

Last Answer : Slope of AB = \(rac{2-4}{1-0}\) = -2, Slope of BC = \(rac{3-2}{3-1}\) = \(rac{1}{2}\)Slope of AC = \(rac{3-4}{3-0}\) = \(-rac{1}{3}\)Slope of AB × Slope of BC = -2 x \(rac{1}{2}\) = -1∴ AB ⊥ BC, i.e, ∠B = 90º ⇒ ΔABC is a right angled.

Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer. (i) 4x2–3x+7 -Maths 9th

Description : Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer. (i) 4x2–3x+7 -Maths 9th

Last Answer : Solution: The equation 4x2–3x+7 can be written as 4x2–3x1+7x0 Since x is the only variable in the given equation and the powers of x (i.e., 2, 1 and 0) are whole numbers, we can say that the expression 4x2–3x+7 is a polynomial in one variable

What is the value of x in the equation 0.25 open brackets 3x - 4 close brackets - 0.5x equals 2.75 A. 27 B. 15 C. 7 D. 3?

Description : What is the value of x in the equation 0.25 open brackets 3x - 4 close brackets - 0.5x equals 2.75 A. 27 B. 15 C. 7 D. 3?

Last Answer : Work it through, doing the same thing to both sides:0.25(3x - 4) - 0.5x = 2.75[Multiply both sides by 4]→ 4 (0.25(3x - 4) - 0.5x) = 4 (2.75)→ 4 0.25(3x - 4) - 4 0.5x = 4 2.75→ 3x - 4 - 2x = ... 11[Add 4 to both sides]→ (x - 4) + 4 = (11) + 4→ x - 4 + 4 = 11 + 4→ x = 15→ Solution is B. 15

The equation whose roots are the negatives of the roots of the equation x^7 + 3x^5 + x^3 – x^2 + 7x + 2 = 0 is : -Maths 9th

Description : The equation whose roots are the negatives of the roots of the equation x^7 + 3x^5 + x^3 – x^2 + 7x + 2 = 0 is : -Maths 9th

Last Answer : answer:

The equation x = 7, in two variables can be written as -Maths 9th

Description : The equation x = 7, in two variables can be written as -Maths 9th

Last Answer : (b) Here, the’Coefficient of y in the given equation x =7 is 0. So, the equation can be written as 1-x + 0-y = 7 Hence, the required equation is 1.x + 0. y = 7.

The equation x = 7, in two variables can be written as -Maths 9th

Description : The equation x = 7, in two variables can be written as -Maths 9th

Last Answer : (b) Here, the’Coefficient of y in the given equation x =7 is 0. So, the equation can be written as 1-x + 0-y = 7 Hence, the required equation is 1.x + 0. y = 7.

If x = 0 and y = k is a solution of the equation 5x - 3 y = 0, find the value of k. -Maths 9th

Description : If x = 0 and y = k is a solution of the equation 5x - 3 y = 0, find the value of k. -Maths 9th

Last Answer : Solution :-

For what value of k will the roots of the equation kx^2 – 5x + 6 = 0 be in the ratio 2 : 3 ? -Maths 9th

Description : For what value of k will the roots of the equation kx^2 – 5x + 6 = 0 be in the ratio 2 : 3 ? -Maths 9th

Last Answer : (b) 1 Let the roots of the equation kx2 - 5x + 6 = 0 be α and β. Then, α + β = \(\frac{5}{k}\) ...(i) αβ = \(\frac{6}{k}\) ...(ii) Given \(\ ... frac{9}{k}\) ⇒ 9k2 - 9k = 0 k(k - 1) = 0 ⇒ k = 0 or 1 But k = 0 does not satisfy the condition, so k = 1.

Is ax + by + c = 0, where a, b and c are real numbers, a linear equation in two variables? Give reason. -Maths 9th

Description : Is ax + by + c = 0, where a, b and c are real numbers, a linear equation in two variables? Give reason. -Maths 9th

Last Answer : Solution :-

Arvind and Vinod have some erasers. Arvind said to Vinod, if you will give me 10 erasers, I will have twice the erasers left with you. Represent this situation as a linear equation in two variables. -Maths 9th

Description : Arvind and Vinod have some erasers. Arvind said to Vinod, if you will give me 10 erasers, I will have twice the erasers left with you. Represent this situation as a linear equation in two variables. -Maths 9th

Last Answer : Solution :-

Classify the following polynomials as polynomials in one variable, two variables etc. -Maths 9th

Description : Classify the following polynomials as polynomials in one variable, two variables etc. -Maths 9th

Last Answer : (i) Polynomial x2+ x+ 1 is a one variable polynomial, because it contains only one variable i.e., x. (ii) Polynomial y3 - 5y is a one variable polynomial, because it contains only one variable i.e ... x2 - Zxy + y2 +1 is a two variables polynomial, because it contains two variables x and y.

Classify the following polynomials as polynomials in one variable, two variables etc. -Maths 9th

Description : Classify the following polynomials as polynomials in one variable, two variables etc. -Maths 9th

Last Answer : (i) Polynomial x2+ x+ 1 is a one variable polynomial, because it contains only one variable i.e., x. (ii) Polynomial y3 - 5y is a one variable polynomial, because it contains only one variable i.e ... x2 - Zxy + y2 +1 is a two variables polynomial, because it contains two variables x and y.

Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Description : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Last Answer : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) ... -5) lt 0` `(viii) |x-1|+|x-2|+|x-3| le 6`

Solve these following equations: (i) 3x + 3 = 15 (ii) 2y + 7 =19 -Maths 9th

Description : Solve these following equations: (i) 3x + 3 = 15 (ii) 2y + 7 =19 -Maths 9th

Last Answer : answer:

Write any two solutions of the linear equation 3x + 2y =9. -Maths 9th

Description : Write any two solutions of the linear equation 3x + 2y =9. -Maths 9th

Last Answer : Solution :-

Draw a graph of the equation x + Y = 5 & 3x - 2y =0 on the same graph paper. Find the coordinates of the point whose two lines intersect. -Maths 9th

Description : Draw a graph of the equation x + Y = 5 & 3x - 2y =0 on the same graph paper. Find the coordinates of the point whose two lines intersect. -Maths 9th

Last Answer : This answer was deleted by our moderators...

Draw a graph of the equation x+ y=5 & 3x -2y=0 in the same graph paper find the coordinates of the point whose two two lines intersect. -Maths 9th

Description : Draw a graph of the equation x+ y=5 & 3x -2y=0 in the same graph paper find the coordinates of the point whose two two lines intersect. -Maths 9th

Last Answer : From x + y = 5, If x = 0 0 + y = 5 y = 5 Therefore (0,5) If x = 1 1 + y = 5 y =5 - 1 y = 4 Therefore (1,4) Draw a graph for this And From 3x - 2y = 0 If x = 0 3 (0) - 2y = 0 0 - ... 2y = 0 -2y = -6 y = -6/-2 y = 3 Therefore (2,3) Draw a graph for these points And the point of intersection is (2,3)

Check whether the graph of the equation y = 3x + 5 passes through the origin or not. -Maths 9th

Description : Check whether the graph of the equation y = 3x + 5 passes through the origin or not. -Maths 9th

Last Answer : Solution :-

Find the coordinate where the linear equation 3x -4y = 11 meets at x-axis. -Maths 9th

Description : Find the coordinate where the linear equation 3x -4y = 11 meets at x-axis. -Maths 9th

Last Answer : hope it helps

Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Description : Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Last Answer : Solution :-

Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th

Description : Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th

Last Answer : hope it helps

The equation whose roots are twice the roots of the equation x^2 – 3x + 3 = 0 is -Maths 9th

Description : The equation whose roots are twice the roots of the equation x^2 – 3x + 3 = 0 is -Maths 9th

Last Answer : answer:

Find the equation of the straight line passing through the point (4, 5) and perpendicular to 3x – 2y + 5 = 0. -Maths 9th

Description : Find the equation of the straight line passing through the point (4, 5) and perpendicular to 3x – 2y + 5 = 0. -Maths 9th

Last Answer : There are two ways to prove it. 1st way: Area of triangle formed by the given points = 0 if they are collinear.∴ \(rac{1}{2}\) [\(x\)(2 - (y + 1) ) + 1((y + 1) - 1) + 0(1 - 2)] = 0⇒ \(rac{1}{2}\) [2\(x\) - \(x\)y - \( ... y - \(x\)y - 1 + \(x\) ⇒ x + y = \(x\)y ⇒ \(rac{1}{x}\) + \(rac{1}{y}\) = 1.

What is the equation of the line joining the origin with the point of intersection of the lines 4x + 3y = 12 and 3x + 4y = 12 ? -Maths 9th

Description : What is the equation of the line joining the origin with the point of intersection of the lines 4x + 3y = 12 and 3x + 4y = 12 ? -Maths 9th

Last Answer : (b) (5, 6)Let the foot of the perpendicular be M(x1, y1) Slope of line AB, i.e., y = -x + 11 = -1 Slope of line PM = \(rac{y_1-3}{x_1-2}\)Now, PM ⊥ AB⇒ \(\bigg(rac{y_1-3}{x_1-2}\bigg)\) x - ... get 2x1 = 10 ⇒ x1 = 5 Putting x1 in (ii), we get y1 = 6. ∴ Required foot of the perpendicular M is (5, 6).

What is the general form of linear equation in two variables ? -Maths 9th

Description : What is the general form of linear equation in two variables ? -Maths 9th

Last Answer : The general form of linear equation in two variables can be written as: ax+by+c=0

Any solution of the linear equation 2x + 0y + 9 = 0 in two variables is of the form -Maths 9th

Description : Any solution of the linear equation 2x + 0y + 9 = 0 in two variables is of the form -Maths 9th

Last Answer : (a) The given linear equation is 2x + 0y + 9 = 0 ⇒ 2x + 9 = 0 ⇒ 2x = -9 ⇒ x= - 9/2 and y can be any real number. Hence, (-9/2 , m) is the required form of solution of the given linear equation.

Any solution of the linear equation 2x + 0y + 9 = 0 in two variables is of the form -Maths 9th

Description : Any solution of the linear equation 2x + 0y + 9 = 0 in two variables is of the form -Maths 9th

Last Answer : (a) The given linear equation is 2x + 0y + 9 = 0 ⇒ 2x + 9 = 0 ⇒ 2x = -9 ⇒ x= - 9/2 and y can be any real number. Hence, (-9/2 , m) is the required form of solution of the given linear equation.

The weight of a man is four times the weight of a child. Write an equation in two variables for this situation. -Maths 9th

Description : The weight of a man is four times the weight of a child. Write an equation in two variables for this situation. -Maths 9th

Last Answer : Solution :-

Express the given statement in the form of a linear equation in two variables. The sum of the ordinate and abscissa of a point is 6. -Maths 9th

Description : Express the given statement in the form of a linear equation in two variables. The sum of the ordinate and abscissa of a point is 6. -Maths 9th

Last Answer : Solution :- x+y = 6

Express the given equation as linear equation in two variables in standard form: 3y = 2x. -Maths 9th

Description : Express the given equation as linear equation in two variables in standard form: 3y = 2x. -Maths 9th

Last Answer : Solution :- 2x - √3y + 0 = 0

Force applied on a body of mass 5 kg is directly proportional to the acceleration produced in the body. Represent this solution as a linear equation in two variables. -Maths 9th

Description : Force applied on a body of mass 5 kg is directly proportional to the acceleration produced in the body. Represent this solution as a linear equation in two variables. -Maths 9th

Last Answer : Solution :- Let the force be x and acceleration due to force be y.

If the length of a rectangle is decreased by 3 units and breadth increased by 4 unit, then the area will increase by 9 sq. units. Represent this situation as a linear equation in two variables. -Maths 9th

Description : If the length of a rectangle is decreased by 3 units and breadth increased by 4 unit, then the area will increase by 9 sq. units. Represent this situation as a linear equation in two variables. -Maths 9th

Last Answer : Solution :-

The cost of a toy horse is same as that of cost of 3 balls. Express this statement as a linear equation in two variables. Also draw its graph. -Maths 9th

Description : The cost of a toy horse is same as that of cost of 3 balls. Express this statement as a linear equation in two variables. Also draw its graph. -Maths 9th

Last Answer : Solution :-

Two batsman Rahul and Anil while playing a cricket match scored 120 runs. For this, write a linear equation in two variables and draw the graph. -Maths 9th

Description : Two batsman Rahul and Anil while playing a cricket match scored 120 runs. For this, write a linear equation in two variables and draw the graph. -Maths 9th

Last Answer : Solution :-

Let cost of a pen and a pencil be “x” and “y” respectively. A girl pays ₹16 for 2 pens and 3 pencils. Write the given data in the form of a linear equation in two variables. Also represent it graphically. -Maths 9th

Description : Let cost of a pen and a pencil be “x” and “y” respectively. A girl pays ₹16 for 2 pens and 3 pencils. Write the given data in the form of a linear equation in two variables. Also represent it graphically. -Maths 9th

Last Answer : Solution :-

The work done by a body on application of a constant force is the product of the constant force and distance travelled by the body in the direction of force. Express this in the form of a linear equation in two variables and draw its graph by taking the constant force as 3 units. -Maths 9th

Description : The work done by a body on application of a constant force is the product of the constant force and distance travelled by the body in the direction of force. Express this in the form of a linear equation in two variables and draw its graph by taking the constant force as 3 units. -Maths 9th

Last Answer : Solution :-

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Last Answer : (i) (x + 4)(x + 10): Using the identity (x + a)(x + b) = x2 + (a + b)x + ab, we have: (x + 4)(x + 10) = x2 + (4 + 10)x + (4 x 10) = x2 + 14x + 40 (ii) (x + 8)(x - 10): Here, a = 8 and b = ( ... have 64m3 - 343n3 = (4m)3 - (7n)3 = (4m - 7n)[(4m)2 + (4m)(7n) + (7n)2] = (4m - 7n)(16m2 + 28mn + 49n2)

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Last Answer : 1. How will you describe the position of a table lamp on your study table to another person ? To describe the position of a table lamp placed on the table, let us consider the table lamp as P and the table as a plane ... the point A(4, 3). (ii) A unique cross street as shown by the point B(3, 4).

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Last Answer : 1: Draw the graph of each of the following linear equations in two variables: (i) x + y = 4 (ii) x - y = 2 (iii) y = 3x (iv) 3 = 2x + y Solution: (i)x + y= 4 ⇒ y = 4 - x If ... graph paper and joining them, we get a straight line PQ. Thus, PQ is the required graph of the linear equation y = 5x + 3.

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Last Answer : 1. Give the geometric representations of y = 3 as an equation (i) in one variable (ii) in two variables (i) y = 3 [An equation in one variable] ∵ y = 3 is an equation in one variable, i.e. y only. ∴ It has ... equation in two variables] We can write 2x + 9 = 0 as 2x + 0y + 9 = 0 or 2x = -9 + 0y

On planet A , each alien has 3 eyes and on planet B , each alien has 4 eyes. A group of aliens from planets A and B landed on earth. They had 30 eyes in all. Assuming number of aliens from planets A and B respectively , express the situation in the form of linear equation in two variables. -Maths 9th

Description : On planet A , each alien has 3 eyes and on planet B , each alien has 4 eyes. A group of aliens from planets A and B landed on earth. They had 30 eyes in all. Assuming number of ... planets A and B respectively , express the situation in the form of linear equation in two variables. -Maths 9th

Last Answer : answer: