Two parallelograms are on equal bases and between the same parallels. -Maths 9th

Two parallelograms are on equal bases and between the same parallels. -Maths 9th
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Two Parallelograms on the equal based and between the same parallels are equal in area.
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Two parallelograms are on equal bases and between the same parallels. -Maths 9th

Description : Two parallelograms are on equal bases and between the same parallels. -Maths 9th

Last Answer : Two Parallelograms on the equal based and between the same parallels are equal in area.

Two parallelograms are on equal bases and between the same parallels. -Maths 9th

Description : Two parallelograms are on equal bases and between the same parallels. -Maths 9th

Last Answer : (b) We know that, parallelogram on the equal bases and between the same parallels are equal in area. So, ratio of their areas is 1 :1.

Two parallelograms are on equal bases and between the same parallels. -Maths 9th

Description : Two parallelograms are on equal bases and between the same parallels. -Maths 9th

Last Answer : (b) We know that, parallelogram on the equal bases and between the same parallels are equal in area. So, ratio of their areas is 1 :1.

Prove that parallelogram on equal bases and between the same parallels are equal in area. -Maths 9th

Description : Prove that parallelogram on equal bases and between the same parallels are equal in area. -Maths 9th

Last Answer : Suppose AL and PM are the altitudes corresponding to equal bases AB and PQ of ||gm ABCD and PQRS respectively . Since the ||gm are between the same parallels PB and SC. ∴ AL = PM Now, ar(||gm ABCD) = AB AL ar(|| ... PM But, AB = PQ [given] AL = PM [proved] ∴ ar(||gm ABCD) = ar(||gm PQRS)

Prove that parallelogram on equal bases and between the same parallels are equal in area. -Maths 9th

Description : Prove that parallelogram on equal bases and between the same parallels are equal in area. -Maths 9th

Last Answer : Suppose AL and PM are the altitudes corresponding to equal bases AB and PQ of ||gm ABCD and PQRS respectively . Since the ||gm are between the same parallels PB and SC. ∴ AL = PM Now, ar(||gm ABCD) = AB AL ar(|| ... PM But, AB = PQ [given] AL = PM [proved] ∴ ar(||gm ABCD) = ar(||gm PQRS)

In the given figure , two opposite angles of a parallelograms PQRS are (3x - 4)° and (56 - 3x)° . Find all the angles of given parallelogram . -Maths 9th

Description : In the given figure , two opposite angles of a parallelograms PQRS are (3x - 4)° and (56 - 3x)° . Find all the angles of given parallelogram . -Maths 9th

Last Answer : We know that opposite angles of a paralleloram are equal . ∴ ∠P = ∠R ⇒ 3x - 4 = 56 - 3x ⇒ 6x = 60 ⇒ x = 10 Thus, ∠P = ∠R = 3 10 - 4 = 26° Also, ∠P + ∠Q = 180° [ ... Hence, the four angles of the parallelogram PQRS are 26°, 154°,26° and 154°. We should care our earth to have good eco balance.

In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Description : In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Last Answer : Given, ABCD and AEFD are two parallelograms. To prove ar (APEA) = ar (AQFD) Proof In quadrilateral PQDA, AP || DQ [since, in parallelogram ABCD, AB || CD ] and PQ || AD [since, in parallelogram AEFD ... APFD) = ar (parallelogram AEFD) - ar (quadrilateral APFD) ⇒ ar (AQFD) = ar (APEA) Hence proved.

In the given figure , two opposite angles of a parallelograms PQRS are (3x - 4)° and (56 - 3x)° . Find all the angles of given parallelogram . -Maths 9th

Description : In the given figure , two opposite angles of a parallelograms PQRS are (3x - 4)° and (56 - 3x)° . Find all the angles of given parallelogram . -Maths 9th

Last Answer : We know that opposite angles of a paralleloram are equal . ∴ ∠P = ∠R ⇒ 3x - 4 = 56 - 3x ⇒ 6x = 60 ⇒ x = 10 Thus, ∠P = ∠R = 3 10 - 4 = 26° Also, ∠P + ∠Q = 180° [ ... Hence, the four angles of the parallelogram PQRS are 26°, 154°,26° and 154°. We should care our earth to have good eco balance.

In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Description : In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Last Answer : Given, ABCD and AEFD are two parallelograms. To prove ar (APEA) = ar (AQFD) Proof In quadrilateral PQDA, AP || DQ [since, in parallelogram ABCD, AB || CD ] and PQ || AD [since, in parallelogram AEFD ... APFD) = ar (parallelogram AEFD) - ar (quadrilateral APFD) ⇒ ar (AQFD) = ar (APEA) Hence proved.

In Fig.8.6, BDEF and FDCE are parallelograms.Can you say that BD = CD? -Maths 9th

Description : In Fig.8.6, BDEF and FDCE are parallelograms.Can you say that BD = CD? -Maths 9th

Last Answer : Solution :-

Area of Parallelograms and Triangles Class 9th Formula -Maths 9th

Description : Area of Parallelograms and Triangles Class 9th Formula -Maths 9th

Last Answer : An angle is formed by two rays originating from same point. The rays making an angle are called arms of the angle and the point is called vertex of the angle. Right angle : An angle whose measure ... parallel to each other. Lines which are perpendicular to a given line are parallel to each other.

NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.1 -Maths 9th

Last Answer : 1. Which of the following figures lie on the same base and between the same parallels. In such a case, write the common base and the two parallels. The figures (i), (iii), and (v) lie on the same base and between the same parallels.

NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.2 -Maths 9th

Last Answer : 1. In the figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD. We have AE ⊥ DC and AB = 16 cm ∵ AB = CD [opp. sides of parallelogram ABCD] ∴ ... sow wheat in (ΔPAQ) and pulses in [(ΔAPS) + (ΔQAR)] OR wheat in [(ΔAPS) + (ΔQAR)] and pulses in (ΔPAQ).

NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.3 -Maths 9th

Last Answer : 1. In the figure, E is any point on median AD of a DABC. Show that ar (ABE) = ar (ACE). We have a ΔABC such that AD is a median. ∴ ar (ΔABD) = ar (ΔADC) ...(1) [∵ A median divides ... from both sides, we get [ar (ΔABD) - ar (ΔAOB)] = [ar (ΔABC) - ar (ΔAOB)] ⇒ ar (ΔAOD) = ar (ΔBOC)

NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.4 -Maths 9th

Last Answer : 1. Parallelogram ABCD and rectangle ABEF are on the same base AB have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle. We have a parallelogram ABCD and rectangle ABEF such that ar ( ... (BCED) = ar (ABMN) + ar (ACFG) [from (5)

If m parallel lines in a plane are intersected by a family of n parallel lines, find the number of parallelograms formed? -Maths 9th

Description : If m parallel lines in a plane are intersected by a family of n parallel lines, find the number of parallelograms formed? -Maths 9th

Last Answer : answer:

Cbqs (case base study ) of chapter 9 Areas of Parallelograms and Triangles of maths class 9th -Maths 9th

Description : Cbqs (case base study ) of chapter 9 Areas of Parallelograms and Triangles of maths class 9th -Maths 9th

Last Answer : CBQs Ch- 13 Surface area and volume - Maths Class 9th 1.Answers: 1. 2. 3

In which of the following figures, you find two polygons on the same base and between the same parallels ? -Maths 9th

Description : In which of the following figures, you find two polygons on the same base and between the same parallels ? -Maths 9th

Last Answer : (d) In figures (a), (b) and (c) there are two polygons on the same base but they are not between the same parallels. In figure (d), there are two polygons (PQRA and BQRS) on the same base and between the same parallels .

In which of the following figures, you find two polygons on the same base and between the same parallels ? -Maths 9th

Description : In which of the following figures, you find two polygons on the same base and between the same parallels ? -Maths 9th

Last Answer : (d) In figures (a), (b) and (c) there are two polygons on the same base but they are not between the same parallels. In figure (d), there are two polygons (PQRA and BQRS) on the same base and between the same parallels .

If a triangle and a parallelogram are on same base and between same parallels, then find the ratio of the area of the triangle to the area of parallelogram. -Maths 9th

Description : If a triangle and a parallelogram are on same base and between same parallels, then find the ratio of the area of the triangle to the area of parallelogram. -Maths 9th

Last Answer : If a triangle and a parallelogram are on the same base and between the same parallels, the area of the triangle is equal to half of the parallelogram.

If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is -Maths 9th

Description : If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is -Maths 9th

Last Answer : (b) We know that, if a parallelogram and a triangle are on the same base and between the same parallels, then area of the triangle is half the area of the parallelogram.

If a triangle and a parallelogram are on same base and between same parallels, then find the ratio of the area of the triangle to the area of parallelogram. -Maths 9th

Description : If a triangle and a parallelogram are on same base and between same parallels, then find the ratio of the area of the triangle to the area of parallelogram. -Maths 9th

Last Answer : If a triangle and a parallelogram are on the same base and between the same parallels, the area of the triangle is equal to half of the parallelogram.

If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is -Maths 9th

Description : If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is -Maths 9th

Last Answer : (b) We know that, if a parallelogram and a triangle are on the same base and between the same parallels, then area of the triangle is half the area of the parallelogram.

If a triangle and a parallelogram are on same base and between the same parallels,then find the ratio of the area of the triangle to the area of parallelogram -Maths 9th

Description : If a triangle and a parallelogram are on same base and between the same parallels,then find the ratio of the area of the triangle to the area of parallelogram -Maths 9th

Last Answer : Solution :-

A right circular cylinder and a right circular cone have equal bases and equal volumes. But the lateral surface area of the right circular cone is -Maths 9th

Description : A right circular cylinder and a right circular cone have equal bases and equal volumes. But the lateral surface area of the right circular cone is -Maths 9th

Last Answer : answer:

A sphere and a cone have equal bases. If their heights are also equal, the ratio of their curved surface will be : -Maths 9th

Description : A sphere and a cone have equal bases. If their heights are also equal, the ratio of their curved surface will be : -Maths 9th

Last Answer : answer:

The length of the midline of a trapezoid equals 4 cm and the base angles are 40° and 50°. The length of the bases if the distance of their -Maths 9th

Description : The length of the midline of a trapezoid equals 4 cm and the base angles are 40° and 50°. The length of the bases if the distance of their -Maths 9th

Last Answer : answer:

1. Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centres. -Maths 9th

Description : 1. Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centres. -Maths 9th

Last Answer : To recall, a circle is a collection of points whose every point is equidistant from its centre. So, two circles can be congruent only when the distance of every point of both the circles are equal from the centre ... ) So, by SSS congruency, ΔAOB ΔCOD ∴ By CPCT we have, AOB = COD. (Hence proved).

A transversal intersects two lines in such a way that the two interior angle on the same side of transversal are equal.Will the two lines always be parallel? -Maths 9th

Description : A transversal intersects two lines in such a way that the two interior angle on the same side of transversal are equal.Will the two lines always be parallel? -Maths 9th

Last Answer : Solution :- The two lines will not be always parallel as the sum of the two equal angles will not always be 180°. Lines will be parallel when each of the equal angles is equal to 90°.

Two cans have the same height equal to 21 cm. One can is cylindrical, the diameter of whose base is 10 cm. -Maths 9th

Description : Two cans have the same height equal to 21 cm. One can is cylindrical, the diameter of whose base is 10 cm. -Maths 9th

Last Answer : (c) 450 cm3. Required difference in capacities = 227227 x (5)2 x 21~ (10)2 x 21 = (1650 ~ 2100) cm3 = 450 cm3

A sphere and a right circular cone of same radius have equal volumes. By what percentage does the height of the cone exceed its diameter ? -Maths 9th

Description : A sphere and a right circular cone of same radius have equal volumes. By what percentage does the height of the cone exceed its diameter ? -Maths 9th

Last Answer : answer:

If a rectangle and a parallelogram are equal in area and have the same base and are situated on the same side, and the ratio of the perimeter -Maths 9th

Description : If a rectangle and a parallelogram are equal in area and have the same base and are situated on the same side, and the ratio of the perimeter -Maths 9th

Last Answer : answer:

Do parallelograms have no congruent angles?

Description : Do parallelograms have no congruent angles?

Last Answer : Parallelograms normally have 2 congruent obtuse angles and 2 congruent acute angles that altogether add up to 360 degrees

All parallelograms are rectangles Always, Sometimes, or Never?

Description : All parallelograms are rectangles Always, Sometimes, or Never?

Last Answer : why

Which of these statements describe properties of parallelograms?

Description : Which of these statements describe properties of parallelograms?

Last Answer : Opposite sides are parallel, Consecutive angles are supplementary, Opposite angles are congruent, Opposite sides are congruent (APEX)

The operation represented by parallelograms. a) Input/Output b) Assignment c) Comparison d) Conditions

Description : The operation represented by parallelograms. a) Input/Output b) Assignment c) Comparison d) Conditions

Last Answer : Answer: a Explanation: The input/output operations are represented by parallelograms. They generally are used to display messages during input and output part of a program

Find the area of a triangle having perimeter 32cm. One side of its side is equal to 11cm and difference of the other two is 5cm. -Maths 9th

Description : Find the area of a triangle having perimeter 32cm. One side of its side is equal to 11cm and difference of the other two is 5cm. -Maths 9th

Last Answer : Solutions :- We have, Perimeter of triangle = 32 cm One of its side = 11 cm Let the second side be x And third side be x + 5 Perimeter of triangle = sum of three sides A/q => 11 + x + x + 5 ... 13 cm Now, By using heron's formula, Find the area of a triangle :- Answer : Area of triangle = 43.81 cm²

find two solution of 4 x + Y is equal to 2 -Maths 9th

Description : find two solution of 4 x + Y is equal to 2 -Maths 9th

Last Answer : When solving for y in this problem(4x+y=2) we need to get y by itself in the equation. To do this we need to move 4x over to the right side of the equation. To do this we subtract, 4x from ... we do to one side of the equation we have to do the same to the other side of the equation. So,..

An exterior angle of a triangle is 110° and the two interior opposite angles are equal find the interior opposite angels -Maths 9th

Description : An exterior angle of a triangle is 110° and the two interior opposite angles are equal find the interior opposite angels -Maths 9th

Last Answer : each interior opposite angles are 55

If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Description : If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Last Answer : Let AB and AC be two chords and AD be the diameter of the circle . Draw OL ⊥ AB and OM ⊥ AC . In ΔOLA and ΔOMA ∠ OLA = ∠ OMA = 90° OA = OA [common sides] ∠ OAL = ∠ OAM [given] . OLA ≅ OMA [by ASA congruency] OL =OM (by CPCT) Chords AM and AC are equidistant from O. ∴ AB = AC Hence proved.

State and prove-line joining the midpoint of any two sides of a triangle is parallel to throw side and is equal to 1/2 of it -Maths 9th

Description : State and prove-line joining the midpoint of any two sides of a triangle is parallel to throw side and is equal to 1/2 of it -Maths 9th

Last Answer : Here, In △△ ABC, D and E are the midpoints of sides AB and AC respectively. D and E are joined. Given: AD = DB and AE = EC. To Prove: DE ∥∥ BC and DE = 1212 BC. Construction: Extend line segment DE to ... we have DF ∥∥ BC and DF = BC DE ∥∥ BC and DE = 1212BC (DE = EF by construction) Hence proved.

The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Description : The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Last Answer : Given = A △ABC in which D and E are the mid-points of side AB and AC respectively. DE is joined . To Prove : DE || BC and DE = 1 / 2 BC. Const. : Produce the line segment DE to F , such that DE = ... of ||gm are equal and parallel] Also, DE = EF [by construction] Hence, DE || BC and DE = 1 / 2 BC

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Description : If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Last Answer : Let ABCD be quadrilateral with ab||cd Join be. In triangle abd and CBD, Angle abd=angle cdb(alternate angles) Anglecbd=angle adb(alternate angles) Bd=bd(common) Abd=~CBD by asa test Ad=BC by cpct Since ad ... c(from 1) Ad =bc(proved above) Triangle adc=~bcd by sas test Ac=bd by cpct Hence proved

If one angle of a triangle is equal to the sum of the other two angles, then the triangle is -Maths 9th

Description : If one angle of a triangle is equal to the sum of the other two angles, then the triangle is -Maths 9th

Last Answer : (d) Let the angles of a AABC be ∠A, ∠B and ∠C. Given, ∠A = ∠B+∠C …(i) InMBC, ∠A+ ∠B+ ∠C-180° [sum of all angles of a triangle is 180°]…(ii) From Eqs. (i) and (ii), ∠A+∠A = 180° ⇒ 2 ∠A = 180° ⇒ 180° /2 ∠A = 90° Hence, the triangle is a right triangle.

If two lines intersect prove that the vertically opposite angles are equal. -Maths 9th

Description : If two lines intersect prove that the vertically opposite angles are equal. -Maths 9th

Last Answer : Given Two lines AB and CD intersect at point O.

‘If two sides and an angle of one triangle are equal to two sides and an angle of another triangle , then the two triangles must be congruent’. -Maths 9th

Description : ‘If two sides and an angle of one triangle are equal to two sides and an angle of another triangle , then the two triangles must be congruent’. -Maths 9th

Last Answer : No, because in the congruent rule, the two sides and the included angle of one triangle are equal to the two sides and the included angle of the other triangle i.e., SAS rule.

ABCD is a quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD -Maths 9th

Description : ABCD is a quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD -Maths 9th

Last Answer : (d) Here, ABCD need not be any of rectangle, rhombus and parallelogram because if ABCD is a square, then its diagonal AC also divides it into two parts which are equal in area.

AB and AC are two equal chords of a circle. -Maths 9th

Description : AB and AC are two equal chords of a circle. -Maths 9th

Last Answer : Given AS and AC are two equal chords whose centre is O. To prove Centre O lies on the bisector of ∠BAC. Construction Join SC, draw bisector AD of ∠BAC. Proof In ΔSAM and ΔCAM, AS = AC [given] ∠BAM = ∠CAM [given]

If two equal chords of a circle intersect, prove that the parts of one chord are separately equal to the parts of the other chord. -Maths 9th

Description : If two equal chords of a circle intersect, prove that the parts of one chord are separately equal to the parts of the other chord. -Maths 9th

Last Answer : Explanation of this question